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If you draw a card at random from a wellshuffled deck, is getting an ace independent of the suit? Explain.

Short Answer

Expert verified
Yes, drawing an ace is independent of the suit, as the probabilities are equal.

Step by step solution

01

Understanding Independence of Events

Two events are independent if the occurrence of one event does not affect the occurrence of the other. In this case, we need to determine if drawing an ace from the deck is independent of drawing any particular suit.
02

Probability of Drawing an Ace

Calculate the probability of drawing an ace from a deck. A deck has 52 cards, and there are 4 aces. Thus, the probability of drawing an ace is \( P(A) = \frac{4}{52} = \frac{1}{13} \).
03

Probability of Drawing a Suit

Calculate the probability of drawing a particular suit (e.g., hearts) from the deck. There are 13 cards per suit in a deck of 52 cards. Thus, the probability of drawing a particular suit is \( P(S) = \frac{13}{52} = \frac{1}{4} \).
04

Joint Probability of Drawing an Ace of a Particular Suit

Calculate the probability of drawing both an ace and a card from a specific suit. There is 1 ace per suit. So, the probability is \( P(A \cap S) = \frac{1}{52} \).
05

Test for Independence

To test for independence, check if the probability of drawing an ace given a particular suit is equal to the probability of drawing an ace independently. Calculate \( P(A|S) \), which is the probability of drawing an ace when we know the suit is fixed. Using the definition of conditional probability: \[ P(A|S) = \frac{P(A \cap S)}{P(S)} = \frac{\frac{1}{52}}{\frac{1}{4}} = \frac{1}{13} \].Since \( P(A) = \frac{1}{13} \) and \( P(A|S) = \frac{1}{13} \), drawing an ace is independent of the suit.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independence of Events
In probability, the concept of independence helps us understand how the occurrence of one event relates to another. Two events are considered independent when the outcome of one does not affect the outcome of the other.
This means that knowing the result of one event provides no information about the other.

For example, when determining if drawing an ace from a deck is independent of getting a particular suit, independence implies that the likelihood of drawing an ace remains unchanged regardless of the suit.
This can be confirmed by comparing the probabilities involved;
  • If the probability of drawing an ace (\(P(A)\)) equals the probability of drawing an ace given a specific suit (\(P(A|S)\)), then these events are independent.
  • If these probabilities differ, there is dependence between the events.
Understanding independence is crucial in probability as it ensures our calculations and predictions about combined events are accurate.
Conditional probability
Conditional probability allows us to calculate the probability of an event occurring given that another event has already occurred.
This approach is particularly useful when we want to explore relationships between events or refine our understanding based on existing information.

For instance, consider the probability of drawing an ace if we know the card comes from a specific suit such as hearts. This is expressed as \(P(A|S)\), the probability of an ace occurring given a predefined suit.
The formula for conditional probability is:
  • \[P(A|S) = \frac{P(A \cap S)}{P(S)}\]
This equation tells us how to adjust the basic probability of an event by incorporating new information about another event.
In essence, conditional probability narrows the sample space by focusing on the subset relevant to both events, providing a more precise probability.
Deck of Cards Analysis
A deck of cards offers a standardized set of probabilities, making it an excellent tool for understanding basic probability concepts.
Each standard deck contains 52 cards divided evenly across four suits: hearts, diamonds, clubs, and spades.
Each suit holds 13 cards ranging from Ace to King.

Analyzing a deck of cards can illustrate numerous probability concepts. For our exercise:
  • The probability of drawing any ace (without regard to suit) is calculated by dividing the number of aces, 4, by the total number of cards, 52. Hence, \(P(A) = \frac{4}{52} = \frac{1}{13}\).
  • The probability of drawing a card from a specific suit is the number of cards per suit, 13, divided by the total number of cards. Thus, \(P(S) = \frac{13}{52} = \frac{1}{4}\).
  • For joint probability such as drawing an ace of a particular suit like the Ace of Hearts, the probability is \(P(A \cap S) = \frac{1}{52}\).
Deck of cards analysis incorporates these calculations to help explain how probability functions in a controlled, known setting, facilitating a deeper understanding of event probability and interdependencies.

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Most popular questions from this chapter

A university requires its biology majors to take a course called BioResearch. The prerequisite for this course is that students must have taken either a Statistics course or a computer course. By the time they are juniors, \(52 \%\) of the Biology majors have taken Statistics, \(23 \%\) have had a computer course, and \(7 \%\) have done both. a) What percent of the junior Biology majors are ineligible for BioResearch? b) What's the probability that a junior Biology major who has taken Statistics has also taken a computer course? c) Are taking these two courses disjoint events? Explain. d) Are taking these two courses independent events? Explain.

In the real-estate ads described in Exercise 1 , \(64 \%\) of homes for sale have garages, \(21 \%\) have swimming pools, and \(17 \%\) have both features. a) If a home for sale has a garage, what's the probability that it has a pool too? b) Are having a garage and a pool independent events? Explain. c) Are having a garage and a pool mutually exclusive? Explain.

A company manufacturing electronic components for home entertainment systems buys electrical connectors from three suppliers. The company prefers to use supplier A because only \(1 \%\) of those connectors prove to be defective, but supplier A can deliver only \(70 \%\) of the connectors needed. The company must also purchase connectors from two other suppliers, \(20 \%\) from supplien \(B\) and the rest from supplier \(\mathrm{C}\). The rates of defective connectors from \(\mathrm{B}\) and \(\mathrm{C}\) are \(2 \%\) and \(4 \%\), respectively. You buy one of these components, and when you try to use it you find that the connector is defective. What's the probability that your component came from supplier A?

According to estimates from the federal government's 2003 National Health Interview Survey, based on face-to-face interviews in 16,677 households, approximately \(58.2 \%\) of U.S. adults have both a landline in their residence and a cell phone, \(2.8 \%\) have only cell phone service but no landline, and \(1.6 \%\) have no telephone service at all. a) Polling agencies won't phone cell phone numbers because customers object to paying for such calls. What proportion of U.S. households can be reached by a landline call? b) Are having a cell phone and having a landline independent? Explain.

Seventy percent of kids who visit a doctor have a fever, and \(30 \%\) of kids with a fever have sore throats. What's the probability that a kid who goes to the doctor has a fever and a sore throat?

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