/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 87 In Exercises 6.87 to \(6.90,\) w... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercises 6.87 to \(6.90,\) what sample size is needed to give the desired margin of error in estimating a population mean with the indicated level of confidence? A margin of error within ±5 with \(95 \%\) confidence, assuming a previous sample had \(s=18\)

Short Answer

Expert verified
After substituting the values into the formula and evaluating, round up the resulting number to the nearest whole number to get the required sample size.

Step by step solution

01

Identifying the known variables.

From the problem, we can identify the following variables: The desired margin of error (E) is ±5, the standard deviation (s) from the previous sample is 18 and the level of confidence is \(95%\). For a \(95%\), the z-value (Z) we use is 1.96, since this value corresponds to the z-score for a \(95%\), from standard normal distribution tables.
02

Using the formula to calculate the sample size.

The formula for calculating the sample size needed to estimate a population mean within a certain margin of error E with a desired level of confidence Z is: \( n = \((\frac{Zs}{E})\) ^2 \). Plugging our known values into the formula, we get to the calculation step.
03

Performing the calculation.

Substitute the values into the formula: \( n = \((\frac{1.96 \times 18}{5})\)^2 \). After evaluating, make sure to round up, because the sample size cannot be a fraction.
04

Evaluating and rounding up the result

After performing the calculation, depending on the exact decimal obtained, remember to round up to the nearest whole number because sample size must be a whole number. The result will be the required sample size.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Margin of Error
The margin of error is a crucial component when estimating a population mean. In simple terms, it represents the maximum amount by which the estimated parameter may differ from the true population parameter. Let's imagine you have a dartboard, and the bulls-eye is the exact population mean. The margin of error tells you how big of a circle you can draw around your dartboard to account for unavoidable uncertainties.

Here's why it's important:
  • It helps express the precision of an estimate.
  • A smaller margin of error indicates a more precise estimate.
  • It's affected by the sample size — a larger sample results in a smaller margin of error.
    • To calculate the sample size needed to achieve a desired margin of error, we use the formula:\[ n = \left(\frac{Zs}{E}\right)^2 \] Where:- \( n \) = required sample size- \( Z \) = z-score associated with the desired level of confidence- \( s \) = standard deviation from the previous sample- \( E \) = desired margin of errorBy understanding how the margin of error works, you can ensure that your population mean estimate is as accurate as possible.
Confidence Interval
A confidence interval gives an estimated range of values which is likely to include an unknown population parameter, like the mean of a population. If you hear someone say they are 95% confident, they are using a confidence interval concept. What does it mean practically?
  • A 95% confidence interval means that if you were to take 100 different samples and compute a confidence interval for each, about 95 of them would contain the true population mean.
  • The width of the confidence interval depends on the margin of error.
  • Narrower confidence intervals indicate more precise estimates.
The relation between confidence intervals and sample size is vital too. As the sample size increases, the confidence interval tends to become narrower, making your estimate more precise. This happens because a larger sample size reduces variability and thus the margin of error. Hence, the confidence interval provides a range within which we can say, with a degree of confidence, the true value lies.
Population Mean Estimation
Estimating the population mean is a fundamental concept in statistics. It helps researchers and analysts infer about a whole population based on a sample. Why do we need it?
  • It allows us to make informed decisions without observing every individual in the population.
  • It's cost-effective and time-saving compared to examining the entire population.
When estimating a population mean, the sample size you choose is paramount. The sample must be sufficiently large to represent the population accurately. This is where our calculated formula for necessary sample size comes in, ensuring we have precise estimates without wastage of resources. Understanding the population mean and the methods used for estimation will provide a solid foundation in statistical analysis. It's like taking a picture where a larger sample ensures sharper, clearer images, giving a better depiction of the entire scene.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use StatKey or other technology to generate a bootstrap distribution of sample proportions and find the standard error for that distribution. Compare the result to the standard error given by the Central Limit Theorem, using the sample proportion as an estimate of the population proportion \(p\). Proportion of survey respondents who say exercise is important, with \(n=1000\) and \(\hat{p}=0.753\)

Use the t-distribution to find a confidence interval for a difference in means \(\mu_{1}-\mu_{2}\) given the relevant sample results. Give the best estimate for \(\mu_{1}-\mu_{2},\) the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed. A \(99 \%\) confidence interval for \(\mu_{1}-\mu_{2}\) using the sample results \(\bar{x}_{1}=501, s_{1}=115, n_{1}=400\) and \(\bar{x}_{2}=469, s_{2}=96, n_{2}=200 .\)

In Exercises 6.109 to 6.111 , we examine the effect of different inputs on determining the sample size needed. Find the sample size needed to give, with \(95 \%\) confidence, a margin of error within ±10 . Within ±5 . Within ±1 . Assume that we use \(\tilde{\sigma}=30\) as our estimate of the standard deviation in each case. Comment on the relationship between the sample size and the margin of error.

We examine the effect of different inputs on determining the sample size needed. Find the sample size needed to give a margin of error within ±3 with \(99 \%\) confidence. With \(95 \%\) confidence. With \(90 \%\) confidence. Assume that we use \(\tilde{\sigma}=30\) as our estimate of the standard deviation in each case. Comment on the relationship between the sample size and the confidence level desired.

\(\mathbf{6 . 2 2 0}\) Diet Cola and Calcium Exercise B.3 on page 349 introduces a study examining the effect of diet cola consumption on calcium levels in women. A sample of 16 healthy women aged 18 to 40 were randomly assigned to drink 24 ounces of either diet cola or water. Their urine was collected for three hours after ingestion of the beverage and calcium excretion (in \(\mathrm{mg}\) ) was measured. The summary statistics for diet cola are \(\bar{x}_{C}=56.0\) with \(s_{C}=4.93\) and \(n_{C}=8\) and the summary statistics for water are \(\bar{x}_{W}=49.1\) with \(s_{W}=3.64\) and \(n_{W}=8 .\) Figure 6.20 shows dotplots of the data values. Test whether there is evidence that diet cola leaches calcium out of the system, which would increase the amount of calcium in the urine for diet cola drinkers. In Exercise \(\mathrm{B} .3\), we used a randomization distribution to conduct this test. Use a t-distribution here, after first checking that the conditions are met and explaining your reasoning. The data are stored in ColaCalcium.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.