/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 A certain tennis player makes a ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A certain tennis player makes a successful first serve \(70 \%\) of the time. Assume that each serve is independent of the others. If she serves 6 times, what's the probability she gets a. all 6 serves in? b. exactly 4 serves in? c. at least 4 serves in? d. no more than 4 serves in?

Short Answer

Expert verified
To solve this exercise, you have to successively apply the formula for binomial probability to each sub-task and add/subtract the results according to the question. The main take-away from the exercise is understanding the concept of independent events and how it applies to a real-world scenario.

Step by step solution

01

Calculate Probability for all 6 serves

For calculating the probability of all 6 serves getting in, we see this as '6 choose 6' scenario which is only one way. We plug in \(n = 6\), \(k = 6\) and \(p = 0.70\) into the formula, \(P(X = 6) = C(6, 6)*(0.7^6)*(1-0.7)^{6-6}\)
02

Calculate Probability for exactly 4 serves

For calculating the probability of exactly 4 serves getting in, we see this as '6 choose 4' scenario. We plug in \(n = 6\), \(k = 4\) and \(p = 0.70\) into the formula, \(P(X = 4) = C(6, 4)*(0.7^4)*(1-0.7)^{6-4}\)
03

Calculate Probability for at least 4 serves

Calculating the Probability of getting at least 4 serves in needs summing up probabilities for 4, 5 and 6 serves getting in. We calculate each of these separately as '6 choose 4', '6 choose 5' and '6 choose 6' scenarios and sum up the results. \(P(X >= 4) = P(X=4) + P(X=5) + P(X=6)\)
04

Calculate Probability for no more than 4 serves

Calculating the Probability of getting no more than 4 serves in needs summing up probabilities for 0, 1, 2, 3 and 4 serves getting in. We calculate each of these separately as '6 choose 0', '6 choose 1', '6 choose 2', '6 choose 3' and '6 choose 4' scenarios and sum up the results. \(P(X<=4) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4)\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Probability Distribution
Understanding the binomial probability distribution is crucial for solving problems involving repeated, independent events with two possible outcomes, like successes or failures. In the context of our tennis player, each serve can either be successful (a 'hit') or not (a 'miss'). Since we're told each of her serves is independent and she has a probability of success of 70%, or (0.70), we can use the binomial distribution to model this situation.

A key characteristic of this distribution is that the probability of success remains constant for each trial. When we calculate the probability of different outcomes for her 6 serves, we're actually finding the probabilities of specific points on the binomial distribution for 6 trials with a success rate of 70%.
Independent Events
When we say that each serve is independent of the others, it implies that the outcome of one serve has no effect on the outcome of any of the subsequent serves. This assumption is foundational for applying the binomial probability distribution. If the events were not independent, we would have to use more complex methods of calculation, as the probability of success might change based on previous outcomes.

In practical terms, even if our player misses a serve, this does not change her probability of hitting the next serve, which remains at 70%. This constant probability is essential for our calculations to remain valid under the binomial distribution model.
Binomial Formula
The binomial formula is a mathematical expression that allows us to calculate the probability of observing a certain number of successes in a fixed number of independent trials. The general formula is given by: \[P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}\]

Here, \(P(X = k)\) represents the probability of getting exactly \(k\) successes in \(n\) trials, \(\binom{n}{k}\) is the binomial coefficient, \(p\) is the probability of success in a single trial, and \((1-p)\) is the probability of failure. When we calculated the probabilities for our tennis player, we used this exact formula, with \(p = 0.70\) and \(n = 6\), altering \(k\) to fit different scenarios (such as getting exactly 4 serves in, at least 4 serves, etc.).
Probability of Success
The probability of success, denoted by \(p\) in our formulas, is a measure of how likely it is for a specific event to occur, in this case, a successful serve. For our tennis player, \(p\) is given as 70%, or 0.70 in decimal form. This number is an essential part of both setting up our distribution model and calculating the various probabilities for different numbers of successful serves.

Knowing the probability of success allows us to establish both the expected number of successful events over multiple trials and to calculate specific binomial probabilities. It's important to realize that the probability of success doesn't change after each trial in a binomial distribution, reinforcing the concept of independent events in our analysis.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose \(75 \%\) of all drivers always wear their seatbelts. Let's investigate how many of the drivers might be belted among five cars waiting at a traffic light. a. Describe how you would simulate the number of seatbelt-wearing drivers among the five cars. b. Run at least 30 trials. c. Based on your simulation, estimate the probabilities there are no belted drivers, exactly one, two, etc. d. Find the actual probability model. e. Compare the distribution of outcomes in your simulation to the probability model.

It is generally believed that nearsightedness affects about \(12 \%\) of all children. A school district tests the vision of 169 incoming kindergarten children. How many would you expect to be nearsighted? With what standard deviation?

A basketball player has made \(80 \%\) of his foul shots during the season. Assuming the shots are independent, find the probability that in tonight's game he a. misses for the first time on his fifth attempt. b. makes his first basket on his fourth shot. c. makes his first basket on one of his first 3 shots.

At a certain college, \(6 \%\) of all students come from outside the United States. Incoming students there are assigned at random to freshman dorms, where students live in residential clusters of 40 freshmen sharing a common lounge area. How many international students would you expect to find in a typical cluster? With what standard deviation?

The euro Shortly after the introduction of the euro coin in Belgium, newspapers around the world published articles claiming the coin is biased. The stories were based on reports that someone had spun the coin 250 times and gotten 140 = heads-that's \(56 \%\) heads. Do you think this is evidence that spinning a euro is unfair? Explain.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.