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A survey \(^{4}\) of 1060 randomly selected US teens ages 13 to 17 found that 605 of them say they have made a new friend online. (a) Find and interpret a \(90 \%\) confidence interval for the proportion, \(p\), of all US teens who have made a new friend online. (b) Give the best estimate for \(p\) and give the margin of error for the estimate. (c) Use the interval to determine whether we can be \(90 \%\) confident that more than half of US teens have made a new friend online.

Short Answer

Expert verified
The 90% confidence interval for the proportion of all US teens who have made a new friend online is between 55.05% and 59.1%. The best estimate for this proportion is 57.075% with a margin of error of 2.025 percentage points. Since the entire interval is above 50%, we can be 90% confident that more than half of all US teens have made a new friend online.

Step by step solution

01

Calculate sample proportion

First, calculate the population proportion (\(\hat{p}\)) by dividing the number of successes (605) by the total in the sample (1060) to get \(\hat{p}=\frac{605}{1060} = 0.57075\). This represents the best estimate for the proportion of US teens who have made a new friend online.
02

Find the z-value

Next, find the applicable z-value for a 90% confidence interval. This value can be found on a standard normal distribution table or calculated using a statistical calculator. The z-value for a two-sided 90% confidence interval is 1.645.
03

Calculate the confidence interval

Now, use the z-value, the calculated sample proportion and the given sample size to compute the confidence interval using the formula \[CI = \hat{p} \pm z*\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\] This gives: \[CI = 0.57075 \pm 1.645*\sqrt{\frac{0.57075*(1-0.57075)}{1060}}= (0.5505, 0.591)\] This is the 90% confidence interval for the true proportion of all US teens who have made a new friend online.
04

Calculate the margin of error

The margin of error is simply half the width of the confidence interval, which is the difference between the upper and lower limits divided by 2. In this case: \[ME = \frac{0.591 - 0.5505}{2}=0.02025\]
05

Interpret results

Interpreting these results, one can say that they are 90% confident that the actual proportion of US teens who have made a new friend online falls between 55.05% and 59.1%. The best estimate for this proportion is 57.075% with a margin of error of 2.025 percentage points. Since the entire interval is above 50%, we can be 90% confident that more than half of all US teens have made a new friend online.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
The sample proportion is a crucial element in statistical analysis, particularly when estimating population parameters. It provides an estimate of the true proportion within the entire population based on a smaller sample. In the provided exercise, the sample proportion is calculated by dividing the number of teenagers who have made a new friend online (605) by the total number of teens surveyed (1060). This calculation results in a sample proportion of approximately 0.57075, or 57.075%.

Understanding the sample proportion is essential because it serves as the foundation for further calculations, such as the confidence interval. It represents the "best guess" we have regarding the population parameter based on the available sample data. In practical terms, if similar research were conducted multiple times, we would see the sample proportion hover around this number, provided that the sample size and selection methods remain consistent.
Margin of Error
The margin of error is an important aspect when reporting a sample statistic like a proportion. It indicates the range within which the true population proportion is expected to lie. In this exercise, the margin of error is determined as part of the confidence interval calculation. Calculating the margin of error involves understanding the variability of the sample proportion and the confidence level you are working with.Here's how it is calculated:
  • Identify the desired confidence level, which in this case is 90%.
  • Obtain the z-value associated with that confidence level. For a 90% confidence interval, the z-value is 1.645.
  • Finally, apply the formula to get the margin of error: \[ME = z \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\]Using this formula, the exercise yields a margin of error of 0.02025 or 2.025 percentage points.

This value communicates that the true proportion is likely to be within 2.025% above or below our sample proportion of 57.075%. Thus, the margin of error quantifies the uncertainty inherent in the sample estimate of the population proportion.
Statistical Interpretation
Statistical interpretation involves making sense of the numbers derived from calculations within a real-world context. When we speak about the 90% confidence interval \(0.5505, 0.591\), we are saying that we have a degree of certainty (90%) that the true proportion of all U.S. teens who have made a new friend online falls within this range. This is not a guarantee but a confident estimate based on the sample data.

Importantly, the entire confidence interval being above 50% provides statistical evidence that more than half of the U.S. teens in the population make new friends online. The interpretation rests upon understanding that confidence intervals offer a range rather than a definitive statement. When analysts say they are "90% confident", they recognize a 10% chance that the population proportion might lie outside this interval.
  • This helps in decision-making and policy planning, as we can be reasonably assured of trends in the population based on robust sampling methods and statistical calculation.
  • Employing a confidence interval helps in communicating both the estimate and the uncertainty related to the sample proportion.
Ultimately, statistical interpretation links numerical results with the broader understanding of a phenomenon, offering insights that are grounded in empirical evidence.

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