/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 106 In Exercise 4.16 on page 268 , w... [FREE SOLUTION] | 91Ó°ÊÓ

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In Exercise 4.16 on page 268 , we describe an observational study investigating a possible relationship between exposure to organophosphate pesticides as measured in urinary metabolites (DAP) and diagnosis of ADHD (attention-deficit/hyperactivity disorder). In reporting the results of this study, the authors \(^{28}\) make the following statements: \- "The threshold for statistical significance was set at \(P<.05 . "\) \- "The odds of meeting the \(\ldots\) criteria for \(\mathrm{ADHD}\) increased with the urinary concentrations of total DAP metabolites" \- "The association was statistically significant." (a) What can we conclude about the p-value obtained in analyzing the data? (b) Based on these statements, can we distinguish whether the evidence of association is very strong vs moderately strong? Why or why not? (c) Can we conclude that exposure to pesticides is related to the likelihood of an ADHD diagnosis? (d) Can we conclude that exposure to pesticides causes more cases of ADHD? Why or why not?

Short Answer

Expert verified
(a) The p-value obtained is less than 0.05 meaning that the data observed is statistically significant.\n(b) No, we can't distinguish if the evidence of association is very strong or moderately strong based solely on p-value and these statements.\n(c) Yes, there seems to be a relation between exposure to pesticides and likelihood of an ADHD diagnosis, according to this study. However, this doesn't establish causation.\n(d) No, we can't conclude that exposure to pesticides directly causes more cases of ADHD based on this observational study.

Step by step solution

01

Understanding p-value

The p-value as per the report is less than 0.05, which means the results are statistically significant. If a p-value is less than the significance level (which is 0.05 in this case), it indicates that the probability of observing the data given there is no true effect or relationship is quite low.
02

Evaluating Strength of Evidence

The strength of the evidence cannot be determined solely based on the p-value. The p-value does not provide a measure of the strength or magnitude of the effect. Therefore, we cannot distinguish whether the evidence of association is very strong or moderately strong just by these statements.
03

Pesticide Exposure and ADHD Diagnosis

Since the study found a statistically significant association between the exposure to pesticides and the diagnosis of ADHD, it can be concluded that there appears to be a relationship between these variables. This, however, does not establish causality and might be due to confounding variables.
04

Identifying Causal Relationship

The statements provided do not provide enough evidence to conclude that exposure to pesticides directly causes more cases of ADHD. This is an observational study and as such can't establish causation. It may identify that exposure to pesticides is associated with an increase in ADHD diagnoses, but other factors could also be contributing that weren't accounted for in this study.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

P-value Interpretation
Understanding the p-value is crucial when interpreting study results. The p-value tells us the probability of observing the data we have—or something more extreme—if there truly was no effect or association. In the study about pesticide exposure and ADHD, a p-value less than 0.05 is deemed statistically significant. This means that if the pesticide exposure had no real effect on ADHD occurrence, the likelihood of observing the data obtained is less than 5%.

However, a common misconception is to equate statistical significance with practical importance. A small p-value does not necessarily mean the effect is large or important; it merely suggests that the observed association is unlikely to have occurred by random chance alone. Thus, while the p-value can guide us in rejecting the null hypothesis, it does not quantify the strength of the association or its practical significance.
Pesticide Exposure and ADHD
The relationship between pesticide exposure and ADHD is a concern that scientists have been exploring. The mentioned observational study sought to explore this relationship by examining the levels of urinary metabolites of organophosphate pesticides (DAP) and their association with ADHD. While the study concluded a significant association, meaning those with higher DAP levels were more likely to be diagnosed with ADHD, this does not imply all factors were accounted for.

Observational studies, unlike randomized controlled trials, cannot completely control for confounding variables—factors that might influence the outcome aside from the variable of interest. Consequently, while there seems to be an association between pesticide exposure and ADHD, it's essential to consider other potential factors like genetics or environmental influences that could also explain the increase in ADHD diagnoses.
Evidence Strength in Statistics
The strength of statistical evidence refers to how convincingly data support a conclusion. However, contrary to what one might assume, the p-value alone does not measure this strength. It is critical to understand that p-values can be influenced by the size of the effect and the sample size. In research reports, we look for confidence intervals or effect sizes to better understand the magnitude of the association.

Unfortunately, the singular statements 'statistically significant' and the threshold of p < 0.05 don't provide us with information about the confidence intervals or effect sizes. It is, therefore, impossible to determine if the evidence of the association between pesticide exposure and ADHD is very strong or moderately strong without further information. This highlight underscores why a comprehensive analysis of study results should look beyond p-values to include other metrics that provide a fuller picture of the data.
Causal Relationships in Research
Establishing causal relationships in research is a challenging endeavor, prominently so in observational studies where variables are not manipulated. The conclusion that pesticide exposure leads to an increase in ADHD diagnoses requires careful consideration. This type of study can show associations, meaning the two variables move together in some way, but that does not necessarily mean one causes the other.

To claim causality, researchers look for evidence meeting several criteria, including temporality, strength, consistency, plausibility, and consideration of alternative explanations. Causality is more confidently asserted in experimental studies, where random assignment and control over variables help rule out alternative explanations. In the case of the reported study on ADHD and pesticides, while there is an association, due to the study design, we cannot definitively state that pesticide exposure causes ADHD without additional research, possibly through longitudinal studies or controlled experiments.

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Most popular questions from this chapter

Translating Information to Other Significance Levels Suppose in a two-tailed test of \(H_{0}: \rho=0\) vs \(H_{a}: \rho \neq 0,\) we reject \(H_{0}\) when using a \(5 \%\) significance level. Which of the conclusions below (if any) would also definitely be valid for the same data? Explain your reasoning in each case. (a) Reject \(H_{0}: \rho=0\) in favor of \(H_{a}: \rho \neq 0\) at a \(1 \%\) significance level. (b) Reject \(H_{0}: \rho=0\) in favor of \(H_{a}: \rho \neq 0\) at a \(10 \%\) significance level. (c) Reject \(H_{0}: \rho=0\) in favor of the one-tail alternative, \(H_{a}: \rho>0,\) at a \(5 \%\) significance level, assuming the sample correlation is positive.

For each situation described, indicate whether it makes more sense to use a relatively large significance level (such as \(\alpha=0.10\) ) or a relatively small significance level (such as \(\alpha=0.01\) ). A pharmaceutical company is testing to see whether its new drug is significantly better than the existing drug on the market. It is more expensive than the existing drug. Which significance level would the company prefer? Which significance level would the consumer prefer?

Figure 4.25 shows a scatterplot of the acidity (pH) for a sample of \(n=53\) Florida lakes vs the average mercury level (ppm) found in fish taken from each lake. The full dataset is introduced in Data 2.4 on page 71 and is available in FloridaLakes. There appears to be a negative trend in the scatterplot, and we wish to test whether there is significant evidence of a negative association between \(\mathrm{pH}\) and mercury levels. (a) What are the null and alternative hypotheses? (b) For these data, a statistical software package produces the following output: $$ r=-0.575 \quad p \text { -value }=0.000017 $$ Use the p-value to give the conclusion of the test. Include an assessment of the strength of the evidence and state your result in terms of rejecting or failing to reject \(H_{0}\) and in terms of \(\mathrm{pH}\) and mercury. (c) Is this convincing evidence that low \(\mathrm{pH}\) causes the average mercury level in fish to increase? Why or why not?

Mating Choice and Offspring Fitness Does the ability to choose a mate improve offspring fitness in fruit flies? Researchers have studied this by taking female fruit flies and randomly dividing them into two groups; one group is put into a cage with a large number of males and able to freely choose who to mate with, while flies in the other group are each put into individual vials, each with only one male, giving no choice in who to mate with. Females are then put into egg laying chambers, and a certain number of larvae collected. Do the larvae from the mate choice group exhibit higher survival rates? A study \(^{44}\) published in Nature found that mate choice does increase offspring fitness in fruit flies (with p-value \(<0.02\) ), yet this result went against conventional wisdom in genetics and was quite controversial. Researchers attempted to replicate this result with a series of related experiments, \({ }^{45}\) with data provided in MateChoice. (a) In the first replication experiment, using the same species of fruit fly as the original Nature study, 6067 of the 10000 larvae from the mate choice group survived and 5976 of the 10000 larvae from the no mate choice group survived. Calculate the p-value. (b) Using a significance level of \(\alpha=0.05\) and \(\mathrm{p}\) -value from (a), state the conclusion in context. (c) Actually, the 10,000 larvae in each group came from a series of 50 different runs of the experiment, with 200 larvae in each group for each run. The researchers believe that conditions dif- fer from run to run, and thus it makes sense to treat each \(\mathrm{run}\) as a case (rather than each fly). In this analysis, we are looking at paired data, and the response variable would be the difference in the number of larvae surviving between the choice group and the no choice group, for each of the 50 runs. The counts (Choice and NoChoice and difference (Choice \(-\) NoChoice) in number of surviving larva are stored in MateChoice. Using the single variable of differences, calculate the p-value for testing whether the average difference is greater than \(0 .\) (Hint: this is a single quantitative variable, so the corresponding test would be for a single mean.) (d) Using a significance level of \(\alpha=0.05\) and the p-value from (c), state the conclusion in context. (e) The experiment being tested in parts (a)-(d) was designed to mimic the experiment from the original study, yet the original study yielded significant results while this study did not. If mate choice really does improve offspring fitness in fruit flies, did the follow-up study being analyzed in parts (a)-(d) make a Type I, Type II, or no error? (f) If mate choice really does not improve offspring fitness in fruit flies, did the original Nature study make a Type I, Type II, or no error?

The same sample statistic is used to test a hypothesis, using different sample sizes. In each case, use StatKey or other technology to find the p-value and indicate whether the results are significant at a \(5 \%\) level. Which sample size provides the strongest evidence for the alternative hypothesis? Testing \(H_{0}: p=0.5\) vs \(H_{a}: p>0.5\) using \(\hat{p}=0.58\) with each of the following sample sizes: (a) \(\hat{p}=29 / 50=0.58\) (b) \(\hat{p}=290 / 500=0.58\)

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