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Give null and alternative hypotheses for a population proportion, as well as sample results. Use StatKey or other technology to generate a randomization distribution and calculate a p-value. StatKey tip: Use "Test for a Single Proportion" and then "Edit Data" to enter the sample information. Hypotheses: \(H_{0}: p=0.5\) vs \(H_{a}: p \neq 0.5\) Sample data: \(\hat{p}=42 / 100=0.42\) with \(n=100\)

Short Answer

Expert verified
Given a null hypothesis \(H_{0}: p = 0.5\) and alternative hypothesis \(H_{a}: p \neq 0.5\). The sample data is \(\hat{p} = 0.42\) and \(n = 100\). The randomization distribution is obtained, and a p-value can be calculated using StatKey or other technology. Note: The computed p-value will depend on the simulated results from the randomization distribution.

Step by step solution

01

Construct Hypotheses

For hypothesis testing of a population proportion, there are two types of hypotheses: a null hypothesis \(H_{0}\) and an alternative hypothesis \(H_{a}\). The null hypothesis is the statement being tested, usually representing no effect or status quo. The alternative hypothesis is the statement that we'll accept if the data provide strong enough evidence against the null hypothesis. Given:Null hypothesis (H_0): \(p = 0.5\) Alternative hypothesis (H_a): \(p \neq 0.5\)
02

Provide Sample Data

The sample data consist of the observed sample proportion \(\hat{p}\) and the sample size \(n\). Given:Sample Proportion (\(\hat{p}\)): 42/100 = 0.42 (meaning 42% of observations)Sample Size (\(n\)): 100
03

Generate Randomization Distribution & Calculate the P-value Using StatKey

StatKey (or a similar statistical tool) should be used to create a randomization distribution and calculate the p-value for the situation. In StatKey, choose 'Test for a Single Proportion', and use 'Edit Data' to input the sample information. The randomization distribution will generate many scenarios (e.g., 5000 scenarios) under the null hypothesis, showing the proportion of successes in the sample size. This will allow us to see the number of scenarios out of the total that have a proportion of successes as extreme or more extreme than what was observed. The p-value will be calculated as \(P-value = \frac{\text{Number of Scenarios as Extreme or More Extreme than Observed}}{\text{Total Number of Scenarios}}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
The null hypothesis, denoted as \(H_{0}\), is a statement in hypothesis testing that implies no effect or no difference. It is the default or status quo condition that a researcher aims to test against experimental data. In the context of testing a population proportion, the null hypothesis might suggest that the proportion of a characteristic within a population is equal to a specific value. For example, if we want to test whether a coin is fair, we could set our null hypothesis as \(H_{0}: p = 0.5\), which states that the probability (proportion) of getting heads is 50%.
When we conduct hypothesis testing, we are essentially looking for evidence that can lead us to reject the null hypothesis. The absence of such evidence means that we do not have enough reason to doubt the null condition, and thus, we fail to reject the null hypothesis.
Alternative Hypothesis
In contrast to the null hypothesis, the alternative hypothesis, denoted as \(H_{a}\) or \(H_{1}\), represents what a researcher wants to prove. It is the assertion that there is an effect or a difference, contrasting the null hypothesis's claim. Going back to our coin example, if we suspect the coin to be biased, the alternative hypothesis might be expressed as \(H_{a}: p eq 0.5\).
This means we believe that the probability of obtaining heads is not 50%. The alternative hypothesis could be one-sided or two-sided, indicating whether we are looking for evidence of a specific direction of the effect or any significant effect in either direction.
Population Proportion
The population proportion, denoted as \(p\), refers to the percentage of a specific characteristic within a whole population. It's what we aim to estimate or make inferences about through hypothesis testing.
For instance, if we're exploring the proportion of left-handed individuals in a certain country, \(p\) would represent the true proportion of left-handers in the entire population. Obtaining an exact value for \(p\) is often impractical due to the large size of populations, so we estimate it using sample proportions from smaller, representative groups.
P-Value Calculation
The p-value is a crucial concept in hypothesis testing. It represents the probability of obtaining a sample result at least as extreme as the one observed, assuming that the null hypothesis is true. A lower p-value suggests that the observed data are unlikely under the null hypothesis and thus provide evidence against it.
To calculate the p-value, we compare our observed sample proportion to a distribution of sample proportions we would expect to see if the null hypothesis were true, known as the randomization distribution. The calculation can be expressed as \( P-value = \frac{\text{Number of Scenarios as Extreme or More Extreme than Observed}}{\text{Total Number of Scenarios}} \). Generally, a p-value lower than a predetermined significance level (commonly 0.05) means that we reject the null hypothesis.
Randomization Distribution
A randomization distribution is a probability distribution that represents the possible outcomes for a statistic if the null hypothesis were true. It's constructed by taking a sample statistic and repeatedly simulating random sampling from the population under the null hypothesis conditions.
For example, if our null hypothesis states that the true population proportion is 0.5, we create a randomization distribution by simulating many random samples (e.g., flipping a coin) and recording the proportion in each sample. This distribution helps us understand how unusual our observed sample proportion is within the context of the null hypothesis.
Sample Proportion
The sample proportion, denoted as \(\hat{p}\), is the percentage of a characteristic within a sample drawn from a population. It serves as an estimate of the true population proportion. In the given exercise, the sample proportion is \(\hat{p} = 42/100 = 0.42\), meaning in a sample of 100 people, 42% have the characteristic being tested.
Obtaining the sample proportion is a critical step in hypothesis testing as it provides the observed value to be compared against the expected outcomes under the null hypothesis. It is the basis for deciding whether the provided data can refute the null hypothesis.
StatKey Software
StatKey is a software tool specifically designed to facilitate teaching and learning statistics. It provides users with a simplified interface to conduct various statistical analyses, including hypothesis tests for population proportions. Using ‘Test for a Single Proportion’ and ‘Edit Data’ features, students can easily input their sample information and simulate randomization distributions for their hypothesis tests.
It serves as a valuable educational resource as it allows students to visualize the randomization distribution, compute p-values, and understand the concepts of statistical inference in a hands-on manner. For instructors and learners, such tools make the process of learning statistics more interactive and grounded in practical experience.

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Most popular questions from this chapter

Weight Loss Program Suppose that a weight loss company advertises that people using its program lose an average of 8 pounds the first month, and that the Federal Trade Commission (the main government agency responsible for truth in advertising) is gathering evidence to see if this advertising claim is accurate. If the FTC finds evidence that the average is less than 8 pounds, the agency will file a lawsuit against the company for false advertising. (a) What are the null and alternative hypotheses the FTC should use? (b) Suppose that the FTC gathers information from a very large random sample of patrons and finds that the average weight loss during the first month in the program is \(\bar{x}=7.9\) pounds with a p-value for this result of \(0.006 .\) What is the conclusion of the test? Are the results statistically significant? (c) Do you think the results of the test are practically significant? In other words, do you think patrons of the weight loss program will care that the average is 7.9 pounds lost rather than 8.0 pounds lost? Discuss the difference between practical significance and statistical significance in this context.

It is believed that sunlight offers some protection against multiple sclerosis (MS) since the disease is rare near the equator and more prevalent at high latitudes. What is it about sunlight that offers this protection? To find out, researchers \({ }^{23}\) injected mice with proteins that induce a condition in mice comparable to MS in humans. The control mice got only the injection, while a second group of mice were exposed to UV light before and after the injection, and a third group of mice received vitamin D supplements before and after the injection. In the test comparing UV light to the control group, evidence was found that the mice exposed to UV suppressed the MS-like disease significantly better than the control mice. In the test comparing mice getting vitamin D supplements to the control group, the mice given the vitamin D did not fare significantly better than the control group. If the p-values for the two tests are 0.472 and 0.002 , which p-value goes with which test?

A study \(^{20}\) conducted in June 2015 examines ownership of tablet computers by US adults. A random sample of 959 people were surveyed, and we are told that 197 of the 455 men own a tablet and 235 of the 504 women own a tablet. We want to test whether the survey results provide evidence of a difference in the proportion owning a tablet between men and women. (a) State the null and alternative hypotheses, and define the parameters. (b) Give the notation and value of the sample statistic. In the sample, which group has higher tablet ownership: men or women? (c) Use StatKey or other technology to find the pvalue.

Give null and alternative hypotheses for a population proportion, as well as sample results. Use StatKey or other technology to generate a randomization distribution and calculate a p-value. StatKey tip: Use "Test for a Single Proportion" and then "Edit Data" to enter the sample information. Hypotheses: \(H_{0}: p=0.6\) vs \(H_{a}: p>0.6\) Sample data: \(\hat{p}=52 / 80=0.65\) with \(n=80\)

A confidence interval for a sample is given, followed by several hypotheses to test using that sample. In each case, use the confidence interval to give a conclusion of the test (if possible) and also state the significance level you are using. A \(99 \%\) confidence interval for \(\mu: 134\) to 161 (a) \(H_{0}: \mu=100\) vs \(H_{a}: \mu \neq 100\) (b) \(H_{0}: \mu=150 \mathrm{vs} H_{a}: \mu \neq 150\) (c) \(H_{0}: \mu=200\) vs \(H_{a}: \mu \neq 200\)

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