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Use the computer output (from different computer packages) to estimate the intercept \(\beta_{0},\) the slope \(\beta_{1},\) and to give the equation for the least squares line for the sample. Assume the response variable is \(Y\) in each case. $$ \begin{array}{lrrrr} \text { Coefficients: } & \text { Estimate } & \text { Std.Error } & \mathrm{t} \text { value } & \mathrm{Pr}(>|\mathrm{t}|) \\ \text { (Intercept) } & 7.277 & 1.167 & 6.24 & 0.000 \\ \text { Dose } & -0.3560 & 0.2007 & -1.77 & 0.087 \end{array} $$

Short Answer

Expert verified
The intercept (\(\beta_0\)) is 7.277, the slope (\(\beta_1\)) is -0.3560, and the equation of the least squares line is \(\hat{Y} = 7.277 - 0.3560* Dose\).

Step by step solution

01

Identify the Intercept (\(\beta_0\))

The Intercept (\(\beta_0\)) is given in the output table under the 'Estimate' column next to '(Intercept)'. From the table, \(\beta_0 = 7.277\). This value represents the estimated value of \(Y\) when all other predictor variables are zero.
02

Identify the Slope (\(\beta_1\))

The Slope (\(\beta_1\)) is given in the output table under the 'Estimate' column next to 'Dose'. From the table, \(\beta_1 = -0.3560\). This value represents how much \(Y\) changes for each one-unit change in the predictor variable 'Dose'.
03

Formulate the Least Squares Line

The equation for the least squares line is always of the form \(\hat{Y} = \beta_0 + \beta_1X\). Based on the estimated values of \(\beta_0\) and \(\beta_1\) obtained in Step 1 and Step 2, the equation of the least squares line can be written as \(\hat{Y} = 7.277 - 0.3560* Dose\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Least Squares Method
The least squares method is a fundamental approach in statistical modeling used to determine the best-fitting line through a set of points. This method minimizes the sum of the squares of the differences (also known as residuals) between the observed values and the values predicted by the linear model.
It is particularly useful in simple linear regression, where the relationship between two variables is explored.The goal of the least squares method is to minimize the vertical deviations of each data point from the line, resulting in the line of best fit.
  • The formula for the line of best fit is \( \hat{Y} = \beta_0 + \beta_1X \).
  • \(\beta_0\) is the y-intercept, the predicted value of \(Y\) when \(X\) is zero.
  • \(\beta_1\) is the slope of the line, indicating the change in \(Y\) for a one-unit change in \(X\).
The least squares line reduces the error by calculating the line’s intercept and slope that lead to the smallest possible sum of squared deviations. This method is widely used because of its simplicity and effectiveness in predicting outcomes based on linear relationships.
Regression Analysis
Regression analysis is a statistical tool for examining the relationships between one dependent variable and one or more independent variables. It enables the prediction of the dependent variable's value based on the known values of independent variables.
There are different types of regression analysis, with linear regression being one of the simplest and most commonly used.The computer output provided in exercises such as this allows students to derive the equation of the least squares line. This formula is crucial for making predictions and understanding the dynamic between variables. Here’s how the specifics work:
  • The coefficients from the regression output, \(\beta_0\) and \(\beta_1\), represent the intercept and the slope of the regression line, respectively.
  • \(\beta_0\) shows where the line intercepts the \(Y\) axis, indicating the expected outcome when the independent variable is zero.
  • \(\beta_1\) describes the change in the dependent variable \(Y\) for each unit change in the independent variable.
Regression analysis can help identify trends, estimate relationships among variables, and predict future points, making it an invaluable tool in data-driven decision-making.
Statistical Modeling
Statistical modeling is a powerful technique used to simplify complex real-world situations with mathematical representations. It leverages statistical analysis to build a model that captures patterns within data using mathematical equations.
In the context of linear regression, statistical modeling allows us to represent the relationship between variables with a straight line. Such models help explain the variability in the data and make predictions about unseen data. As statistical models are built upon assumptions, it is crucial to validate these assumptions throughout the analysis:
  • First, it's assumed that there is a linear relationship between the dependent and independent variables.
  • The residuals (the differences between the observed and predicted values) should be normally distributed.
  • There should not be or only minimal multicollinearity, meaning the independent variables should not be too highly correlated.
Statistical modeling provides insight into the relationship and allows for accurate predictions, which are essential for scientific, economic, and industrial applications. The rigor in constructing and validating these models ensures that they can be relied upon for critical tasks.

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Most popular questions from this chapter

Data 9.1 on page 577 introduces the dataset InkjetPrinters, which includes information on all-in-one printers. Two of the variables are Price (the price of the printer in dollars) and CostColor (average cost per page in cents for printing in color). Computer output for predicting the price from the cost of printing in color is shown: $$ \begin{aligned} &\text { The regression equation is Price }=378-18.6 \text { CostColor }\\\ &\begin{array}{lrrrrr} \text { Analysis of Variance } & & & & \\ \text { Source } & \text { DF } & \text { SS } & \text { MS } & \text { F } & \text { P } \\ \text { Regression } & 1 & 57604 & 57604 & 13.19 & 0.002 \\ \text { Residual Error } & 18 & 78633 & 4369 & & \\ \text { Total } & 19 & 136237 & & & \end{array} \end{aligned} $$ (a) What is the predicted price of a printer that costs 10 cents a page for color printing? (b) According to the model, does it tend to cost more or less (per page) to do color printing on a cheaper printer? (c) Use the information in the ANOVA table to determine the number of printers included in the dataset. (d) Use the information in the ANOVA table to compute and interpret \(R^{2}\). (e) Is the linear model effective at predicting the price of a printer? Use information from the computer output and state the conclusion in context.

We give computer output with two regression intervals and information about the percent of calories eaten during the day. Interpret each of the intervals in the context of this data situation. (a) The \(95 \%\) confidence interval for the mean response (b) The \(95 \%\) prediction interval for the response The intervals given are for mice that eat \(10 \%\) of their calories during the day: DayPci 1.164 \(\begin{array}{rr}95 \% \mathrm{Cl} & 95 \% \mathrm{P} 1 \\\ (-0.013,4.783) & (-2.797,7.568)\end{array}\) 85 10.0 3888 2:

We show an ANOVA table for regression. State the hypotheses of the test, give the F-statistic and the p-value, and state the conclusion of the test. $$ \begin{array}{lrrrr} \text { Analysis of Variance } & & & & \\ \text { Source } & \text { DF } & \text { SS } & \text { MS } & \text { F } & \text { P } \\ \text { Regression } & 1 & 3396.8 & 3396.8 & 21.85 & 0.000 \\ \text { Residual Error } & 174 & 27053.7 & 155.5 & & \\ \text { Total } & 175 & 30450.5 & & & \end{array} $$

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