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About \(8 \%\) of males are color-blind. A researcher needs some color-blind subjects for an experiment and begins checking potential subjects. a. On average, how many men should the researcher expect to check to find one who is color-blind? b. What's the probability that she won't find anyone colorblind among the first 4 men she checks? c. What's the probability that the first color-blind man found will be the sixth person checked? d. What's the probability that she finds someone who is color-blind before checking the 10th man?

Short Answer

Expert verified
a. On average, the researcher should expect to check about 13 men. b. The probability she won't find anyone colorblind among the first 4 men she checks is about 73.5%. c. The probability the first colorblind man is the 6th man checked is about 3.4%. d. The probability she finds someone colorblind before checking the 10th man is about 54%.

Step by step solution

01

Average Number of Checked Men to Find First Color-Blind

As the average number of trials to meet success is the reciprocal of the probability of each 'successful' trial, divide 1 by the likelihood to find a color blind man, which is \(0.08\), to get the expectation. The mathematical operation to perform here is \(1 / 0.08 = 12.5\). So on average, it is expected to check about 13 men to find one who is color-blind (we round up as we can't check half a person).
02

Finding a Color-Blind among the First 4 Checks

The probability that she won't find anyone colorblind among the first four men she checks is equivalent to having four 'failures' in a row. The probability of each 'failure' is \(1 - 0.08\). Therefore, we will raise \((1 - 0.08)\) to the 4th power to get \((1 - 0.08)^4 = 0.735\). So the probability is about 73.5%.
03

The Colorblind Man Being the Sixth Check

The probability that the first color-blind man is the sixth man checked is equivalent to the first 5 men checked (or trials) being 'failures' and the sixth being a 'success'. Therefore we apply the geometric distribution formula \((1 - p)^{k-1} * p\), where \(p\) is the probability of success, and \(k\) is the total number of trials. Performing this calculation gives \((1 - 0.08)^5 * 0.08 = 0.034\). So the probability is about 3.4%.
04

Finding a Color-Blind Before 10th Check

The probability that she finds someone who is color-blind before checking the 10th man is equivalent to at least one 'success' in the first 9 trials. Rather than summing these probabilities, it is simpler to find the complementary probability or having 9 'failures', and subtract that from 1. Performing this calculation gives \(1 - (1 - 0.08)^9 = 0.54\). So the probability is about 54%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometric Distribution
The geometric distribution is a probability distribution that models the number of trials needed to get the first success in a series of independent Bernoulli trials. Think of it as flipping a coin. You're trying to get heads, and you're interested in how many flips it takes.

Key characteristics include:
  • Each trial is independent.
  • Each trial has two possible outcomes: success or failure.
  • The probability of success is constant in each trial.
For example, in the given exercise, to find a color-blind man, each man checked is a separate trial. Using the formula for expectation or average number of trials, the reciprocal of the probability of success (\( p \)) gives us the expected number of trials. So, with each man having an 8% chance to be color-blind, on average, the researcher must check 13 men to find one who is color-blind.
Binomial Distribution
The binomial distribution is used when you are interested in the number of successes over a fixed number of trials. If you think of it as a series of dice rolls, it's like predicting how many times you'll roll a specific number over multiple rolls.

Main properties include:
  • The trials are independent.
  • Each trial has only two outcomes: success or failure.
  • There is a fixed number of trials.
In the exercise, the probability that she won't find anyone color-blind among the first four men she checks uses the concept of repeated trials producing failures. By raising the probability of failure to the power of the number of trials, the calculation yields the chances of not finding a single color-blind man, resulting in about 73.5% probability.
Expectation Calculation
Expectation calculation refers to determining the average number of trials needed or the expected value of a probability distribution. It's like predicting the average outcome in a game where you keep playing until you win.

For a geometric distribution, the expectation is \( \frac{1}{p} \), where \( p \) is the probability of success. In our exercise, with an 8% probability of success (color-blindness), the average number of needed checks is 12.5. Since you can't check half a person, you round up to 13.

This kind of calculation helps researchers understand what to anticipate, saving time and resources in experiments like these.
Success and Failure Probabilities
Success and failure probabilities are fundamental in probability theory, describing the likelihood of an event occurring (success) or not occurring (failure).

These probabilities must add up to 1, as one or the other must occur. For example, if the probability of success \( p \) is 0.08, then the probability of failure is \( 1 - p = 0.92 \).

Using these probabilities, we can find the likelihood of sequences of successes and failures. For instance, the probability of the first color-blind man being the sixth person is calculated by multiplying the probabilities of five failures by the probability of one success, resulting in about 3.4%. Similarly, finding a success before the 10th check involves calculating at least one success in the first nine trials, which has a 54% chance.

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