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An airline's public relations department says that the airline rarely loses passengers' luggage. It further claims that on those occasions when luggage is lost, \(90 \%\) is recovered and delivered to its owner within 24 hours. A consumer group that surveyed a large number of air travelers found that only 103 of 122 people who lost luggage on that airline were reunited with the missing items by the next day. Does this cast doubt on the airline's claim? Explain.

Short Answer

Expert verified
The actual percentage, based on the survey, of lost luggage that was recovered within 24 hours is approximately \(84.4\% \), which is significantly less than the airline's claim of \(90\% \). Therefore, the findings of the consumer group does cast doubt on the claim made by the airline's public relations department.

Step by step solution

01

Calculating the Actual Percentage

First we need to calculate the actual percentage of lost luggage that is recovered within 24 hours. We do that by dividing the number of people who recovered their luggage within 24 hours by the total number of people who lost their luggage and multiplying it by 100. So it will be: \((103 / 122) * 100\)
02

Comparing with Airline Claim

After we have calculated the actual percentage, we need to compare this with the airline’s claim of 90%. If our calculated percentage is significantly less than 90%, then it would cast doubt on the airline's claim.
03

Formulating the Conclusion

Based on the result from step 2, we conclude whether the claim of the airline's public relations department is in doubt or not. If it is significantly less than the airline's claim of 90%, it will indeed cast doubt on their claim. However, if the calculated percentage is approximately the same as or higher than 90%, it will not.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Significance
Statistical significance plays a crucial role in hypothesis testing. It is a measure of the extent to which a result deviates from what would be expected by pure chance. In the context of our airline luggage problem, demonstrating statistical significance would mean providing strong evidence that the observed 84.4% of luggage being returned within 24 hours (calculated from 103 out of 122) is not consistent with the airline's claim of 90% purely due to random variation.

In hypothesis testing, we establish a null hypothesis that represents the scenario being challenged—in this case, the airline's claim. We then calculate the probability of obtaining our observed result (or one more extreme) given that the null hypothesis is true. If this probability, known as the p-value, is less than a predefined significance level (usually 5%), we reject the null hypothesis, thus suggesting that our result is statistically significant.
Confidence Intervals
Confidence intervals provide a range of values within which we can say with a certain level of confidence that a population parameter lies. For the airline example, a confidence interval around the proportion of lost luggage returned within 24 hours could indicate the range of percentages we might expect if we were able to survey every single case of lost luggage for the airline.

Typically, a 95% confidence interval is used. This means if we were to take many random samples and calculate confidence intervals for each, approximately 95% of those intervals would contain the true population parameter. Should the airline's claimed 90% not fall within our calculated confidence interval, it further casts doubt on their claim, reinforcing any findings of statistical significance.
P-value Calculation
The p-value is a fundamental concept in hypothesis testing that quantifies the evidence against the null hypothesis. It is calculated as the probability of obtaining a result at least as extreme as the one observed, under the assumption that the null hypothesis is true.

In the luggage example, calculating the p-value would involve determining the likelihood of observing 84.4% or less of luggage being returned within 24 hours if the true percentage were actually 90%, as the airline claims. A small p-value indicates that such an extreme result is unlikely to occur just by chance, suggesting that there may be a genuine issue with the airline's process for returning lost luggage.
Binomial Distribution
Many random events follow a binomial distribution, which applies when we are dealing with a fixed number of independent 'trials' each with two possible outcomes. In the airline's situation, each piece of lost luggage represents a trial with two outcomes: it is either returned within 24 hours or it isn't.

The distribution is defined by two parameters: the number of trials (in our case, 122 people who lost luggage) and the probability of 'success' on each trial (the purported 90% recovery rate stated by the airline). If we want to calculate the probability of exactly 103 successful outcomes (returned luggage), or to find the p-value for our example, the binomial distribution formula is used. This formula helps in determining the likelihood of a given number of successes in a set number of trials, allowing us to compute probabilities crucial for hypothesis testing.

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Most popular questions from this chapter

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