/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 184 Assume the samples are random sa... [FREE SOLUTION] | 91影视

91影视

Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the endpoints of the t-distribution with \(2.5 \%\) beyond them in each tail if the samples have sizes \(n_{1}=15\) and \(n_{2}=25\).

Short Answer

Expert verified
The endpoints of the t-distribution with 2.5% beyond them in each tail when the sample sizes are \(n_{1}=15\) and \(n_{2}=25\) are approximately 卤2.024.

Step by step solution

01

Degrees of Freedom

The formula for degrees of freedom for a two-sample t-test when sample sizes are different and variance is assumed unequal is given as: \[ df = {(s_{1}^2/n_{1} + s_{2}^2/n_{2})^2 \over {(s_{1}^2/n_{1})^2/(n_{1}-1) + (s_{2}^2/n_{2})^2/(n_{2}-1)} } \] Where: \n \(s_{1}^2\) and \(s_{2}^2\) are the sample variances \n \(n_{1}\) and \(n_{2}\) are the sample sizes Since we don't have standard deviations here, we will use the simpler formula to calculate degrees of freedom which is: \[ df = n_{1} + n_{2} - 2 \] Substituting with given values, we get : \[ df = 15 + 25 - 2 = 38 \]
02

Calculating the t-distribution endpoints

The next step is to use a t-table or a t-distribution calculator to obtain the t-distribution values, accounting for the 2.5% in each tail. The t-distribution value that leaves 2.5% in each tail for 38 degrees of freedom is approximately 卤2.024.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees of Freedom
In statistical tests, degrees of freedom (df) are values that are free to vary when making calculations to estimate statistical parameters. In the context of a two-sample t-test, the degrees of freedom are crucial because they guide us in determining the t-distribution to be used. For a two-sample t-test where the sample sizes are different and variances are assumed unequal, you typically would use a complex formula to calculate df. However, a simplified approach is often used when assumptions can be made. For our scenario in the exercise, since it did not provide standard deviations, we adopted the simpler formula for unequal variances:
  • df = 苍鈧 + 苍鈧 - 2,
where 苍鈧 and 苍鈧 are sample sizes. Substituting the given values 苍鈧=15 and 苍鈧=25, we find that the degrees of freedom is 38. It's important to remember that the choice of using a simpler or more complex df formula depends on the data available.
T-Distribution
The t-distribution is a type of probability distribution that is symmetric and bell-shaped, similar to the normal distribution but with heavier tails. This means it has a higher probability for extreme values than a normal distribution. The t-distribution becomes crucial when dealing with small sample sizes or when the population standard deviation is unknown. To find the t-distribution values necessary for hypothesis testing, you often refer to a t-table or use a calculator. The t-distribution has certain critical values that correspond to specific confidence levels. In the exercise, we wanted t-distribution values with 2.5% beyond each tail for 38 degrees of freedom. For our context, this corresponds to approximately 卤2.024. This value essentially acts as a threshold to determine statistical significance when comparing sample means. This flexible nature of the t-distribution facilitates robust analysis in diverse datasets.
Sample Variance
Sample variance, a measure of the spread of sample data, represents how much individual data points deviate from the mean. It plays an important role in the computation of the statistical measure known as standard deviation. Variability in data is key to understanding the reliability of the mean of the dataset, with larger variances implying greater data dispersion and potentially less reliability in the mean.In our context of the two-sample t-test, knowing the sample variance is essential. It helps in calculating degrees of freedom more accurately using a more complex formula when variances are unknown or unequal. The more complex formula for degrees of freedom involves the sample variances:\[s_{1}^{2}, s_{2}^{2}\]These values are needed to understand the distribution of our data points. Sample variance directly influences the t-value through division by sample size, reflecting the text's emphasis on sound calculations for t-tests.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Gender Bias In a study \(^{52}\) examining gender bias, a nationwide sample of 127 science professors evaluated the application materials of an undergraduate student who had ostensibly applied for a laboratory manager position. All participants received the same materials, which were randomly assigned either the name of a male \(\left(n_{m}=63\right)\) or the name of a female \(\left(n_{f}=64\right) .\) Participants believed that they were giving feedback to the applicant, including what salary could be expected. The average salary recommended for the male applicant was \(\$ 30,238\) with a standard deviation of \(\$ 5152\) while the average salary recommended for the (identical) female applicant was \(\$ 26,508\) with a standard deviation of \(\$ 7348\). Does this provide evidence of a gender bias, in which applicants with male names are given higher recommended salaries than applicants with female names? Show all details of the test.

In Exercises 6.203 and \(6.204,\) use Stat Key or other technology to generate a bootstrap distribution of sample differences in means and find the standard error for that distribution. Compare the result to the standard error given by the Central Limit Theorem, using the sample standard deviations as estimates of the population standard deviations. Difference in mean commuting time (in minutes) between commuters in Atlanta and commuters in St. Louis, using \(n_{1}=500, \bar{x}_{1}=29.11,\) and \(s_{1}=20.72\) for Atlanta and \(n_{2}=500, \bar{x}_{2}=21.97,\) and \(s_{2}=14.23\) for St. Louis

Physician's Health Study In the Physician's Health Study, introduced in Data 1.6 on page 37 , 22,071 male physicians participated in a study to determine whether taking a daily low-dose aspirin reduced the risk of heart attacks. The men were randomly assigned to two groups and the study was double-blind. After five years, 104 of the 11,037 men taking a daily low-dose aspirin had had a heart attack while 189 of the 11,034 men taking a placebo had had a heart attack. \({ }^{39}\) Does taking a daily lowdose aspirin reduce the risk of heart attacks? Conduct the test, and, in addition, explain why we can infer a causal relationship from the results.

Does Red Increase Men's Attraction to Women? Exercise 1.99 on page 44 described a study \(^{46}\) which examines the impact of the color red on how attractive men perceive women to be. In the study, men were randomly divided into two groups and were asked to rate the attractiveness of women on a scale of 1 (not at all attractive) to 9 (extremely attractive). Men in one group were shown pictures of women on a white background while the men in the other group were shown the same pictures of women on a red background. The results are shown in Table 6.14 and the data for both groups are reasonably symmetric with no outliers. To determine the possible effect size of the red background over the white, find and interpret a \(90 \%\) confidence interval for the difference in mean attractiveness rating.

Use StatKey or other technology to generate a bootstrap distribution of sample proportions and find the standard error for that distribution. Compare the result to the standard error given by the Central Limit Theorem, using the sample proportion as an estimate of the population proportion \(p\). Proportion of survey respondents who say exercise is important, with \(n=1000\) and \(\hat{p}=0.753\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.