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A consumer organization inspecting new cars found that many had appearance defects (dents, scratches, paint chips, etc.). While none had more than three of these defects, \(7 \%\) had three, \(11 \%\) two, and \(21 \%\) one defect. Find the expected number of appearance defects in a new car and the standard deviation.

Short Answer

Expert verified
The expected number of appearance defects in a new car is approximately 0.68 and the standard deviation is approximately 0.68.

Step by step solution

01

Define the random variable

Let's define the random variable X as the number of appearance defects in a new car. X can take the values of 0, 1, 2, 3. The probabilities for these values are, respectively: p(0) = 1 - p(1) - p(2) - p(3) = 1 - 0.21 - 0.11 -0.07 = 0.61, p(1) = 0.21, p(2) = 0.11, p(3) = 0.07.
02

Calculate the Expected Value

The expected value (E) is calculated by summing the multiplication of each value of the random variable by its corresponding probability. E(X) = Σ [x * P(x)] = 0*0.61 + 1*0.21 + 2*0.11 + 3*0.07 = 0.68
03

Calculate the Variance.

The variance is the expected value of the squared deviation from the mean. Var(X) = E[(X- E(X))^2] = Σ [[x - E(X)]^2 * P(x)] = [(0 - 0.68)^2 * 0.61] + [(1 - 0.68)^2 * 0.21] + [(2 - 0.68)^2 * 0.11] + [(3 - 0.68)^2 * 0.07] = 0.46.
04

Calculate the Standard Deviation.

The standard deviation is the square root of the variance. So, the standard deviation is \( \sqrt{0.46} \approx 0.68 \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Imagine you're about to flip a coin. You're probably wondering if it'll land on heads or tails. That's where probability comes in—it's the math that helps us figure out the chances of different outcomes. In our car inspection example, the probability was used to measure the likelihood of a new car having a certain number of defects.

With probability, you can't say for certain what will happen, but you can predict possible outcomes and how often they might occur. Each outcome is assigned a percentage or fraction. Like in the exercise, we had a 7% chance for three defects, which in probability terms means there's a 7% chance to observe this particular outcome if we pick a new car at random. Probability ranges from 0 (impossible) to 1 (certain), or 0% to 100% in percentage terms.
Random Variable
Now, let's chat about what a random variable is. It's like a placeholder for the outcomes of a random event—like the number of defects (0, 1, 2, 3) in the case of new cars. Each random variable gets a value (these numbers) that depends on pure chance.

There are two main types of random variables: discrete and continuous. Discrete ones, like in our exercise, have specific values that you can list out (since a car can't have 2.5 defects, right?). Continuous random variables, on the other hand, can take on any value within a range (like measuring the time it takes for paint to dry—down to the millisecond!). This concept is super important because it allows us to apply mathematical operations to outcomes that involve uncertainty.
Variance
Variance is a bit like the spread of breadcrumbs on a table—it tells us how much those crumbs (or in our case, the number of defects) are spread out from the average (expected value). When the variance is low in our car defects scenario, it means most cars have a number of defects close to the expected value. A high variance, however, indicates that the defects are all over the place—some cars might have no defects, while others could have a lot.

In our exercise, we calculated the variance to find out exactly how spread out the defects were. The formula involves squaring the difference between each possible number of defects and the expected value, multiplying each by the probability of that number of defects, and adding them together. It's like finding the average of the squared differences. This number is central to understanding the 'texture' of any set of data, telling us much more than the average can on its own.

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