/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 \(t\) -models, part II Using the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

\(t\) -models, part II Using the \(t\) tables, software, or a calculator, estimate a) the critical value of \(t\) for a \(95 \%\) confidence interval with df \(=7\) b) the critical value of \(t\) for a \(99 \%\) confidence interval with \(\mathrm{df}=102\) c) the P-value for \(t \leq 2.19\) with 41 degrees of freedom. d) the P-value for \(|t|>2.33\) with 12 degrees of freedom.

Short Answer

Expert verified
a) 2.364, b) 2.626, c) 0.015, d) 0.04

Step by step solution

01

Estimate Critical Value for 95% Confidence Interval, df=7

To find the critical value of t for a 95% confidence interval with degrees of freedom (df) = 7, we can use a t-table or suitable software. For 95% confidence, we look for the value that leaves 2.5% in each tail of the t-distribution (total 5%). From the t-table, the critical value is nearly 2.364.
02

Estimate Critical Value for 99% Confidence Interval, df=102

For a 99% confidence interval with df = 102, we need the t value that leaves 0.5% in each tail (total 1%). Using a t-table or software, we find that the critical value is approximately 2.626.
03

Find P-value for t ≤ 2.19, df=41

To calculate the P-value for t ≤ 2.19 with 41 degrees of freedom, we refer to the cumulative probability in the t-distribution table or software. The cumulative probability is approximately 0.985, hence the P-value is the complement, about 1 - 0.985 = 0.015.
04

P-value for |t| > 2.33, df=12

For a two-tailed test with |t| > 2.33 and 12 degrees of freedom, find the tail area for t > 2.33 and multiply it by 2 (since it's a two-tailed test). Using a t-table or software, we find the upper tail probability is approximately 0.02. Therefore, the P-value is 0.02 * 2 = 0.04.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Critical Value
Understanding the critical value in a t-distribution is essential. It acts as a threshold to determine whether a test statistic lies in the rejection region of a hypothesis test. For instance, when constructing a confidence interval with a 95% probability, we ensure that our estimate falls within a reliable range. This range excludes extreme values, which we identify using the critical value. In the given exercise, for a 95% confidence interval with degrees of freedom (df) = 7, the critical t value is approximately 2.364. Similarly, for a 99% confidence interval with df = 102, the critical t value is about 2.626. You can determine these values using a t-table or statistical software. Critical values vary based on the confidence level and the degrees of freedom.
  • Higher confidence levels generally result in larger critical values.
  • The degrees of freedom factor is vital as it adjusts the shape of the t-distribution, which in turn, affects the values.
Confidence Interval
A confidence interval provides a range of values that likely includes the true population parameter. It essentially tells us how uncertain we are about our estimate. The width of this interval is influenced by the critical value and the sample size. With a high confidence level like 95% or 99%, we're saying there's a 'confidence' that the true mean lies within this range.
  • For a 95% confidence interval, the boundaries are usually narrower, giving a more precise estimate.
  • A 99% confidence interval is broader, reflecting increased certainty by allowing more room for potential variation within the data.
These intervals support decision-making by presenting an estimate with known precision and reliability.
Degrees of Freedom
Degrees of freedom (df) in statistical terms play a crucial role, especially in the context of t-distribution. They are determined by the number of independent values that can fluctuate in an analysis without breaking any constraints. For example, if you have a sample size of n, the degrees of freedom are typically n-1.
  • In t-distributions, the shape changes with different df values. Lower df values lead to wider and more variable distributions.
  • Higher df typically result in a distribution that closely resembles a normal distribution, which is more stable and peaked.
Degrees of freedom are not just theoretical numbers; they directly influence the accuracy and trustworthiness of statistical conclusions and confidence intervals.
P-value
The P-value measures the strength of evidence against a null hypothesis. A smaller P-value indicates stronger evidence in favor of the alternative hypothesis. In our exercise, we looked at different scenarios where the P-value varied based on different t-scores and degrees of freedom.
  • For instance, for t ≤ 2.19 and df = 41, the P-value was around 0.015, suggesting that such an occurrence is relatively rare if the null hypothesis is true.
  • Meanwhile, for |t| > 2.33 with df = 12, the resulting P-value was approximately 0.04. Since this was a two-tailed test, the doubly small value suggests convincing evidence against the null hypothesis.
P-values are essential for hypothesis testing, guiding whether to reject or fail to reject a null hypothesis based on the chosen significance level.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Popcorn Yvon Hopps ran an experiment to test optimum power and time settings for microwave popcorn. His goal was to find a combination of power and time that would deliver high-quality popcorn with less than \(10 \%\) of the kernels left unpopped, on average. After experimenting with several bags, he determined that power 9 at 4 minutes was the best combination. a) He concluded that this popping method achieved the \(10 \%\) goal. If it really does not work that well, what kind of error did Hopps make? b) To be sure that the method was successful, he popped 8 more bags of popcorn (selected at random) at this setting. All were of high quality, with the following percentages of uncooked popcorn: 7,13.2,10,6,7.8 \(2.8,2.2,5.2 .\) Does this provide evidence that he met his goal of an average of no more than \(10 \%\) uncooked kernels? Explain.

Speed of light In 1882 Michelson measured the speed of light (usually denoted \(c\) as in Einstein's famous equation \(\left.E=m c^{2}\right) .\) His values are in \(\mathrm{km} / \mathrm{sec}\) and have 299,000 subtracted from them. He reported the results of 23 trials with a mean of 756.22 and a standard deviation of 107.12 a) Find a \(95 \%\) confidence interval for the true speed of light from these statistics. b) State in words what this interval means. Keep in mind that the speed of light is a physical constant that, as far as we know, has a value that is true throughout the universe. c) What assumptions must you make in order to use your method?

Parking Hoping to lure more shoppers downtown, a city builds a new public parking garage in the central business district. The city plans to pay for the structure through parking fees. During a two-month period (44 weekdays), daily fees collected averaged \(\$ 126,\) with a standard deviation of \(\$ 15\) a) What assumptions must you make in order to use these statistics for inference? b) Write a \(90 \%\) confidence interval for the mean daily income this parking garage will gencrate. c) Interpret this confidence interval in context. d) Explain what "90\% confidence" means in this context. e) The consultant who advised the city on this project predicted that parking revenues would average \(\$ 130\) per day. Based on your confidence interval, do you think the consultant was correct? Why?

Pizza A researcher tests whether the mean cholesterol Ievel among those who eat frozen pizza exceeds the value considered to indicate a health risk. She gets a P-value of \(0.07 .\) Explain in this context what the "7 \(\%\) " represents.

Catheters During an angiogram, heart problems can be examined via a small tube (a catheter) threaded into the heart from a vein in the patient's leg. It's important that the company that manufactures the catheter maintain a diameter of \(2.00 \mathrm{mm}\). (The standard deviation is quite small.) Each day, quality control personnel make several measurements to test \(\mathrm{H}_{0}: \mu=2.00\) against \(\mathrm{H}_{\mathrm{A}}: \mu \neq 2.00\) at a significance level of \(\alpha=0.05 .\) If they discover a problem, they will stop the manufacturing process until it is corrected. a) Is this a one-sided or two-sided test? In the context of the problem, why do you think this is important? b) Explain in this context what happens if the quality control people commit a Type I error. c) Explain in this context what happens if the quality control people commit a Type II error.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.