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Based on the Normal model \(N(100,16)\) describing IQ scores, what percent of people's IQs would you expect to be a) over \(80 ?\) b) under \(90 ?\) c) between 112 and \(132 ?\)

Short Answer

Expert verified
a) 100% over 80. b) 0.62% under 90. c) 0.13% between 112 and 132.

Step by step solution

01

Identify the Normal Distribution

We are given a normal distribution for IQ scores described by the model \(N(100,16)\), where the mean \(\mu = 100\) and the variance \(\sigma^2 = 16\). This implies the standard deviation \(\sigma = 4\).
02

Convert Score to Z-Score for Over 80

To find the percentage of people with an IQ over 80, we first convert the IQ score of 80 to a Z-score using the formula \(Z = \frac{X - \mu}{\sigma}\). Thus, \(Z = \frac{80 - 100}{4} = -5\).
03

Find Probability from Z-Table for Over 80

Using the Z-table, a Z-score of -5 is extremely low, practically resulting in a probability of nearly 0 (or 0.0000) for people scoring 80 or below. Consequently, the probability of scoring over 80 is approximately 1 (or 100%).
04

Convert Score to Z-Score for Under 90

To find the percentage of people with an IQ under 90, convert the IQ score of 90 to a Z-score using the formula \(Z = \frac{X - \mu}{\sigma}\). Thus, \(Z = \frac{90 - 100}{4} = -2.5\).
05

Find Probability from Z-Table for Under 90

Using the Z-table, a Z-score of -2.5 corresponds to a cumulative probability of approximately 0.0062. This means about 0.62% of people have an IQ under 90.
06

Convert Scores to Z-Scores for Between 112 and 132

To find the percentage of people with an IQ between 112 and 132, convert these scores to Z-scores. For 112, \(Z = \frac{112 - 100}{4} = 3\), and for 132, \(Z = \frac{132 - 100}{4} = 8\).
07

Find Probability from Z-Table for Between 112 and 132

Using the Z-table, a score of \(Z = 3\) gives a cumulative probability of roughly 0.9987. Since a Z-score of 8 is far beyond usual tables, it approximates to 1, indicating a nearly full range from Z = 3 to Z = 8. Hence, the probability is approximately 0.0013 or 0.13% for having an IQ between 112 and 132.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-Score
The Z-Score is a powerful statistical tool used to determine how far away a data point is from the mean in the context of a standard normal distribution.

It is calculated using the formula: \[Z = \frac{X - \mu}{\sigma}\]Where:
  • \(Z\) is the Z-score.
  • \(X\) is the data point or score you are examining, such as an IQ score.
  • \(\mu\) is the mean of the distribution.
  • \(\sigma\) is the standard deviation of the distribution.

The Z-score shows the number of standard deviations a particular score is away from the average. For example, a Z-score of -5 suggests the IQ is 5 standard deviations below the mean, while a Z-score of 3 places the IQ 3 standard deviations above the mean.
In our example, Z-scores help us determine probabilities using the Z-table, a statistical tool listing probabilities that a standard normal random variable is less than or equal to a given value.
Probability
Probability is the measure of the likelihood or chance of a particular event occurring. In statistical terms, it's a value between 0 (impossible event) and 1 (certain event), that signifies how often you would expect to see the given event in repeated trials.

In the context of the normal distribution and IQ scores, probabilities inform us about the percentage of individuals likely to fall within a certain range of scores.

For example:
  • A Z-score with a very low value like -5 has a probability near 0, meaning almost nobody scores 80 or below when the mean IQ is 100.
  • A Z-score of -2.5 corresponds to a probability of around 0.0062, indicating about 0.62% have IQs under 90.
  • Probabilities for a range of scores, like between 112 and 132, explain the very small percent (here, just 0.13%) of people falling within this higher bracket.
This is how probabilities provide insight into the distribution of IQ scores within a population.
IQ Scores
IQ Scores, or Intelligence Quotient Scores, are standardized measures used to assess human intelligence. These scores are typically modeled using a normal distribution, with specific mean and standard deviation values that represent the average and spread of intelligence levels across the population, respectively.

In our example, the IQ scores are modeled by the normal distribution \(N(100,16)\), where:
  • \(\mu = 100\): This is the mean, representing the average IQ score.
  • \(\sigma^2 = 16\): This is the variance, with the square root (\(\sigma = 4\)) being the standard deviation.

This model signifies that most people have an IQ score close to 100, with fewer individuals having significantly higher or lower scores.
Understanding the IQ score distribution allows us to use statistics to estimate how common a certain IQ score is among the population. Identifying outliers or extreme values becomes easier with this model; IQs well above or below average show their rarity in this context.
Standard Deviation
Standard Deviation is a crucial measure in statistics that indicates how spread out the numbers in a set of data are. It is the square root of the variance, providing an understanding of how much variation or dispersion exists from the average (mean).

In a normal distribution, approximately 68% of data fall within one standard deviation from the mean, 95% within two standard deviations, and 99.7% within three standard deviations.
  • For IQ scores modeled as \(N(100,16)\), the standard deviation \(\sigma = 4\).
  • This indicates that a majority of IQ scores lie close to 100, within 4 points in either direction for roughly two-thirds of the population.
  • Less common are scores several standard deviations away, confirming either unusually high or low intelligence.
This concept is central when working with Z-scores, as it allows conversion of raw data into standardized scores that describe their distance from the mean in terms of standard deviations. This helps in determining probabilities and understanding the distribution of scores in a population.

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Most popular questions from this chapter

. Agricultural scientists are working on developing an improved variety of Roma tomatoes. Marketing research indicates that customers are likely to bypass Romas that weigh less than 70 grams. The current variety of Roma plants produces fruit that averages 74 grams, but \(11 \%\) of the tomatoes are too small. It is reasonable to assume that a Normal model applies. a) What is the standard deviation of the weights of Romas now being grown? b) Scientists hope to reduce the frequency of undersized tomatoes to no more than \(4 \%\). One way to accomplish this is to raise the average size of the fruit. If the standard deviation remains the same, what target mean should they have as a goal? c) The researchers produce a new variety with a mean weight of 75 grams, which meets the \(4 \%\) goal. What is the standard deviation of the weights of these new Romas? d) Based on their standard deviations, compare the tomatoes produced by the two varieties.

Anna, a language major, took final exams in both French and Spanish and scored 83 on each. Her roommate Megan, also taking both courses, scored 77 on the French exam and 95 on the Spanish exam. Overall, student scores on the French exam had a mean of 81 and a standard deviation of 5, and the Spanish scores had a mean of 74 and a standard deviation of 15 . a) To qualify for language honors, a major must maintain at least an 85 average for all language courses taken. So far, which student qualifies? b) Which student's overall performance was better?

The Virginia Cooperative Extension reports that the mean weight of yearling Angus steers is 1152 pounds. Suppose that weights of all such animals can be described by a Normal model with a standard deviation of 84 pounds. a) How many standard deviations from the mean would a steer weighing 1000 pounds be? b) Which would be more unusual, a steer weighing 1000 pounds or one weighing 1250 pounds?

Suppose your Statistics professor reports test grades as z-scores, and you got a score of \(2.20\) on an exam. Write a sentence explaining what that means.

. Exercise 26 proposes modeling IQ scores with \(N(100,16) .\) What IQ would you consider to be unusually high? Explain.

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