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What Gives a Small P-value? In each case below, two sets of data are given for a two-tail difference in means test. In each case, which version gives a smaller \(\mathrm{p}\) -value relative to the other? (a) Both options have the same standard deviations and same sample sizes but: Option 1 has: \(\quad \bar{x}_{1}=25 \quad \bar{x}_{2}=23\) $$ \text { Option } 2 \text { has: } \quad \bar{x}_{1}=25 \quad \bar{x}_{2}=11 $$ (b) Both options have the same means \(\left(\bar{x}_{1}=22,\right.\) \(\left.\bar{x}_{2}=17\right)\) and same sample sizes but: Option 1 has: \(\quad s_{1}=15 \quad s_{2}=14\) $$ \text { Option } 2 \text { has: } \quad s_{1}=3 \quad s_{2}=4 $$ (c) Both options have the same means \(\left(\bar{x}_{1}=22,\right.\) \(\left.\bar{x}_{2}=17\right)\) and same standard deviations but: Option 1 has: \(\quad n_{1}=800 \quad n_{2}=1000\) $$ \text { Option } 2 \text { has: } \quad n_{1}=25 \quad n_{2}=30 $$

Short Answer

Expert verified
For each of the parts: (a) Option 2 will have a smaller p-value, (b) Option 2 will have a smaller p-value, and (c) Option 1 will have a smaller p-value.

Step by step solution

01

- Analyze the differences in means

In a two-tail difference of means test, a larger difference in sample means tend to produce smaller p-values. To see why, recall that a smaller p-value indicates stronger evidence against the null hypothesis, which in this case usually states that there's no difference between the means. So, a larger difference in means corresponds to a greater deviation from the null hypothesis, leading to smaller p-value. Therefore for part (a), Option 2 should produce a smaller p-value because the difference in means is larger than that of Option 1.
02

- Consider the effect of standard deviations

When the sample means and sizes are the same, a smaller standard deviation will result in a smaller p-value. This is because a smaller standard deviation indicates that the data points are closer to the mean, making the difference between the means appear more significant. That's why in part (b) Option 2 would have a smaller p-value. The standard deviations are smaller, so the difference in means will be more significant relative to the variability in the data.
03

- Evaluate the effect of sample sizes

Finally, larger sample sizes tend to produce smaller p-values. The reason is that having more data increases our ability to detect a difference where one exists. Hence, in part (c), Option 1 would have a smaller p-value because the sample sizes are much larger than those of Option 2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Two-Tail Difference in Means Test
In statistical analysis, a two-tail difference in means test is a common procedure to determine if there is a significant difference between the means of two populations. This type of test is called 'two-tail' because it considers extreme values—and thus potential significant differences—in both tails of the distribution curves.

When conducting such a test, the p-value is a crucial statistic. It offers evidence against the null hypothesis, which typically posits no difference between the two means. A smaller p-value signifies more substantial evidence against the null hypothesis. A larger difference between the means usually yields a smaller p-value since it suggests that the likelihood of such an extreme observed result occurring by chance is low. This concept was exemplified in part (a) of the exercise where Option 2, with a larger difference in means, should produce a smaller p-value.
Standard Deviation
Understanding standard deviation is critical as it measures the amount of variability or dispersion within a set of data values. In other words, it indicates the extent to which the individual data points in a dataset deviate from the mean. Within the context of a two-tail difference in means test, a smaller standard deviation suggests that the data points are tightly grouped around the mean, entailing less variability.

Why does this matter for p-values? Lower variability strengthens the statistical evidence for a difference in means when the sample means are the same, as observed in part (b) of the problem. In that scenario, Option 2 has smaller standard deviations, so the differences between the means appear more remarkable relative to the consistency of the data, thereby resulting in a smaller p-value.
Sample Size
Sample size plays a fundamental role in the validity of statistical tests. A larger sample size allows for more precise estimation of the population parameters and enhances the robustness of the statistical test's results. When comparing two means, increasing the sample size can detect even small differences between the means, thereby lowering the p-value, indicating more substantial evidence against the null hypothesis of no difference.

As applied in part (c) of the exercise, large sample sizes as in Option 1 (with hundreds of samples) versus smaller ones in Option 2 (with around two dozen samples each) can have a significant effect on p-values. The larger sizes in Option 1 reduce the impact of random variability, making it easier to identify true differences, thereby producing a smaller p-value compared to Option 2's smaller sample sizes.

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Most popular questions from this chapter

In Exercises 6.32 and 6.33, find a \(95 \%\) confidence interval for the proportion two ways: using StatKey or other technology and percentiles from a bootstrap distribution, and using the normal distribution and the formula for standard error. Compare the results. Proportion of home team wins in soccer, using \(\hat{p}=0.583\) with \(n=120\)

Do Babies Prefer Speech? Psychologists in Montreal and Toronto conducted a study to determine if babies show any preference for speech over general noise. \(^{61}\) Fifty infants between the ages of \(4-13\) months were exposed to both happy-sounding infant speech and a hummed lullaby by the same woman. Interest in each sound was measured by the amount of time the baby looked at the woman while she made noise. The mean difference in looking time was 27.79 more seconds when she was speaking, with a standard deviation of 63.18 seconds. Perform the appropriate test to determine if this is sufficient evidence to conclude that babies prefer actual speaking to humming.

Using Data 5.1 on page \(375,\) we find a significant difference in the proportion of fruit flies surviving after 13 days between those eating organic potatoes and those eating conventional (not organic) potatoes. ask you to conduct a hypothesis test using additional data from this study. \(^{40}\) In every case, we are testing $$\begin{array}{ll}H_{0}: & p_{o}=p_{c} \\\H_{a}: & p_{o}>p_{c}\end{array}$$ where \(p_{o}\) and \(p_{c}\) represent the proportion of fruit flies alive at the end of the given time frame of those eating organic food and those eating conventional food, respectively. Also, in every case, we have \(n_{1}=n_{2}=500 .\) Show all remaining details in the test, using a \(5 \%\) significance level. Effect of Organic Potatoes after 20 Days After 20 days, 250 of the 500 fruit flies eating organic potatoes are still alive, while 130 of the 500 eating conventional potatoes are still alive.

For each scenario, use the formula to find the standard error of the distribution of differences in sample means, \(\bar{x}_{1}-\bar{x}_{2}\) Samples of size 50 from Population 1 with mean 3.2 and standard deviation 1.7 and samples of size 50 from Population 2 with mean 2.8 and standard deviation 1.3

Use Stat Key or other technology to generate a bootstrap distribution of sample differences in means and find the standard error for that distribution. Compare the result to the standard error given by the Central Limit Theorem, using the sample standard deviations as estimates of the population standard deviations. Difference in mean commuting distance (in miles) between commuters in Atlanta and commuters in St. Louis, using \(n_{1}=500, \bar{x}_{1}=18.16,\) and \(s_{1}=13.80\) for Atlanta and \(n_{2}=500, \bar{x}_{2}=14.16,\) and \(s_{2}=10.75\) for St. Louis.

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