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Using \(N(1152,84)\), the Normal model for weights of Angus steers in Exercise 13 a. How many standard deviations from the mean would a steer weighing 1000 pounds be? b. Which would be more unusual, a steer weighing 1000 pounds or one weighing 1250 pounds?

Short Answer

Expert verified
The steer weighing 1000 pounds is 1.81 standard deviations below the mean weight while the steer weighing 1250 pounds is 1.17 standard deviations above the mean weight. Hence, it is more unusual for a steer to weigh 1000 pounds as compared to when a steer weighs 1250 pounds.

Step by step solution

01

Compute the z-score for a steer weighing 1000 pounds.

Z-score is calculated using the formula: \(Z = (X - µ) / σ\), where X is the value from the data set, \(µ\) is the mean and \(σ\) is the standard deviation. Here, \(X = 1000\), \(µ = 1152\), and \(σ = 84\). So, \(Z = (1000 - 1152) / 84 = -1.81\). This means a steer weighing 1000 pounds is 1.81 standard deviations below the mean weight.
02

Compute the z-score for a steer weighing 1250 pounds.

Using the same formula, we will calculate Z-score for a steer weighing 1250 pounds. Here, \(X = 1250\), \(µ = 1152\), and \(σ = 84\). So, \(Z = (1250 - 1152) / 84 = 1.17\). This means a steer weighing 1250 pounds is 1.17 standard deviations above the mean weight.
03

Determine which steer's weight is more unusual.

A data point is considered more unusual if its z-score has a larger absolute value. Here, the absolute z-score of a 1000 pounds steer is 1.81 while absolute z-score of a 1250 pounds steer is 1.17. Hence, it's more unusual for a steer to weigh 1000 pounds than to weigh 1250 pounds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Standard Deviation
Standard deviation is a measure that indicates the amount of variation or dispersion from the statistical mean in a set of data. It is commonly used to quantify the degree to which each number in the dataset differs from the mean, and hence, provides insight into the spread of a dataset.

For example, in the exercise regarding the weights of Angus steers, the standard deviation (\(σ\)) is 84 pounds. This means that the weights of the steers typically vary by 84 pounds above or below the mean (average) weight. A low standard deviation indicates that the data points tend to be close to the mean, whereas a high standard deviation indicates that the data points are spread out over a broader range of values.

Calculating the standard deviation involves several steps, including finding the mean, calculating the difference of each data point from the mean, squaring these differences, finding the average of these squares, and taking the square root of this average. This calculation forms the basis for many statistical analyses and is essential for understanding variability in any data set, such as the weight of steers in this example.
The Significance of Normal Distribution
Normal distribution, also known as the bell curve, is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean. In a normal distribution, the mean, median, and mode of the dataset are all equal.

The properties of a normal distribution are determined by its mean and standard deviation. The mean (\(µ\)) of the distribution determines the location of the center of the graph, and the standard deviation determines the height and width of the graph. In the context of the exercise, the notation 'N(1152,84)' indicates that the steers' weights are normally distributed around a mean of 1152 pounds with a standard deviation of 84 pounds.

A key feature of the normal distribution is the empirical rule, which states that approximately 68% of data falls within one standard deviation of the mean, 95% falls within two standard deviations, and 99.7% falls within three standard deviations. Therefore, in practice, knowing the normal distribution of a dataset can help you predict probabilities and understand the likelihood of a certain outcome, such as the weight of a steer being above or below a certain value.
The Role of Statistical Mean
The statistical mean, often simply called 'the mean', is the average value in a data set. It is calculated by adding up all the numbers and then dividing by the count of numbers. The mean is a measure of central tendency, which gives a good indication of the 'typical' value one can expect within a data set.

In the case of the Angus steers, the mean weight is reported as 1152 pounds, denoted mathematically in the exercise as (\(µ\)). The mean represents the center point of the distribution of steer weights. It's an especially useful measure in a normal distribution because it also identifies the peak of the curve where the data are most concentrated.

Understanding the mean is crucial when working with z-scores, because a z-score measures the distance (in terms of standard deviations) a data point is from the mean. Thus, while standard deviation informs us about the range of variation, and normal distribution gives us a pattern of spread in relation to the mean, the statistical mean itself tells us the central point from which we can measure all other values.

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Most popular questions from this chapter

Based on the model \(N(1152,84)\) describing Angus steer weights from Exercise 29 ?, what are the cutoff values for a. the highest \(10 \%\) of the weights? b. the lowest \(20 \%\) of the weights? c. the middle \(40 \%\) of the weights?

IQ, finis Consider the IQ model \(N(100,15)\) one last time. a. What IQ represents the 15 th percentile? b. What IQ represents the 98th percentile? c. What's the IQR of the IQs?

The Mathematics section of the ACT test had a mean of 20.9 and an SD of 5.3 for the years 2013-2015. If these are well modeled by a Normal distribution, about what percent of students scored a. Over \(31 ?\) b. under \(18 ?\) c. between 18 and \(31 ?\)

A popular band on tour played a series of concerts in large venues. They always drew a large crowd, averaging 21,359 fans. While the band did not announce (and probably never calculated) the standard deviation, which of these values do you think is most likely to be correct: \(20,200,2000,\) or 20,000 fans? Explain your choice.

More cattle Recall that the beef cattle described in Exercise 29 ?had a mean weight of 1152 pounds, with a standard deviation of 84 pounds. a. Cattle buyers hope that yearling Angus steers will weigh at least 1000 pounds. To see how much over (or under) that goal the cattle are, we could subtract 1000 pounds from all the weights. What would the new mean and standard deviation be? b. Suppose such cattle sell at auction for 40 cents a pound. Find the mean and standard deviation of the sale prices (in dollars) for all the steers.

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