/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Facebook reports that \(70 \%\) ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Facebook reports that \(70 \%\) of its users are from outside the United States and that \(50 \%\) of its users log on to Facebook every day. Suppose that \(20 \%\) of its users are U.S. users who log on every day. Make a probability table.

Short Answer

Expert verified
A probability table shows how users are distributed by geographical location and daily login status.

Step by step solution

01

Understand the problem

To solve the problem, we need to construct a probability table with the given probabilities: 1) 70% of users are international, 2) 50% log on daily, 3) 20% are U.S. users who log on daily.
02

Define the events

Let A be the event that a user is from the U.S., and B be the event that a user logs on daily. Then, P(A') = 0.70 (international users), P(B) = 0.50 (log on daily), and P(A ∩ B) = 0.20 (U.S. users who log on daily).
03

Find probabilities using given data

The probability of being a U.S. user is P(A) = 1 - P(A') = 1 - 0.70 = 0.30. Thus, 30% of the users are from the U.S.
04

Calculate P(B|A) and P(B|A')

P(B|A) is the probability that a U.S. user logs on daily: P(B|A) = P(A ∩ B) / P(A) = 0.20 / 0.30 = 0.67. For international users, to find P(B|A'), use total probability: P(B) = P(A)P(B|A) + P(A')P(B|A') and solve for P(B|A').
05

Solve for P(B|A')

Substitute known values into the total probability equation: 0.50 = 0.30(0.67) + 0.70P(B|A'). Solve for P(B|A'): 0.50 = 0.201 + 0.70P(B|A') Thus, 0.70P(B|A') = 0.299 -> P(B|A') = 0.43.
06

Complete the probability table

Use the calculated probabilities to fill in all potential outcomes: - U.S. users who log on: P(A ∩ B) = 0.20 - International users who log on: P(A' ∩ B) = P(A')P(B|A') = 0.70 * 0.43 = 0.301 - U.S. users who don't log on: P(A ∩ B') = P(A) - P(A ∩ B) = 0.30 - 0.20 = 0.10 - International users who don't log on: P(A' ∩ B') = P(A') - P(A' ∩ B) = 0.70 - 0.301 = 0.399
07

Create the probability table

| | Log On (B) | Not Log On (B') | Total | |:-----------:|:----------:|:---------------:|:------:| | U.S. (A) | 0.20 | 0.10 | 0.30 | |Int'l (A') | 0.301 | 0.399 | 0.70 | | Total | 0.50 | 0.50 | 1.00 |

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability is a way to measure the likelihood of an event occurring, given that another event has already taken place. It's like asking, "If I know one thing, how does that change my expectations about another thing?" In our exercise, we look at the probability that a user logs on daily given their nationality, either U.S. or international.

For example, we calculated the probability that a U.S. user logs on daily using the formula for conditional probability:
  • \(P(B|A)\) = \(\frac{P(A \cap B)}{P(A)}\)
Here, \(B\) is the event that a user logs on daily, and \(A\) is the event that a user is from the U.S. The result was \(0.67\), meaning if the user is from the U.S., there's a 67% chance they log on daily. Understanding conditional probability allows us to see how the probability changes with additional information.
Joint Probability
Joint probability refers to the probability of two events happening at the same time. In this exercise, a practical example is the likelihood of a user being both from the U.S. and logging on every day.

Joint probability is calculated by multiplying the probability of one event by the conditional probability of the second event given the first:
  • \(P(A \cap B) = P(A) \cdot P(B|A)\)
This is seen in the problem where \(P(A \cap B)\) equaled 0.20, representing that 20% of users are both from the U.S. and log on daily. Joint probabilities give a broader picture of how frequently combinations of events occur together in a data set.
Probability Distribution
A probability distribution is a mathematical function that provides the probabilities of occurrence of different possible outcomes in an experiment. In simple terms, it helps us understand how the probabilities are spread across different outcomes.

In our exercise, we created a probability distribution table showing separate probabilities for U.S. and International users, both logging on and not logging on daily. Each cell in the table represents the probability of a combination of these events:
  • U.S. users logging on: 0.20
  • U.S. users not logging on: 0.10
  • International users logging on: 0.301
  • International users not logging on: 0.399
This table is a practical representation of the probability distribution, helping visualize all possible outcomes and their probabilities.
Statistics Education
Statistics education involves learning about the collection, analysis, interpretation, and presentation of data. Understanding statistics is crucial in a data-driven world as it enables us to make informed decisions based on data.

In our exercise, by working through conditional and joint probabilities and developing a probability distribution, we apply statistical concepts to real-world scenarios related to social media usage. This enhances our analytical skills and helps build a foundation for more complex statistical modeling.

Practicing exercises such as these helps students hone their problem-solving abilities and promotes critical thinking, which are essential skills in any field involving data analysis.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.