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91Ó°ÊÓ

If random samples of the given sizes are drawn from populations with the given proportions: (a) Find the standard error of the distribution of differences in sample proportions, \(\hat{p}_{A}-\hat{p}_{B}\) (b) Determine whether the sample sizes are large enough for the Central Limit Theorem to apply. Samples of size 50 from population \(A\) with proportion 0.70 and samples of size 75 from population \(B\) with proportion 0.60

Short Answer

Expert verified
The standard error of the distribution of differences in sample proportions, \(\hat{p}_{A}-\hat{p}_{B}\) can be found using the given formula, and the Central Limit Theorem can be applied if both \(n*p>5\) and \(n*(1-p)>5\) for both the samples.

Step by step solution

01

Determine the Variables

Identify the variables from the problem:\(n_A = 50\), \(p_A = 0.70\), \(n_B = 75\), \(p_B = 0.60\)
02

Calculate the Standard Error

The standard error for the distribution of differences in sample proportions, \(SE(\hat{p}_A - \hat{p}_B)\) is given by the formula: \[SE(\hat{p}_A - \hat{p}_B) = \sqrt{{p_A(1 - p_A)/n_A + p_B (1 - p_B) / n_B}}\]Substituting the given values into the formula, \[SE = \sqrt{{0.70(1 - 0.70)/50 + 0.60(1 - 0.60) / 75}}\]
03

Evaluate the Expression

Evaluate the expression inside the square root to obtain the standard error. This would require multiplying the terms inside the brackets, dividing by the respective sample sizes and adding the results.
04

Apply Central Limit Theorem Conditions

The Central Limit Theorem can be applied if the sample size is large enough, which generally means \(n*p>5\) and \(n*(1-p)>5\). Check these inequalities for both sample A and B.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Error of Sample Proportions
Understanding the standard error of sample proportions is key when dealing with statistics that involve comparing groups. This measure gives us insight into the variability one can expect when comparing sample proportions from two different populations. In the given exercise, to calculate the standard error of the difference in sample proportions, \( \hat{p}_{A} - \hat{p}_{B} \), we use the formula:
\[SE(\hat{p}_A - \hat{p}_B) = \sqrt{{p_A(1 - p_A)/n_A + p_B (1 - p_B) / n_B}}\]
Here, \( p_A \) and \( p_B \) are the sample proportions, and \( n_A \) and \( n_B \) are the sample sizes from the two different populations A and B, respectively. Once values are substituted and the mathematical operations are carried out, one obtains the standard error, which quantifies the average amount that the difference in sample proportions will deviate from the true difference in population proportions due to random sampling.

To put it simply, a smaller standard error indicates that the sample proportions are more likely to closely represent the true population proportions.
Distribution of Differences in Sample Proportions
When we compare sample proportions, like in this exercise, we're not just computing a single figure, but actually referring to a whole distribution of differences. This distribution tells us how the sample proportions from two populations could vary from one another by mere chance. The Central Limit Theorem (CLT) assures us that, provided certain conditions are met, this distribution will approximate the normal distribution, regardless of the underlying population's distribution.
In practical terms, having a normally distributed set of differences allows us to make inferences about the population using the familiar properties of the normal curve, such as confidence intervals and hypothesis testing. The calculation of the standard error, which we previously discussed, is a fundamental step in evaluating this distribution and hence in making reliable conclusions about the populations from our samples.
Sample Size Criteria for CLT
Applying the Central Limit Theorem (CLT) hinges on having a large enough sample size. This 'large enough' condition is typically quantified by a set of criteria that the sample must satisfy. Generally, these criteria are that each possible outcome of an event must occur more than a certain number of times on average for the theorem to apply. A commonly used rule of thumb is that both \( n*p \) and \( n*(1-p) \) must be greater than 5.
For our given problem, this means checking if \( n_A*p_A \) and \( n_A*(1-p_A) \) for population A, and similarly \( n_B*p_B \) and \( n_B*(1-p_B) \) for population B, are greater than 5. If these conditions are met for both samples, the CLT can be used, and we can proceed with confidence knowing the sampling distribution of the sample proportions will be approximately normal. This approximation allows for the practical application of statistical tests and intervals to make inferences about the population parameters from our sample statistics.

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Most popular questions from this chapter

Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution above 2.1 if the samples have sizes \(n_{1}=12\) and \(n_{2}=12\).

Plastic microparticles are contaminating the world's shorelines (see Exercise 6.108\()\), and much of this pollution appears to come from fibers from washing polyester clothes. \({ }^{27}\) The worst offender appears to be fleece, and a recent study found that the mean number of polyester fibers discharged into wastewater from washing fleece was 290 fibers per liter of wastewater, with a standard deviation of 87.6 and a sample size of 120 . (a) Find and interpret a \(99 \%\) confidence interval for the mean number of polyester microfibers per liter of wastewater when washing fleece. (b) What is the margin of error? (c) If we want a margin of error of only ±5 with \(99 \%\) confidence, what sample size is needed?

For each scenario, use the formula to find the standard error of the distribution of differences in sample means, \(\bar{x}_{1}-\bar{x}_{2}\) Samples of size 100 from Population 1 with mean 87 and standard deviation 12 and samples of size 80 from Population 2 with mean 81 and standard deviation 15

Use Stat Key or other technology to generate a bootstrap distribution of sample differences in means and find the standard error for that distribution. Compare the result to the standard error given by the Central Limit Theorem, using the sample standard deviations as estimates of the population standard deviations. Difference in mean commuting distance (in miles) between commuters in Atlanta and commuters in St. Louis, using \(n_{1}=500, \bar{x}_{1}=18.16,\) and \(s_{1}=13.80\) for Atlanta and \(n_{2}=500, \bar{x}_{2}=14.16,\) and \(s_{2}=10.75\) for St. Louis.

Using Data 5.1 on page \(375,\) we find a significant difference in the proportion of fruit flies surviving after 13 days between those eating organic potatoes and those eating conventional (not organic) potatoes. Exercises 6.166 to 6.169 ask you to conduct a hypothesis test using additional data from this study. \(^{40}\) In every case, we are testing $$\begin{array}{ll}H_{0}: & p_{o}=p_{c} \\\H_{a}: & p_{o}>p_{c}\end{array}$$ where \(p_{o}\) and \(p_{c}\) represent the proportion of fruit flies alive at the end of the given time frame of those eating organic food and those eating conventional food, respectively. Also, in every case, we have \(n_{1}=n_{2}=500 .\) Show all remaining details in the test, using a \(5 \%\) significance level. Effect of Organic Raisins after 15 Days After 15 days, 320 of the 500 fruit flies eating organic raisins are still alive, while 300 of the 500 eating conventional raisins are still alive.

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