/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 Twenty percent of cars that are ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Twenty percent of cars that are inspected have faulty pollution control systems. The cost of repairing a pollution control system exceeds $$\$ 100$$ about \(40 \%\) of the time. When a driver takes her car in for inspection, what's the probability that she will end up paying more than $$\$ 100$$ to repair the pollution control system?

Short Answer

Expert verified
There's an 8% chance of exceeding $100 for repairs.

Step by step solution

01

Understanding the Problem

We need to determine the probability that a car will require a repair costing more than $100, given that the car is inspected. This involves two probabilities: the probability of having a faulty pollution control system and the probability that repairing it costs more than $100.
02

Define Given Probabilities

We know that the probability of a car having a faulty pollution control system is \( P(A) = 0.20 \) and the probability that the repair cost exceeds $100 given that it is faulty is \( P(B|A) = 0.40 \).
03

Use the Multiplication Rule

The probability that both events happen (i.e., the car has a faulty system and the repair cost exceeds $100) is the product of the probability of each event: \( P(A \text{ and } B) = P(A) \times P(B|A) \). Thus, \( P(A \text{ and } B) = 0.20 \times 0.40 \).
04

Calculate the Probability

Multiply the probabilities obtained: \( P(A \text{ and } B) = 0.20 \times 0.40 = 0.08 \). Thus, there's an 8% chance that a car inspection will lead to a cost of more than $100.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability is the likelihood of an event happening given another event has already occurred. It's a fundamental concept in probability theory that helps us measure how one event can affect the probability of another event. For example, in our scenario, we want to know the chance that a repair costs over \(100, assuming the car already has a faulty pollution control system. Here, the conditional probability is given as \( P(B|A) = 0.40 \). This means there's a 40% chance that the repair will exceed \)100, provided the pollution control system is faulty.

To determine conditional probabilities, follow these steps:
  • Identify the primary event (Event A), the situation that's given or assumed to be true.
  • Identify the secondary event (Event B), the event whose probability is affected by the primary event.
  • Use the formula: \( P(B|A) = \frac{P(A \text{ and } B)}{P(A)} \), where \( P(A \text{ and } B) \) is the probability that both events occur together.
Understanding conditional probability helps untangle complex situations by focusing on events' relationships.
Multiplication Rule
The multiplication rule allows us to find the probability of two or more events happening at the same time. It's particularly useful when dealing with conditional probabilities, as it combines the probability of one event with the conditional probability of another. In simple terms, the rule tells us that the probability of events A and B both occurring is the product of the probability of A and the probability of B given A.

In our car repair example, we have:
  • The probability that a car has a faulty pollution control system (\(P(A) = 0.20\))
  • The conditional probability that repairs cost more than \(100 if the system is faulty (\(P(B|A) = 0.40\))
Using the multiplication rule:
  • \( P(A \text{ and } B) = P(A) \times P(B|A) \)
  • Calculate: \( P(A \text{ and } B) = 0.20 \times 0.40 = 0.08 \)
Thus, the chance that a car inspection leads to costs exceeding \)100 is 8%. This method effectively assesses combined event probabilities.
Faulty System Probability
Faulty system probability is a specific type of probability that quantifies the likelihood of an error or defect in a system. In our example, it refers to cars having faulty pollution control systems. This probability is crucial because it forms the basis for further calculations involving costs or additional inspections needed.
Understanding and calculating the faulty system probability involve:
  • Recognizing the proportion of total cases that can be faulty, given by \( P(A) = 0.20 \). This tells us that 20% of cars are likely to have a faulty system.
  • Using this base probability to anticipate defects' potential impact on costs and maintenance.
By assessing the faulty system probability, companies, and individuals can make informed decisions about inspections and necessary repairs, optimizing costs and resources.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You pick three cards at random from a deck. Find the probability of each event described below. a) You get no aces. b) You get all hearts. c) The third card is your first red card. d) You have at least one diamond.

Employment data at a large company reveal that \(72 \%\) of the workers are married, that \(44 \%\) are college graduates, and that half of the college grads are married. What's the probability that a randomly chosen worker a) is neither married nor a college graduate? b) is married but not a college graduate? c) is married or a college graduate?

Leah is flying from Boston to Denver with a connection in Chicago. The probability her first flight leaves on time is \(0.15\). If the flight is on time, the probability that her luggage will make the connecting flight in Chicago is \(0.95\), but if the first flight is delayed, the probability that the luggage will make it is only \(0.65\). a) Are the first flight leaving on time and the luggage making the connection independent events? Explain. b) What is the probability that her luggage arrives in Denver with her?

An airline offers discounted "advancepurchase" fares to customers who buy tickets more than 30 days before travel and charges "regular" fares for tickets purchased during those last 30 days. The company has noticed that \(60 \%\) of its customers take advantage of the advance-purchase fares. The "no- show" rate among people who paid regular fares is \(30 \%\), but only \(5 \%\) of customers with advance-purchase tickets are no-shows. a) What percent of all ticket holders are no-shows? b) What's the probability that a customer who didn't show had an advance- purchase ticket? c) Is being a no-show independent of the type of ticket a passenger holds? Explain.

Real estate ads suggest that \(64 \%\) of homes for sale have garages, \(21 \%\) have swimming pools, and \(17 \%\) have both features. What is the probability that a home for sale has a) a pool or a garage? b) neither a pool nor a garage? c) a pool but no garage?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.