/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 \(.\) Customer center operator R... [FREE SOLUTION] | 91Ó°ÊÓ

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\(.\) Customer center operator Raaj works at the customer service call center of a major credit card bank. Cardholders call for a variety of reasons, but regardless of their reason for calling, if they hold a platinum card, Raaj is instructed to offer them a double-miles promotion. About \(10 \%\) of all cardholders hold platinum cards, and about \(50 \%\) of those will take the double-miles promotion. On average, how many calls will Raaj have to take before finding the first cardholder to take the double-miles promotion?

Short Answer

Expert verified
Raaj will need, on average, 20 calls.

Step by step solution

01

Understand the requirements

The goal is to find the average number of calls Raaj needs to make to have the first customer accept the promotion. This problem can be modeled as a geometric distribution, where we seek the expected number of trials (calls) until success (acceptance of the promotion).
02

Determine the success probability

First, identify the probability of a single call resulting in a successful promotion acceptance. A success occurs if a call connects with a platinum cardholder, which happens 10% of the time (0.10 probability), and then they accept the offer, which happens 50% of the time (0.50 probability). Thus, the probability, \(p\), of success in any single call is \( p = 0.10 \times 0.50 = 0.05 \).
03

Calculate expected number of calls

In a geometric distribution, the expected number of calls (trials) needed before a success is given by \( \frac{1}{p} \), where \(p\) is the probability of success on each call. Substituting the probability calculated in Step 2, we have \( \frac{1}{0.05} = 20 \).
04

Conclusion

Raaj will have to make, on average, 20 calls to find the first cardholder who takes the double miles promotion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability in Geometric Distribution
Probability is a key concept in statistics and mathematics that helps us understand how likely it is for an event to occur. In this context, we are looking at a geometric distribution, where the focus is on the probability of the first success in a sequence of trials. To break it down in simpler terms, probability is a way of quantifying the chance of a specific outcome happening.
The problem involving Raaj at the call center requires finding the probability of a successful call. A successful call means Raaj reaches a platinum cardholder and they accept the double-miles promotion.
  • The probability of reaching a platinum cardholder is 10%, or 0.10 in probability terms.
  • If Raaj does reach a platinum cardholder, there’s then a 50% chance, or 0.50 probability, that they accept the offer.
  • These probabilities are independent events, so to find the overall probability of a call being successful, we multiply them: 0.10 (probability of platinum cardholder) * 0.50 (probability they accept) = 0.05.
Therefore, the probability that any given call is successful is 0.05, or 5%.
Expected Value in Geometric Distribution
The expected value, often considered as the average in a probabilistic process, gives us a mathematical expectation of outcomes. In geometric distributions, it's specifically about how many trials we expect to see before achieving our first "success." For Raaj, it represents the average number of customer calls needed before one customer takes the promotion.
In general, the formula for finding the expected number of trials in a geometric distribution is \( \frac{1}{p} \), where \( p \) is the probability of success on any single trial. This formula provides an easy calculation for average predictions, offering a deep insight without much complexity for students.
  • In Raaj's case, we calculated that the probability \( p \) is 0.05.
  • Applying the formula for expected value, it becomes \( \frac{1}{0.05} = 20 \).
Thus, Raaj can expect to make, on average, 20 calls before he successfully convinces a platinum cardholder to accept the promotion. This informs us well about potential efforts and helps in planning for resources or staffing at the call center.
Customer Service Call Center Context
Customer service call centers are essential touchpoints for businesses, enabling direct interactions with customers. For Raaj, a customer service operator at a credit card call center, facilitating a smooth and fruitful interaction is crucial. These centers typically handle a wide range of issues and inquiries from cardholders.
Understanding the customer landscape is vital for operators like Raaj. In this scenario, he needs to identify potential platinum cardholders and offer them a promotion. The randomness of receiving calls from different types of customers introduces elements of probability into his daily work environment.
  • Call centers operate on probabilities because they cannot predict who will call next.
  • Operators need to be prepared to offer certain services based on the caller's eligibility, like the platinum cardholder promotion.
  • Expected value calculations, like the one Raaj uses, assist in managing workload, ensuring operators like Raaj are not overwhelmed.
By understanding these elements, call centers can optimize their operation. It ensures that operators are informed about the likelihood of outcomes, improving service quality and customer satisfaction. For Raaj, knowing he may need to make around 20 calls to find a successful promotion acceptance allows better time management and performance expectation.

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