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An incoming freshman took her college's placement exams in French and mathematics. In French, she scored 82 and in math \(86 .\) The overall results on the French exam had a mean of 72 and a standard deviation of \(8,\) while the mean math score was 68 with a standard deviation of \(12 .\) On which exam did she do better compared with the other freshmen?

Short Answer

Expert verified
She did better on the Math exam compared to her peers.

Step by step solution

01

Calculate the Z-Score for the French Exam

The Z-score is calculated using the formula \( Z = \frac{(X - \mu)}{\sigma} \) where \( X \) is the student's score, \( \mu \) is the mean, and \( \sigma \) is the standard deviation. For the French exam, \( X = 82 \), \( \mu = 72 \), and \( \sigma = 8 \). Substitute to find the Z-score: \[ Z_{\text{French}} = \frac{(82 - 72)}{8} = \frac{10}{8} = 1.25 \]
02

Calculate the Z-Score for the Math Exam

Again, use the Z-score formula \( Z = \frac{(X - \mu)}{\sigma} \). For the math exam, \( X = 86 \), \( \mu = 68 \), and \( \sigma = 12 \).Substitute to find the Z-score: \[ Z_{\text{Math}} = \frac{(86 - 68)}{12} = \frac{18}{12} = 1.5 \]
03

Compare the Z-Scores

The Z-score indicates how many standard deviations a student's score is from the mean. A higher Z-score means a better relative performance. The Z-score for the French exam is 1.25 while for the Math exam is 1.5. Since 1.5 is greater than 1.25, the student performed better on the Math exam compared to others.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
Standard deviation is a key concept in statistics, often used to describe the variability or spread of a set of numbers. In other words, it tells us how much the individual numbers in a dataset differ from the mean or average of that set.
Imagine you took a class test and everyone scored very similar marks. Here, the standard deviation would be low because the scores are close to each other and the mean. Conversely, if the scores were all over the place, the standard deviation would be high.
It's calculated using the formula: \[ \sigma = \sqrt{\frac{1}{N}\sum_{i=1}^{N}(X_i - \mu)^2} \]Where
  • \( \sigma \) is the standard deviation,
  • \( N \) is the number of values,
  • \( X_i \) is each value,
  • \( \mu \) is the mean of the values.
Whenever you are interpreting data like test results, knowing the standard deviation can help you understand how unusual or usual a particular score like your test result is within a set.Recognizing how spread out or tightly clustered results are aids in forming a picture of the overall performance.
Mean Score
The mean score is what most of us refer to as the "average." It's a measure that sums up what's typical about a set of scores or data points. To find the mean, you add up all the numbers in a dataset and then divide by the count of numbers.
Let's say you have a test with scores of 70, 75, and 85. To find the mean, you calculate:\[ \mu = \frac{(70 + 75 + 85)}{3} = 76.67 \]Here, the mean score of 76.67 gives us a central value that indicates the overall trend in the data.
If scores increase significantly, the mean will adjust upward, reflecting the trend. Conversely, if scores drop, the mean will decrease, indicating some trouble that might need addressing.Mean scores are essential if you want to compare individual scores to get a sense of whether they are above or below average. They are especially significant in cases like comparing test performances with an entire class or group.
Placement Exams
Placement exams are tests used by educational institutions to determine a student's skill level—placing them appropriately in levels or courses that suit their capabilities. They often cover subjects like English, Math, and Science.
The tests are designed to ensure students don't take classes too easy or too challenging for them. For example, in a college setting, they might face tests in subjects like French and Math, as seen in our original problem. Upon taking these placement exams, the scores are compared against predefined benchmarks or the average scores (and their standard deviations).
  • These benchmarks help schools decide the best course of action for each student.
  • Higher-than-average scores suggest readiness for higher-level classes.
  • Scores close to or below the average might suggest a regular or even remedial class.
Placement exams, therefore, play a crucial role in aligning students' educational pathways with their current skills, ensuring the curriculum is tailored to their development needs while facilitating optimal learning.

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Most popular questions from this chapter

Anna, a language major, took final exams in both French and Spanish and scored 83 on each. Her roommate Megan, also taking both courses, scored 77 on the French exam and 95 on the Spanish exam. Overall, student scores on the French exam had a mean of 81 and a standard deviation of \(5,\) and the Spanish scores had a mean of 74 and a standard deviation of \(15 .\) a) To qualify for language honors, a major must maintain at least an 85 average for all language courses taken. So far, which student qualifies? b) Which student's overall performance was better?

A high school senior uses the Internet to get information on February temperatures in the town where he'll be going to college. He finds a website with some statistics, but they are given in degrees Celsius. The conversion formula is \(^{\circ} \mathrm{F}=9 / 5^{\circ} \mathrm{C}+32 .\) Determine the Fahrenheit equivalents for the summary information below. Maximum temperature \(=11^{\circ} \mathrm{C}\) Range \(=33^{\circ}\) Mean \(=1^{\circ} \quad\) Standard deviation \(=7^{\circ}\) Median \(=2^{\circ} \quad\) IQR \(=16^{\circ}\)

A company that manufactures rivets believes the shear strength (in pounds) is modeled by \(N(800,50)\) a) Draw and label the Normal model. b) Would it be safe to use these rivets in a situation requiring a shear strength of 750 pounds? Explain. c) About what percent of these rivets would you expect to fall below 900 pounds? d) Rivets are used in a variety of applications with varying shear strength requirements. What is the maximum shear strength for which you would feel comfortable approving this company's rivets? Explain your reasoning.

For the car speed data of Exercise 18 recall that the mean speed recorded was \(23.84 \mathrm{mph}\) with a standard deviation of \(3.56 \mathrm{mph}\). To see how many cars are speeding, John subtracts \(20 \mathrm{mph}\) from all speeds. a) What is the mean speed now? What is the new standard deviation? b) His friend in Berlin wants to study the speeds, so John converts all the original miles-per-hour readings to kilometers per hour by multiplying all speeds by 1.609 (km per mile). What is the mean now? What is the new standard deviation?

In the Normal model \(N(100,16),\) what cutoff value bounds a) the highest \(5 \%\) of all IQs? b) the lowest \(30 \%\) of the IQs? c) the middle \(80 \%\) of the IQs?

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