/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 Recall from Chapter 17 ?, Exerci... [FREE SOLUTION] | 91Ó°ÊÓ

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Recall from Chapter 17 ?, Exercise 55 ? that students investigated the packaging of potato chips. They purchased 6 bags of Lay's Ruffles marked with a net weight of 28.3 grams. They carefully weighed the contents of each bag, recording the following weights (in grams): \(29.3,28.2,29.1,28.7,28.9,28.5 .\) a. Do these data satisfy the assumptions for inference? Explain. b. Find the mean and standard deviation of the weights. c. Test the hypothesis that the net weight is as claimed.

Short Answer

Expert verified
After checking assumptions, calculating the mean and standard deviation, the calculated t-statistic should be compared with the critical t-value. If the t-statistic is greater than the critical t-value, then we reject the null hypothesis indicating that the claimed net weight differs from the recorded weights. If the t-statistic is less than or equal to the critical t-value, we do not reject the null hypothesis indicating the recorded weights are statistically in line with the claimed net weight.

Step by step solution

01

Check Assumptions

The assumptions for inference that could be employed here are independence and normality. Considering that each bag of chips were purchased and weighed independently from each other, we can safely assume independence. The normality assumption suggests that the sampling distribution of the mean is normal or nearly normal. In this case, our sample size is too small to invoke the Central Limit Theorem directly, we can use a normal probability plot to check this assumption to some extent.
02

Calculate Mean and Standard Deviation

To calculate the mean, sum up all the weights and divide by the number of weights. The mean \(\mu\) can be calculated as follows: \(\mu = \frac{29.3 +28.2 +29.1 +28.7 +28.9 +28.5}{6}\). For standard deviation, calculate each weight's difference from the Mean, square it, sum them up, divide that sum by the count of weights minus 1 and then take the square root.
03

Formulate the Hypothesis

The null hypothesis denoted as H0: µ = 28.3 (the net weight is as claimed). The alternative hypothesis denoted as Ha: µ ≠ 28.3 (the net weight is different from the claim).
04

Test the Hypothesis

A t-statistic will be used to test this hypothesis, calculated as follows: \(t = \frac{\bar{X} - \mu_0}{s/\sqrt{n}}\), where \(\bar{X}\) is the sample mean, \(\mu_0\) is the claimed mean, s is the sample standard deviation, and n is the sample size. Once the t-statistic is calculated, it is compared with the critical t-value for a specified level of significance with degree of freedom \(df = n-1\) to determine if the null hypothesis should be rejected.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
In statistics, hypothesis testing is a vital method that helps us make decisions based on data analysis. It's like a detective's toolkit for statistically verifying or refuting an assumption. The process involves creating two opposite statements called hypotheses. The first one is the **null hypothesis (H0)**, which is generally a statement of no effect or no difference. In the context of the potato chip example, **H0 states that the mean weight of the bags is 28.3 grams**.

The second statement is the **alternative hypothesis (Ha)**, which contradicts the null and represents a potential different outcome. Here, **Ha suggests that the mean weight is not 28.3 grams**. We perform a statistical test to determine which hypothesis is more convincing based on the sample data.
  • We calculate a test statistic (like the t-statistic in this case).
  • We compare it to a critical value or use it to determine a p-value.
  • If the test statistic indicates a small probability under H0, we might reject the null hypothesis.
Hypothesis testing is all about assessing evidence and making informed decisions based on the strength of this evidence.
Standard Deviation
Standard deviation is like a thermometer for variability—it tells us how much the data points in a sample deviate from the mean. It's a crucial concept in statistics education since it gives insight into the spread or dispersion of the data.

In simpler terms, if the standard deviation is small, it means the data points are close to the mean, indicating consistency. On the other hand, a larger standard deviation implies more spread out data, showing higher variability among the observations.
  • Calculating this involves finding the average of the squared differences from the mean.
  • The formula is: \[\text{Standard Deviation} = \sqrt{\frac{\sum (X_i - \bar{X})^2}{n-1}}\]where \(X_i\) are the individual data points, \(\bar{X}\) is the mean, and \(n\) is the sample size.
By understanding standard deviation, students can better interpret how much individual weights of potato chip bags differ from the average weight.
Central Limit Theorem
The Central Limit Theorem (CLT) is a cornerstone concept that assures us that the sampling distribution of the sample mean will be approximately normal, even if the data in the population isn't perfectly normal. This holds provided the sample size is large enough.

However, in our potato chips case, the sample size is quite small (only 6 bags). Therefore, we can't fully rely on the CLT to justify normality. But it is still crucial to understand because:
  • With a larger sample, the distribution of the sample mean becomes more normal, allowing us to make easier inferences.
  • CLT helps in constructing confidence intervals and conducting hypothesis tests when sample sizes get bigger.
Having a grasp of the Central Limit Theorem aids students in understanding why larger samples tend to give more reliable statistical outcomes.
Normality Assumption
The normality assumption is an essential requirement in many statistical techniques, such as t-tests, because it ensures that the inferential procedures yield reliable results. It implies that the data should follow a normal distribution or look approximately 'bell-shaped'.

In scenarios like our potato chip investigation, checking for normality is critical, especially with smaller samples. Since the CLT can't help much with a tiny sample size, visual methods like normal probability plots or statistical tests for normality can help determine this aspect.
  • When data is normal, parametric tests can be used, which are generally more powerful.
  • If not, alternatives like non-parametric tests might be required.
Understanding and ensuring the normality assumption is met can improve the reliability and accuracy of statistical analyses, making it a vital part of statistics education.

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Most popular questions from this chapter

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