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An airline's public relations department says that the airline rarely loses passengers' luggage. It further claims that on those occasions when luggage is lost, \(90 \%\) is recovered and delivered to its owner within 24 hours. A consumer group that surveyed a large number of air travelers found that only 103 of 122 people who lost luggage on that airline were reunited with the missing items by the next day. Does this cast doubt on the airline's claim? Explain.

Short Answer

Expert verified
The actual percentage, based on the survey, of lost luggage that was recovered within 24 hours is approximately \(84.4\% \), which is significantly less than the airline's claim of \(90\% \). Therefore, the findings of the consumer group does cast doubt on the claim made by the airline's public relations department.

Step by step solution

01

Calculating the Actual Percentage

First we need to calculate the actual percentage of lost luggage that is recovered within 24 hours. We do that by dividing the number of people who recovered their luggage within 24 hours by the total number of people who lost their luggage and multiplying it by 100. So it will be: \((103 / 122) * 100\)
02

Comparing with Airline Claim

After we have calculated the actual percentage, we need to compare this with the airline’s claim of 90%. If our calculated percentage is significantly less than 90%, then it would cast doubt on the airline's claim.
03

Formulating the Conclusion

Based on the result from step 2, we conclude whether the claim of the airline's public relations department is in doubt or not. If it is significantly less than the airline's claim of 90%, it will indeed cast doubt on their claim. However, if the calculated percentage is approximately the same as or higher than 90%, it will not.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Significance
Statistical significance plays a crucial role in hypothesis testing. It is a measure of the extent to which a result deviates from what would be expected by pure chance. In the context of our airline luggage problem, demonstrating statistical significance would mean providing strong evidence that the observed 84.4% of luggage being returned within 24 hours (calculated from 103 out of 122) is not consistent with the airline's claim of 90% purely due to random variation.

In hypothesis testing, we establish a null hypothesis that represents the scenario being challenged—in this case, the airline's claim. We then calculate the probability of obtaining our observed result (or one more extreme) given that the null hypothesis is true. If this probability, known as the p-value, is less than a predefined significance level (usually 5%), we reject the null hypothesis, thus suggesting that our result is statistically significant.
Confidence Intervals
Confidence intervals provide a range of values within which we can say with a certain level of confidence that a population parameter lies. For the airline example, a confidence interval around the proportion of lost luggage returned within 24 hours could indicate the range of percentages we might expect if we were able to survey every single case of lost luggage for the airline.

Typically, a 95% confidence interval is used. This means if we were to take many random samples and calculate confidence intervals for each, approximately 95% of those intervals would contain the true population parameter. Should the airline's claimed 90% not fall within our calculated confidence interval, it further casts doubt on their claim, reinforcing any findings of statistical significance.
P-value Calculation
The p-value is a fundamental concept in hypothesis testing that quantifies the evidence against the null hypothesis. It is calculated as the probability of obtaining a result at least as extreme as the one observed, under the assumption that the null hypothesis is true.

In the luggage example, calculating the p-value would involve determining the likelihood of observing 84.4% or less of luggage being returned within 24 hours if the true percentage were actually 90%, as the airline claims. A small p-value indicates that such an extreme result is unlikely to occur just by chance, suggesting that there may be a genuine issue with the airline's process for returning lost luggage.
Binomial Distribution
Many random events follow a binomial distribution, which applies when we are dealing with a fixed number of independent 'trials' each with two possible outcomes. In the airline's situation, each piece of lost luggage represents a trial with two outcomes: it is either returned within 24 hours or it isn't.

The distribution is defined by two parameters: the number of trials (in our case, 122 people who lost luggage) and the probability of 'success' on each trial (the purported 90% recovery rate stated by the airline). If we want to calculate the probability of exactly 103 successful outcomes (returned luggage), or to find the p-value for our example, the binomial distribution formula is used. This formula helps in determining the likelihood of a given number of successes in a set number of trials, allowing us to compute probabilities crucial for hypothesis testing.

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Most popular questions from this chapter

He cheats? A friend of yours claims that when he tosses a coin he can control the outcome. You are skeptical and want him to prove it. He tosses the coin, and you call heads; it's tails. You try again and lose again. a. Do two losses in a row convince you that he really can control the toss? Explain. b. You try a third time, and again you lose. What's the probability of losing three tosses in a row if the process is fair? c. Would three losses in a row convince you that your friend controls the outcome? Explain. d. How many times in a row would you have to lose to be pretty sure that this friend really can control the toss? Justify your answer by calculating a probability and explaining what it means.

A national vital statistics report indicated that about \(3 \%\) of all births produced twins. Is the rate of twin births the same among very young mothers? Data from a large city hospital found that only 7 sets of twins were born to 469 teenage girls. Test an appropriate hypothesis and state your conclusion. Be sure the appropriate assumptions and conditions are satisfied before you proceed.

According to the 2010 Census, \(16 \%\) of the people in the United States are of Hispanic or Latino origin. One county supervisor believes her county has a different proportion of Hispanic people than the nation as a whole. She looks at their most recent survey data, which was a random sample of 437 county residents, and found that 44 of those surveyed are of Hispanic origin. a. State the hypotheses. b. Name the model and check appropriate conditions for a hypothesis test. c. Draw and label a sketch, and then calculate the test statistic and P-value. d. State your conclusion.

Write the null and alternative hypotheses you would use to test each of the following situations: a. A governor is concerned about his "negatives"- -the percentage of state residents who express disapproval of his job performance. His political committee pays for a series of TV ads, hoping that they can keep the negatives below \(30 \%\). They will use follow-up polling to assess the ads' effectiveness. b. Is a coin fair? c. Only about \(20 \%\) of people who try to quit smoking succeed. Sellers of a motivational tape claim that listening to the recorded messages can help people quit.

Pollution A company with a fleet of 150 cars found that the emissions systems of 7 out of the 22 they tested failed to meet pollution control guidelines. Is this strong evidence that more than \(20 \%\) of the fleet might be out of compliance? Test an appropriate hypothesis and state your conclusion. Be sure the appropriate assumptions and conditions are satisfied before you proceed.

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