/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 In Exercise 29 , we suggested th... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercise 29 , we suggested the model \(N(1152,84)\) for weights in pounds of yearling Angus steers. What weight would you consider to be unusually low for such an animal? Explain.

Short Answer

Expert verified
A weight of 984 pounds or less would be considered unusually low for a yearling Angus steer.

Step by step solution

01

Understanding the question

In this case, this exercise is asking for the weight that would be considered unusually low for such an animal. When talking about 'unusually low' or 'unusually high' in statistics, we often refer to values that are more than two standard deviations away from the mean. In this case, since 'unusually low' is asked, we will subtract two standard deviations from the mean weight.
02

Calculating the 'unusually low' weight

The given model is \(N(1152,84)\), where 1152 is the mean weight and 84 is the standard deviation. To calculate the 'unusually low' weight, we subtract two times the standard deviation from the mean: \(1152 - 2*84\).
03

Solve the equation

Perform the subtraction. \(1152 - 2*84 = 984\). This means that any yearling Angus steer weighing 984 pounds or less would be considered unusually low.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
At the heart of many statistical analyses lies the concept of the normal distribution, which is a critical tool for understanding the spread and behavior of most types of data. Imagine a bell-shaped curve where most of the occurrences happen around a central point: this is the essence of the normal distribution. In real-world terms, numerous things, like the heights of a group of people, test scores, or in the case of our exercise, the weights of yearling Angus steers, fit into this pattern.

In a perfectly normal distribution, the mean (average value), median (middle value), and mode (most frequently occurring value) are the same. The spread of values around the mean is symmetric, meaning half the values are above the mean and half are below. The model given in the exercise, N(1152,84), indicates a normal distribution with a mean (average weight) of 1152 pounds and some unit of measurement for spread, which brings us neatly to the concept of standard deviation.
Standard Deviation
The standard deviation is a measure of the amount of variation or dispersion in a set of values. In simpler terms, it tells us how much the values in a dataset deviate from the mean of the dataset. A small standard deviation indicates that the values tend to be close to the mean, while a large standard deviation indicates that the values are spread out over a wider range.

In our exercise, the standard deviation is 84 pounds, meaning that most of the steers' weights will be within 84 pounds of the mean weight. By calculating one, two, or more standard deviations from the mean, we can determine how 'typical' or 'atypical' a weight is. According to empirical rule, for normal distribution approximately 68% of the data falls within one standard deviation, 95% within two standard deviations, and 99.7% within three standard deviations of the mean. This statistical measure helps us set expectations for variation within a dataset, and evaluate what constitutes an 'unusual' observation.
Outliers
In any set of data, there exist values so different from the other observations that they raise eyebrows. These values are known as outliers. Outliers can be indicative of a measurement error, a different population, or simply natural variation. They're important to identify because they can skew data analysis and create false impressions if not accounted for appropriately.

In the context of our exercise, outliers in the weights of Angus steers are those significantly below or above the average weight. Specifically, we considered 'unusually low' weights to be outliers. We determined this by calculating weights that are more than two standard deviations away from the mean – in this case, 984 pounds or less. Such values are rare in the normal distribution and are thus labeled as outliers. Understanding outliers is essential for researchers and statisticians because it aids in fine-tuning data interpretations and makes the decision-making process concerning the data more informed.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Exercise 10 proposes modeling IQ scores with \(N(100,15)\). What IQ would you consider to be unusually high? Explain.

Each year thousands of high school students take either the SAT or the ACT, standardized tests used in the college admissions process. Combined SAT Math and Verbal scores go as high as \(1600,\) while the maximum ACT composite score is \(36 .\) Since the two exams use very different scales, comparisons of performance are difficult. A convenient rule of thumb is \(S A T=40 \times A C T+150\) that is, multiply an ACT score by 40 and add 150 points to estimate the equivalent SAT score. An admissions officer reported the following statistics about the ACT scores of 2355 students who applied to her college one year. Find the summaries of equivalent SAT scores. Lowest score \(=19\) Mean \(=27\) Standard deviation \(=3 \mathrm{Q} 3=30\) Median \(=28 \mathrm{IQF}\)

The mean score on the Stats exam was 75 points with a standard deviation of 5 points, and Gregor's z-score was -2 . How many points did he score?

IQ, finis Consider the IQ model \(N(100,15)\) one last time. a. What IQ represents the 15 th percentile? b. What IQ represents the 98th percentile? c. What's the IQR of the IQs?

A tire manufacturer believes that the treadlife of its snow tires can be described by a Normal model with a mean of 32,000 miles and standard deviation of 2500 miles. a. If you buy one of these tires, would it be reasonable for you to hope it will last 40,000 miles? Explain. b. Approximately what fraction of these tires can be expected to last less than 30,000 miles? c. Approximately what fraction of these tires can be expected to last between 30,000 and 35,000 miles? d. Estimate the IQR of the treadlives. e. In planning a marketing strategy, a local tire dealer wants to offer a refund to any customer whose tires fail to last a certain number of miles. However, the dealer does not want to take too big a risk. If the dealer is willing to give refunds to no more than 1 of every 25 customers, for what mileage can he guarantee these tires to last?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.