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A high school senior uses the Internet to get information on February temperatures in the town where hell be going to college. He finds a Web site with some statistics, but they are given in degrees Celsius. The conversion formula is \({ }^{\circ} \mathrm{F}=9 / 5^{\circ} \mathrm{C}+32\). Determine the Fahrenheit equivalents for the summary information below. Maximum temperature \(=11^{\circ} \mathrm{C} \quad\) Range \(=33^{\circ}\) Mean \(=1^{\circ} \quad\) Standard deviation \(=7^{\circ}\) Median \(=2^{\circ} \quad\) IQR \(=16^{\circ}\)

Short Answer

Expert verified
Maximum: \(50.8^{\circ}F\); Range: \(59.4^{\circ}F\); Mean: \(33.8^{\circ}F\); Standard Deviation: \(12.6^{\circ}F\); Median: \(35.6^{\circ}F\); IQR: \(28.8^{\circ}F\).

Step by step solution

01

Understand the Conversion Formula

The conversion formula to change degrees Celsius to degrees Fahrenheit is given by \(^{\circ}F=\frac{9}{5}^{\circ}C+32\). We will use this formula to convert each of the statistical measures from Celsius to Fahrenheit.
02

Convert Maximum Temperature

Convert the maximum temperature of \(11^{\circ}C\) to Fahrenheit using the formula:\[^{\circ}F = \frac{9}{5} \times 11 + 32 = 19.8 + 32 = 50.8^{\circ}F\]
03

Convert Mean Temperature

Convert the mean temperature of \(1^{\circ}C\) to Fahrenheit:\[^{\circ}F = \frac{9}{5} \times 1 + 32 = 1.8 + 32 = 33.8^{\circ}F\]
04

Convert Median Temperature

Convert the median temperature of \(2^{\circ}C\) to Fahrenheit:\[^{\circ}F = \frac{9}{5} \times 2 + 32 = 3.6 + 32 = 35.6^{\circ}F\]
05

Convert Temperature Ranges and Deviations

For the range and standard deviation, which represent differences in temperature, we only multiply by \(\frac{9}{5}\), not add 32, because they aren't absolute temperatures:- Range \((33^{\circ}C)\): \[9/5 \times 33 = 59.4^{\circ}F\]- Standard deviation \((7^{\circ}C)\): \[9/5 \times 7 = 12.6^{\circ}F\]
06

Convert Interquartile Range (IQR)

Similarly, convert the interquartile range \((16^{\circ}C)\):\[9/5 \times 16 = 28.8^{\circ}F\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Celsius to Fahrenheit
Temperature conversion is essential, especially when dealing with international data presented in different temperature scales. The primary formula to convert a temperature from degrees Celsius to degrees Fahrenheit is:
  • \(^{\circ}F = \frac{9}{5} \times ^{\circ}C + 32\)
Understanding this conversion is crucial for accurately interpreting data. The formula consists of two main components: the multiplication factor \(\frac{9}{5}\) and the addition of 32.
The multiplication factor accounts for the scale difference between Celsius and Fahrenheit. Celsius uses 100 degrees between the freezing point and boiling point of water, compared to Fahrenheit which uses 180 degrees in the same range. The addition of 32 bridges the starting points of the two scales: 0°C is equivalent to 32°F.
It's important to note that when converting differences, such as ranges or deviations, you only multiply by \(\frac{9}{5}\) without adding 32. This is because they measure relative change, not absolute temperature points.
Statistical Measures
Statistical measures like mean, median, range, standard deviation, and interquartile range (IQR) help us understand data sets in a more structured way.
Here's a brief explanation of each:
  • **Mean**: The average of all data points. Here it gives you a general idea of the central tendency of temperatures.
  • **Median**: The middle value when all data points are arranged in order. It is useful for understanding the central tendency when your data includes outliers.
  • **Range**: The difference between the highest and lowest values. It indicates the spread of temperatures.
  • **Standard Deviation**: Reflects how much individual data points deviate from the mean. A large standard deviation means the data points are spread out over a large range of values.
  • **Interquartile Range (IQR)**: The range between the first quartile (25th percentile) and the third quartile (75th percentile), showing the middle 50% of data.
These statistical measures allow us to understand data variability and central tendency, important for making sense of weather patterns.
Data Interpretation
Interpreting data goes beyond just understanding the numbers; it involves analyzing what they mean in context. When looking at temperature data, consider the implications for daily life or specific applications.
For instance, knowing the average maximum temperature helps people prepare for expected weather conditions, while understanding the range or standard deviation reflects potential variations. It supports planning outfits, equipment, or activities that are temperature-sensitive.
Additionally, interquartile ranges and medians provide insights into typical weather patterns, especially useful for those moving to new climates or planning travel. By converting and interpreting these statistics in the Fahrenheit scale, people accustomed to this scale can more easily relate the information to their own experiences.
Understanding both statistical measures and conversion processes is key for accurate data interpretation across different contexts and units.

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Most popular questions from this chapter

Environmental Protection Agency (EPA) fuel economy estimates for automobile models tested recently predicted a mean of \(24.8 \mathrm{mpg}\) and a standard deviation of \(6.2 \mathrm{mpg}\) for highway driving. Assume that a Normal model can be applied. a) Draw the model for auto fuel economy. Clearly label it, showing what the \(68-95-99.7\) Rule predicts. b) In what interval would you expect the central \(68 \%\) of autos to be found? c) About what percent of autos should get more than \(31 \mathrm{mpg}\) ? d) About what percent of cars should get between 31 and \(37.2 \mathrm{mpg}\) ? e) Describe the gas mileage of the worst \(2.5 \%\) of all cars.

A company selling clothing on the Internet reports that the packages it ships have a median weight of 68 ounces and an IQR of 40 ounces. a) The company plans to include a sales flyer weighing 4 ounces in each package. What will the new median and IQR be? b) If the company recorded the shipping weights of these new packages in pounds instead of ounces, what would the median and IQR be? \((1 \mathrm{lb} .=16 \mathrm{oz}\).)

A company that manufactures rivets believes the shear strength (in pounds) is modeled by \(N(800,50)\). a) Draw and label the Normal model. b) Would it be safe to use these rivets in a situation requiring a shear strength of 750 pounds? Explain. c) About what percent of these rivets would you expect to fall below 900 pounds? d) Rivets are used in a variety of applications with varying shear strength requirements. What is the maximum shear strength for which you would feel comfortable approving this company's rivets? Explain your reasoning.

The first Stats exam had a mean of 65 and a standard deviation of 10 points; the second had a mean of 80 and a standard deviation of 5 points. Derrick scored an 80 on both tests. Julie scored a 70 on the first test and a 90 on the second. They both totaled 160 points on the two exams, but Julie claims that her total is better. Explain.

Recall that the beef cattle described in Exercise 17 had a mean weight of 1152 pounds, with a standard deviation of 84 pounds. a) Cattle buyers hope that yearling Angus steers will weigh at least 1000 pounds. To see how much over (or under) that goal the cattle are, we could subtract 1000 pounds from all the weights. What would the new mean and standard deviation be? b) Suppose such cattle sell at auction for 40 cents a pound. Find the mean and standard deviation of the sale prices for all the steers.

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