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Exercises 3.96 to 3.101 use data from a study designed to examine the effect of doing synchronized movements (such as marching in step or doing synchronized dance steps) and the effect of exertion on many different variables, such as pain tolerance and attitudes toward others. In the study, 264 high school students in Brazil were randomly assigned to one of four groups reflecting whether or not movements were synchronized (Synch= yes or no) and level of activity (Exertion= high or low). \(^{49}\) Participants rated how close they felt to others in their group both before (CloseBefore) and after (CloseAfter) the activity, using a 7-point scale (1=least close to \(7=\) most close ). Participants also had their pain tolerance measured using pressure from a blood pressure cuff, by indicating when the pressure became too uncomfortable (up to a maximum pressure of \(300 \mathrm{mmHg}\) ). Higher numbers for this Pain Tolerance measure indicate higher pain tolerance. The full dataset is available in SynchronizedMovement. For each of the following problems: (a) Give notation for the quantity we are estimating, and define any relevant parameters. (b) Use StatKey or other technology to find the value of the sample statistic. Give the correct notation with your answer. (c) Use StatKey or other technology to find the standard error for the estimate. (d) Use the standard error to give a \(95 \%\) confidence interval for the quantity we are estimating. (e) Interpret the confidence interval in context. How Close Do You Feel to Others? Use the closeness ratings before the activity (CloseBefore) to estimate the mean closeness rating one person would assign to others in a group.

Short Answer

Expert verified
The quantity we are estimating, denoted by \( µ_{CB} \), is the mean closeness rating a person would assign to others in a group before the activity. The value of the sample statistic (sample mean) and the standard error can be calculated using the statistical software. A 95% confidence interval for this quantity is calculated using the sample mean and standard error. The interpretation of the confidence interval is that we can be 95% confident that the true mean closeness rating falls within this interval.

Step by step solution

01

Identifying the Quantity and Parameters

We are trying to estimate the mean closeness rating that a person would assign to others in a group before doing synchronized movement or any activity. Thus, we denote the quantity we are estimating as \( µ_{CB} \), where 'CB' represents 'CloseBefore' referring to the closeness measure before the activity. 'µ' represents the mean value we are trying to estimate.
02

Finding the Value of Sample Statistic

Using the given dataset in the statistical software (like StatKey), we need to find the mean value of the 'CloseBefore' ratings. It gives us the sample mean which is represented as \( \bar{x}_{CB} \). This is our sample statistic.
03

Calculating Standard Error for the Estimate

The standard error for the estimate can be calculated using the software too. It can be done by finding the standard deviation of the 'CloseBefore' ratings and dividing it by the square root of the number of observations. This value represents the standard error (SE) and it measures the accuracy of our estimate.
04

Constructing a Confidence Interval

A 95% confidence interval for the quantity we are estimating can be calculated using the formula: \[ \bar{x}_{CB} \pm 1.96 * SE \] where \( \bar{x}_{CB} \) is the sample mean, SE is the standard error, 1.96 is the z-score for a 95% confidence interval. This interval gives us a range in which we can be 95% confident that the true population mean falls in.
05

Interpretation of Confidence Interval

The interpretation of the confidence interval is in the context of the problem. It means that we can be 95% confident that the true mean closeness rating that one person would assign to others in a group before activity falls within the calculated interval.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Standard Error
Standard error (SE) is a crucial concept in statistics that helps in understanding the reliability and accuracy of a sample mean as an estimate of the true population mean. It essentially measures the extent to which the sample mean might vary from the actual population mean.
To calculate the standard error, one needs to determine the standard deviation of the sample and then divide it by the square root of the sample size. The formula is given by:
  • \[SE = \frac{s}{\sqrt{n}}\]
The smaller the standard error, the more precise the estimate of the population mean. This is because smaller SE values indicate less variation among the sample means that would be obtained if we took multiple samples from the population.
When you encounter a standard error value, it helps quantify the uncertainty associated with the sample mean. A high SE value suggests more variability which might lead to a wider confidence interval. Conversely, a low SE value typically results in a narrow confidence interval.
Sample Statistic: Mean of 'CloseBefore' Ratings
A sample statistic is a single measure, derived from sample data, which is used to estimate a population parameter. In this study, the sample statistic of interest is the mean of 'CloseBefore' ratings, denoted as \( \bar{x}_{CB} \).
This mean provides an average rating that high school students used to quantify how close they felt to their peers before engaging in synchronized movements.
To obtain this sample mean, you would compile all the 'CloseBefore' ratings from the collected data and calculate their average. This simple arithmetic mean serves as the sample statistic that estimates the true population mean (\( µ_{CB} \)).
Understanding the sample statistic is essential because it offers a base from which other calculations, like the standard error and confidence interval, are derived. It reflects the central tendency of your data and provides a summary measure that is easy to interpret.
Estimating the Mean with Confidence
Mean estimation is a statistical process for using sample data to make inferences about the population mean. In this problem, the goal is to estimate the mean closeness rating \( µ_{CB} \), representing how close students feel to each other before an activity.
The main tool used in this estimation is the confidence interval, which offers a range of values that likely encompass the true population mean. For a 95% confidence level, the general formula is:
  • \[ \bar{x}_{CB} \pm 1.96 \times SE \]
This formula uses the sample mean (\( \bar{x}_{CB} \)) and the calculated standard error (SE). The constant 1.96 is a z-score value corresponding to a 95% confidence level, signifying that if the study were repeated many times, 95% of the calculated intervals would contain the true population mean.
Estimating the mean through a confidence interval not only provides a specific range but also expresses the degree of uncertainty associated with the estimate. It's a foundational concept in inferential statistics that helps researchers understand the precision of their sample estimates.

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Most popular questions from this chapter

In estimating the mean score on a fitness exam, we use an original sample of size \(n=30\) and a bootstrap distribution containing 5000 bootstrap samples to obtain a \(95 \%\) confidence interval of 67 to \(73 .\) In Exercises 3.106 to 3.111 , a change in this process is described. If all else stays the same, which of the following confidence intervals \((A, B,\) or \(C)\) is the most likely result after the change: \(\begin{array}{ll}A .66 \text { to } 74 & B .67 \text { to } 73\end{array}\) C. 67.5 to 72.5 Using 1000 bootstrap samples for the distribution.

Use data from a study designed to examine the effect of doing synchronized movements (such as marching in step or doing synchronized dance steps) and the effect of exertion on many different variables, such as pain tolerance and attitudes toward others. In the study, 264 high school students in Brazil were randomly assigned to one of four groups reflecting whether or not movements were synchronized (Synch= yes or no) and level of activity (Exertion= high or low). \(^{49}\) Participants rated how close they felt to others in their group both before (CloseBefore) and after (CloseAfter) the activity, using a 7-point scale (1=least close to \(7=\) most close ). Participants also had their pain tolerance measured using pressure from a blood pressure cuff, by indicating when the pressure became too uncomfortable (up to a maximum pressure of \(300 \mathrm{mmHg}\) ). Higher numbers for this Pain Tolerance measure indicate higher pain tolerance. The full dataset is available in SynchronizedMovement. For each of the following problems: (a) Give notation for the quantity we are estimating, and define any relevant parameters. (b) Use StatKey or other technology to find the value of the sample statistic. Give the correct notation with your answer. (c) Use StatKey or other technology to find the standard error for the estimate. (d) Use the standard error to give a \(95 \%\) confidence interval for the quantity we are estimating. (e) Interpret the confidence interval in context. Does Synchronization Boost Pain Tolerance? Use the pain tolerance ratings ( PainTolerance) after the activity to estimate the difference in mean pain tolerance between those who just completed a synchronized activity and those who did a nonsynchronized activity.

Small Sample Size and Outliers As we have seen, bootstrap distributions are generally symmetric and bell-shaped and centered at the value of the original sample statistic. However, strange things can happen when the sample size is small and there is an outlier present. Use StatKey or other technology to create a bootstrap distribution for the standard deviation based on the following data: \(8 \quad 10\) 72 \(13 \quad 8\) \(\begin{array}{ll}10 & 50\end{array}\) Describe the shape of the distribution. Is it appropriate to construct a confidence interval from this distribution? Explain why the distribution might have the shape it does.

Playing Video Games A new study provides some evidence that playing action video games strengthens a person's ability to translate sensory information quickly into accurate decisions. Researchers had 23 male volunteers with an average age of 20 look at moving arrays on a computer screen and indicate the direction in which the dots were moving \(^{33}\) Half of the volunteers ( 11 men) reported playing action video games at least five times a week for the previous year, while the other 12 reported no video game playing in the previous year. The response time and the accuracy score were both measured. A \(95 \%\) confidence interval for the mean response time for game players minus the mean response time for non-players is -1.8 to -1.2 seconds, while a \(95 \%\) confidence interval for mean accuracy score for game players minus mean accuracy score for non-players is -4.2 to +5.8 . (a) Interpret the meaning of the \(95 \%\) confidence interval for difference in mean response time. (b) Is it plausible that game players and non-game players are basically the same in response time? Why or why not? If not, which group is faster (with a smaller response time)? (c) Interpret the meaning of the \(95 \%\) confidence interval for difference in mean accuracy score. (d) Is it plausible that game players and non-game players are basically the same in accuracy? Why or whynot? If not, which group is more accurate?

Effect of Overeating for One Month: Average Long-Term Weight Gain Overeating for just four weeks can increase fat mass and weight over two years later, a Swedish study shows \(^{35}\) Researchers recruited 18 healthy and normal-weight people with an average age of \(26 .\) For a four-week period, participants increased calorie intake by \(70 \%\) (mostly by eating fast food) and limited daily activity to a maximum of 5000 steps per day (considered sedentary). Not surprisingly, weight and body fat of the participants went up significantly during the study and then decreased after the study ended. Participants are believed to have returned to the diet and lifestyle they had before the experiment. However, two and a half years after the experiment, the mean weight gain for participants was 6.8 lbs with a standard error of 1.2 lbs. A control group that did not binge had no change in weight. (a) What is the relevant parameter? (b) How could we find the actual exact value of the parameter? (c) Give a \(95 \%\) confidence interval for the parameter and interpret it. (d) Give the margin of error and interpret it.

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