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A citrus farmer has observed the following distribution for the number of oranges per tree. How many oranges does he expect on average? $$\begin{array}{l|c|c|c|c}\text { Oranges } & 25 & 30 & 35 & 40 \\\\\hline \text { Probability } & 0.10 & 0.40 & 0.30 & 0.20\end{array}$$

Short Answer

Expert verified
The farmer expects 33 oranges per tree on average.

Step by step solution

01

Understand the Problem

The problem requires finding the expected number of oranges per tree, given a probability distribution for different scenarios.
02

Recall the Formula for Expectation

The expected value (or expectation) of a random variable is calculated by multiplying each possible outcome by its probability and summing all these products. Mathematically, it is given by \(E(X) = \sum [x_i \cdot P(x_i)]\), where \(x_i\) is the number of oranges, and \(P(x_i)\) is the probability of \(x_i\).
03

Calculate Each Product

Compute the product of each number of oranges with its corresponding probability: - For 25: \(25 \times 0.10 = 2.5\) - For 30: \(30 \times 0.40 = 12\) - For 35: \(35 \times 0.30 = 10.5\) - For 40: \(40 \times 0.20 = 8\)
04

Sum the Results

Add up all the products obtained in Step 3 to find the expected number of oranges: \(2.5 + 12 + 10.5 + 8 = 33\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Distribution
A probability distribution is a fundamental concept in statistics and probability theory. It provides a mathematical description of the likelihood of various outcomes. Imagine you have a set of all the possible outputs of a random experiment, like rolling a die or counting oranges on a tree.
For each outcome, there is an associated probability, which tells you how likely that outcome is to occur. A probability distribution must satisfy two main conditions:
  • The probability of each outcome must be between 0 and 1.
  • The sum of the probabilities for all possible outcomes must equal 1.
In our exercise, the number of oranges per tree is described by the probability distribution given in the table. This distribution helps us understand and predict how many oranges are likely to appear on any given tree.
Random Variable
Random variables are crucial in understanding probability distributions. A random variable is a numerical representation of the outcomes of a random phenomenon. It assigns numbers to every possible outcome.
For example, consider a tree with oranges. The number of oranges can be considered as a random variable. What makes it random? The fact that we don’t always know beforehand how many oranges each tree will have.
In our problem, the number of oranges per tree is the random variable. We denote it as typically by a letter, like X, to keep our calculations and descriptions simple.
This is why we use terms like \(x_i\) to indicate specific values that our random variable can take. Being clear on what a random variable is helps to accurately calculate the expected value, which is the goal of our exercise.
Outcomes
In the context of probability and random variables, outcomes are the possible results we can observe. Outcomes are essential for constructing a probability distribution.
Every outcome in a distribution has a probability attached to it, indicating the chance of it happening. Recognizing and counting these outcomes in advance is vital. It allows us to examine and prepare for what might come next in a probability experiment.
In the citrus farmer's problem, the outcomes are the number of oranges per tree, specifically 25, 30, 35, or 40. Understanding these outcomes helps in visualizing what we're tracking when we use a random variable to count oranges. Thus, when we calculate probabilities and expectations, we reorder these outcomes to observe any patterns or averages that appear.
Mathematical Expectation
Mathematical expectation, often referred to as expected value, is the average value that a random variable can take. It is a way of summarizing all possible outcomes and their probabilities into one single number. In other words, it gives us the long-run average if the random event (like the number of oranges on a tree) were repeated many times.
The expected value is calculated by summing up the products of each outcome with its respective probability. This is expressed as \(E(X) = \sum [x_i \cdot P(x_i)]\). Here, \(x_i\) represents each outcome, and \(P(x_i)\) is the probability of that outcome occurring.
By calculating the expected value of the number of oranges per tree in our exercise, we determine that, on average, each tree yields 33 oranges. This result reflects the mathematical expectation of the distribution we have for oranges per tree. It's a powerful way to anticipate future outcomes based on known probabilities.

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Most popular questions from this chapter

Organizers of a televised fundraiser know from past experience that most people donate small amounts \((\$ 10-\$ 25),\) some donate larger amounts \((\$ 50-\) \(\$ 100\) ), and a few people make very generous donations of \(\$ 250, \$ 500,\) or more. Historically, pledges average about \(\$ 32\) with a standard deviation of \(\$ 54\) a) If 120 people call in pledges, what are the mean and standard deviation of the total amount raised? b) What assumption did you make in answering this question?

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