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Suppose the probability of a major earthquake on a given day is 1 out of 10,000 . a. What's the expected number of major earthquakes in the next 1000 days? b. Use the Poisson model to approximate the probability that there will be at least one major earthquake in the next 1000 days.

Short Answer

Expert verified
a. The expected number of major earthquakes in the next 1000 days is 0.1. b. The probability that there will be at least one major earthquake in the next 1000 days is \(1 - e^{-0.1}\).

Step by step solution

01

Calculate Expected Value

Given that the probability of a major earthquake on any given day \(P(E)\) is 1 out of 10,000, we use the formula for expectation, \(E(X) = n \times P(E)\), where \(n\) is the total number of trials. In this case, we have \(n = 1000\) days. So, \(E(X) = 1000 \times \frac{1}{10000} = 0.1\). This means that the expected number of major earthquakes in the next 1000 days is 0.1.
02

Define Poisson Model

For the Poisson process, the parameter lambda \(\lambda\) is the average number of events in a given length of time. Since we expect 0.1 earthquake in 1000 days, we have \(\lambda = 0.1\).
03

Calculate Probability using Poisson Model

We want to find the probability of at least one earthquake in the next 1000 days. This is the complement of the event that there will be no earthquakes in the next 1000 days. Using the formula for the Poisson distribution, \(P(X=k) = \frac{\lambda^k e^{-\lambda}}{k!}\), we can find the probability of zero earthquakes, where \(X\) is the random variable representing the number of earthquakes, \(k = 0\), \(\lambda = 0.1\), and \(e\) is the base of the natural logarithm: \(P(X=0) = \frac{0.1^0 e^{-0.1}}{0!} = e^{-0.1}\). The probability of at least one earthquake is the complement of this: \(P(X>=1) = 1 - P(X=0) = 1 - e^{-0.1}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expected Value
The expected value is a fundamental concept in probability theory that represents the average outcome of a random event if it were to be repeated many times. Think of it as a long-term average that you would expect after conducting an experiment over and over again under the same conditions.

The expected value is calculated using the formula:\[ E(X) = n \times P(E) \]Here, \( E(X) \) represents the expected value, \( n \) stands for the total number of trials or occurrences, and \( P(E) \) is the probability of a specific event occurring. To better grasp this, let's look at the exercise regarding major earthquakes. Since the probability of a major earthquake occurring on any given day is 1 in 10,000 (\[ P(E) = \frac{1}{10000} \]), over 1000 days, we calculate the expected number of earthquakes as:\[ E(X) = 1000 \times \frac{1}{10000} = 0.1 \]This result implies that, on average, you'd expect 0.1 major earthquakes over the course of 1000 days. While you can't have a fraction of an earthquake in reality, the expected value here helps us understand the average rate of occurrence over time.
Poisson Distribution
The Poisson distribution is a probability distribution that expresses the probability of a given number of events occurring in a fixed interval of time or space if these events occur with a known constant rate and independently of the time since the last event. This distribution is particularly useful for modeling the number of times an event occurs within a specific interval.

For instance, when modeling the occurrence of earthquakes, if they are rare and independent events over a specified period, the Poisson distribution can be quite effective. It is characterized by the parameter lambda (\( \lambda \)), which is the average rate of occurrences in a given length of time. The formula for the Poisson probability is:\[ P(X=k) = \frac{\lambda^k e^{-\lambda}}{k!} \]In this formula, \( X \) is the random variable indicating the number of events (earthquakes), \( k \) is the number of occurrences being calculated for, \( e \) is the base of the natural logarithm, and \( k! \) represents \( k \) factorial. To reconcile this with our earthquake example, if the expected number (lambda) of earthquakes in 1000 days is 0.1, we apply this rate to the Poisson formula to determine the probability of different numbers of earthquakes occurring in that period. It’s an elegant way to estimate the likelihood of rare events over time.
Probability Theory
Probability theory is the mathematical framework for quantifying the likelihood of events, ranging from the flip of a coin to the occurrence of natural disasters. It provides a set of rules and principles to deal with uncertain events and make sense of randomness.In probability, we deal with outcomes and the likelihood that these outcomes occur. When we refer to a 'probability,' we’re talking about a value between 0 and 1, including both. A probability of 0 means an event will not occur, while a probability of 1 assures the event will happen. Anything in between reflects varying degrees of certainty or uncertainty.

Applying this theory to earthquakes, we consider each day as a trial where an earthquake may or may not occur. The problem earlier asked about the probability of at least one major earthquake in 1000 days. Using probability theory, we don't just guess; we calculate based on known probabilities and sound mathematical models, like the Poisson distribution, to come up with precise figures for decision-making.
Complement of an Event
In probability theory, the complement of an event is essentially the opposite of the event itself. If the event is 'having an earthquake,' the complement is 'not having an earthquake'. When we calculate probabilities, we also think about the probabilities of things not happening because they provide valuable insights too.The probability of an event and its complement always add up to 1 because between the two, they cover every possible outcome. Mathematically, if the probability of an event \( E \) is \( P(E) \), the probability of the complement of \( E \), written as \( P(E^c) \), is:\[ P(E^c) = 1 - P(E) \]The exercise on earthquake probability made use of the concept of the complement to determine the probability of experiencing at least one earthquake. Instead of directly calculating the probability of one or more earthquakes, which could be cumbersome, we calculate the easier event — no earthquakes — and subtract from 1 to find the desired probability. This complementary approach is a helpful strategy when dealing with probabilities of rare events.

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Most popular questions from this chapter

A cable provider wants to contact customers in a particular telephone exchange to see how satisfied they are with the new digital TV service the company has provided. All numbers are in the 452 exchange, so there are 10,000 possible numbers from \(452-0000\) to \(452-9999 .\) If they select the numbers with equal probability: a. What distribution would they use to model the selection? b. The new business "incubator" was assigned the 200 numbers between \(452-2500\) and \(452-2699,\) but these businesses don't subscribe to digital TV. What is the probability that the randomly selected number will be for an incubator business? c. Numbers above 9000 were only released for domestic use last year, so they went to newly constructed residences. What is the probability that a randomly selected number will be one of these?

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