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91Ó°ÊÓ

When we want \(95 \%\) confidence and use the conservative estimate of \(p=0.5,\) we can use the simple formula \(n=1 /(M E)^{2}\) to estimate the sample size needed for a given margin of error ME. In Exercises 6.40 to 6.43, use this formula to determine the sample size needed for the given margin of error. A margin of error of 0.02 .

Short Answer

Expert verified
The sample size required for a margin of error of 0.02 is 2500.

Step by step solution

01

Identify the given values

The conservative estimate \(p\) is given as 0.5 (however, it is not needed in calculation). The margin of error \(ME\) is provided as 0.02.
02

Substitute the values into the formula

Substitute the values into the formula \(n=1 /(M E)^{2}\). So \(n = 1 /(0.02)^2\).
03

Carry out the calculation

Carry out the calculation which gives \(n = 2500\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval is a range of values that is used to estimate a population parameter. In simpler terms, it's like saying "we are X% sure that the true value lies somewhere between A and B." This range provides a way to express uncertainty about the measurement. Confidence intervals are constructed from sample data, providing an idea of how much doubt there is in our estimate of a true population parameter.

When we state a confidence interval, it is typically accompanied by a confidence level, often expressed as a percentage, like 95% or 99%, which tells us how sure we are that the interval contains the true value. For example, a 95% confidence interval for a survey result suggests we are 95% confident the true population mean falls within the interval.
  • Confidence Level: The proportion of times that the confidence interval would contain the true parameter if you repeated the study a large number of times.
  • Population Parameter: The measure of a characteristic in a population, like the average or proportion.
Confidence intervals are essential in statistics because they don't just give a single estimation but also show a range, highlighting the variability in data and helping researchers make informed decisions.
Margin of Error
The margin of error (ME) is a statistic expressing the amount of random sampling error in a survey's results. It tells us how much we should expect the sample percentage to deviate from the actual population percentage, acting almost like a buffer zone.The margin of error is crucial because it provides insight into the precision of our estimate. If the margin of error is small, our estimates are quite precise. Conversely, a large margin of error indicates less precision.
  • To determine the sample size needed for a given margin of error, we use the formula: \[ n = \frac{1}{(ME)^2} \]
  • A smaller margin of error requires a larger sample size and vice versa.
This makes understanding and calculating the margin of error fundamental when planning surveys or experiments, ensuring that the data collected will provide statistically reliable results.
Statistical Estimation
Statistical estimation involves using data from a sample to make estimates or predictions about a larger population. It's a core concept in statistics, playing an essential role in interpreting data and drawing conclusions. There are two main types of estimation:
  • Point Estimation: Provides a single value estimate of a population parameter (like a mean or proportion).
  • Interval Estimation: Provides a range of values, creating a confidence interval that likely contains the population parameter.
The examples often use formulas to calculate these estimates, ensuring they are as accurate as possible. For instance, statistical estimation helps determine the necessary sample size to achieve a reliable estimate with your desired level of confidence and margin of error. This aids researchers in collecting enough data to reflect the characteristics of the entire population accurately, thereby increasing the validity of the conclusions drawn from the data.

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Most popular questions from this chapter

Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4 if the samples have sizes \(n_{1}=30\) and \(n_{2}=40\)

A data collection method is described to investigate a difference in means. In each case, determine which data analysis method is more appropriate: paired data difference in means or difference in means with two separate groups. To study the effect of sitting with a laptop computer on one's lap on scrotal temperature, 29 men have their scrotal temperature tested before and then after sitting with a laptop for one hour.

(a) Find the relevant sample proportions in each group and the pooled proportion. (b) Complete the hypothesis test using the normal distribution and show all details. Test whether males are less likely than females to support a ballot initiative, if \(24 \%\) of a random sample of 50 males plan to vote yes on the initiative and \(32 \%\) of a random sample of 50 females plan to vote yes.

Using Data 5.1 on page \(375,\) we find a significant difference in the proportion of fruit flies surviving after 13 days between those eating organic potatoes and those eating conventional (not organic) potatoes. ask you to conduct a hypothesis test using additional data from this study. \(^{40}\) In every case, we are testing $$\begin{array}{ll}H_{0}: & p_{o}=p_{c} \\\H_{a}: & p_{o}>p_{c}\end{array}$$ where \(p_{o}\) and \(p_{c}\) represent the proportion of fruit flies alive at the end of the given time frame of those eating organic food and those eating conventional food, respectively. Also, in every case, we have \(n_{1}=n_{2}=500 .\) Show all remaining details in the test, using a \(5 \%\) significance level. Effect of Organic Raisins after 20 Days After 20 days, 275 of the 500 fruit flies eating organic raisins are still alive, while 170 of the 500 eating conventional raisins are still alive.

When we want \(95 \%\) confidence and use the conservative estimate of \(p=0.5,\) we can use the simple formula \(n=1 /(M E)^{2}\) to estimate the sample size needed for a given margin of error ME. In Exercises 6.40 to 6.43, use this formula to determine the sample size needed for the given margin of error. A margin of error of 0.01

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