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In a litter of seven kittens, three are female. You pick two kittens at random. a) Create a probability model for the number of male kittens you get. b) What's the expected number of males? c) What's the standard deviation?

Short Answer

Expert verified
The expected number of male kittens is \(\frac{8}{7}\), with a standard deviation of \(\frac{2}{7}\).

Step by step solution

01

Understand the Situation

We have a litter of 7 kittens where 3 are female and 4 are male. We need to determine the probability of selecting a certain number of male kittens when randomly choosing 2 kittens.
02

Define the Random Variable

Let the random variable \( X \) represent the number of male kittens we select. \( X \) can take values 0, 1, or 2, as it is possible to choose none, one, or both kittens as male.
03

Compute Probability of 0 Males

The probability of choosing 0 males means both kittens are female. This is calculated using combinations: \( P(X = 0) = \frac{\binom{3}{2}}{\binom{7}{2}} = \frac{3}{21} = \frac{1}{7} \).
04

Compute Probability of 1 Male

Choosing 1 male and 1 female can happen in two ways: selecting a male first and then a female or vice versa. \( P(X = 1) = \frac{\binom{4}{1} \cdot \binom{3}{1}}{\binom{7}{2}} = \frac{12}{21} = \frac{4}{7} \).
05

Compute Probability of 2 Males

The probability of choosing 2 males means both kittens are male. \( P(X = 2) = \frac{\binom{4}{2}}{\binom{7}{2}} = \frac{6}{21} = \frac{2}{7} \).
06

Verify Probability Model

Ensure probabilities sum to 1: \( \frac{1}{7} + \frac{4}{7} + \frac{2}{7} = 1 \). Thus, the model is correct.
07

Calculate Expected Number of Males

The expected value (mean) is given by \( E(X) = \sum (x \cdot P(X = x)) = 0 \cdot \frac{1}{7} + 1 \cdot \frac{4}{7} + 2 \cdot \frac{2}{7} = \frac{8}{7} \).
08

Calculate Variance

Variance is computed as \( Var(X) = E(X^2) - [E(X)]^2 \). Find \( E(X^2) = 0^2 \cdot \frac{1}{7} + 1^2 \cdot \frac{4}{7} + 2^2 \cdot \frac{2}{7} = \frac{12}{7} \). Then \( Var(X) = \frac{12}{7} - \left(\frac{8}{7}\right)^2 = \frac{4}{49} \).
09

Calculate Standard Deviation

The standard deviation is the square root of the variance: \( \sigma = \sqrt{\frac{4}{49}} = \frac{2}{7} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variables
A random variable is a mathematical way to describe a phenomenon that can take on different values based on chance. In the context of the exercise about kittens, the random variable \( X \) denotes the number of male kittens picked. - **Discrete Random Variables**: \( X \) can take on discrete values 0, 1, or 2, indicating the possible scenarios when selecting 2 kittens at random. - **Probability Distribution**: Each value of \( X \) has a probability associated with it, which reflects the likelihood of that scenario occurring. The sum of probabilities for all possible values of \( X \) equals 1. To model this situation, we calculate the probability of choosing 0, 1, or 2 male kittens by considering the various combinations that could lead to each outcome.
Expected Value
The expected value (or mean) of a random variable provides a measure of its central tendency, or "average" outcome over many trials. For the random variable \( X \) representing male kittens, it is calculated as follows: - **Formula**: \( E(X) = \sum (x \cdot P(X = x)) \) - **Calculation**: Here, \( E(X) = 0 \cdot \frac{1}{7} + 1 \cdot \frac{4}{7} + 2 \cdot \frac{2}{7} = \frac{8}{7} \). This expected value tells us that, on average, you can expect to pick about 1.14 male kittens when randomly selecting two from the litter. Although not a whole number, it reflects the balance of probabilities across many repeated selections.
Combinatorics
Combinatorics is the branch of mathematics concerning the counting, arrangement, and combination of objects. It's essential for calculating probabilities in scenarios like the kitten selection problem because it allows us to determine the number of favorable outcomes. - **Combination Formula**: Used when the order does not matter, \( \binom{n}{k} \), calculates the number of ways to choose \( k \) items from \( n \) items. - **Application**: In our example, to find the probability of selecting 0 males, we used \( \binom{3}{2} \), representing choosing 2 females from 3, and \( \binom{7}{2} \), representing choosing any 2 kittens from 7. Combinatorial techniques like these provide a foundation for determining probabilities in more complex probability models.
Standard Deviation
Standard deviation is a measure of dispersion that indicates how spread out the values of a random variable are from the mean. In this kitten example, it helps us understand the variability in the number of male kittens we might expect when picking two at random. - **Variance and Standard Deviation**: First, compute the variance \( Var(X) \) using \( Var(X) = E(X^2) - [E(X)]^2 \). For our problem, this is \( Var(X) = \frac{12}{7} - \left(\frac{8}{7}\right)^2 = \frac{4}{49} \). - **Standard Deviation Formula**: The standard deviation \( \sigma \) is the square root of the variance, \( \sigma = \sqrt{Var(X)} \). Calculating the standard deviation as \( \frac{2}{7} \), we find the values of \( X \) are clustered closely around the expected value, reflecting low variability in potential outcomes.

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Most popular questions from this chapter

An employer pays a mean salary for a 5 -day workweek of \(\$ 1250\) with a standard deviation of \(\$ 129\) On the weekends, his salary expenses have a mean of \$450 with a standard deviation of \(\$ 57 .\) What is the mean and standard deviation of his total weekly salaries?

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Mary is deciding whether to book the cheaper flight home from college after her final exams, but she's unsure when her last exam will be. She thinks there is only a \(20 \%\) chance that the exam will be scheduled after the last day she can get a seat on the cheaper flight. If it is and she has to cancel the flight, she will lose \(\$ 150 .\) If she can take the cheaper flight, she will save \(\$ 100\) a) If she books the cheaper flight, what can she expect to gain, on average? b) What is the standard deviation?

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