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Is a Car a Necessity? A random sample of \(n=1483\) adults in the US were asked whether they consider a car a necessity or a luxury, \({ }^{31}\) and we find that a \(95 \%\) confidence interval for the proportion saying that it is a necessity is 0.83 to \(0.89 .\) Explain the meaning of this confidence interval in the appropriate context.

Short Answer

Expert verified
The 95% confidence interval of 0.83 to 0.89 indicates that we can be 95% confident that the actual percentage of adults in the US who consider a car a necessity falls between 83% and 89% based on the sampled data.

Step by step solution

01

Understanding Confidence Interval

A confidence interval is an estimated range of values which is likely to include an unknown population parameter. Here, it is used to determine the proportion of people who think a car is a necessity.
02

Applying Confidence Interval

The 95% confidence interval given is 0.83 to 0.89. This implies that if repeated samples were taken and the 95% confidence interval was calculated for each sample, the actual population parameter would be within the interval estimates 95% of the time.
03

Interpreting the Confidence Interval

The confidence interval 0.83 to 0.89 indicates that we can be 95% confident that the true proportion of all US adults who consider a car a necessity lies between 83% and 89%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Inference
Statistical inference is a cornerstone of data analysis, allowing us to draw conclusions about a population based on a sample of data. It's a way of 'making sense' of data by using various methods to test hypotheses and estimate population characteristics. In the context of the given exercise, statistical inference is used to derive a conclusion about the entire US adult population’s opinion on cars being a necessity, based on the sample of 1,483 individuals.

Understanding Through Confidence Intervals

One of the primary tools of statistical inference is the confidence interval, which gives us a range in which we expect the true population parameter to fall a certain percentage of the time. For instance, in our car necessity question, we interpret the 95% confidence interval of 0.83 to 0.89 as a statistically informed estimate, indicating that we are 95% certain the actual proportion in the full population falls within this range. The confidence level (95% in this case) reflects how sure we are that the intervals calculated from different random samples will contain the true parameter.
Population Parameter Estimation
Population parameter estimation is the process of using sample data to estimate the characteristics of a larger population. In a statistical sense, parameters are numerical characteristics that summarize data for an entire population, like the mean or proportion. As individuals, we cannot survey an entire population due to constraints like time and cost, but we can estimate parameters like the mean or proportion using a representative sample.

The Role of Sample Data

The 1,483 US adults represent the sample data from which we can estimate the population parameter — in this case, the proportion who view a car as a necessity rather than a luxury. Estimation comes in two types: point estimation and interval estimation. Point estimation provides a single value as an estimate of the population parameter, while interval estimation gives a range (like the confidence interval) where the parameter is likely to fall. The latter is more informative as it also communicates the estimate's precision.
Sample Proportion
The sample proportion is a statistic that estimates the proportion of the population that has a particular characteristic, based on a sample drawn from that population. It's calculated by dividing the number of individuals in the sample with the characteristic by the total sample size. In our exercise, the characteristic of interest is considering a car a necessity.

Relevance in the Real World

For the surveyed sample of US adults, the calculation would involve the number who answered that they see a car as a necessity divided by 1,483, the total sample size. This gives us a sample proportion, which we then use to infer about the population's perspective. Because it's based on a sample, the sample proportion is subject to sampling variability—thus the need for a confidence interval, which acknowledges this variability and provides a range that the true population proportion is likely to fall within.

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Most popular questions from this chapter

Give information about the proportion of a sample that agrees with a certain statement. Use StatKey or other technology to estimate the standard error from a bootstrap distribution generated from the sample. Then use the standard error to give a \(95 \%\) confidence interval for the proportion of the population to agree with the statement. StatKey tip: Use "CI for Single Proportion" and then "Edit Data" to enter the sample information. In a random sample of 400 people, 112 agree and 288 disagree.

In Exercises 3.49 and 3.50 , a \(95 \%\) confidence interval is given, followed by possible values of the population parameter. Indicate which of the values are plausible values for the parameter and which are not. A \(95 \%\) confidence interval for a mean is 112.1 to \(128.2 .\) Is the value given a plausible value of \(\mu ?\) (a) \(\mu=121\) (b) \(\mu=113.4\) (c) \(\mu=105.3\)

Exercises 3.112 to 3.115 give information about the proportion of a sample that agree with a certain statement. Use StatKey or other technology to find a confidence interval at the given confidence level for the proportion of the population to agree, using percentiles from a bootstrap distribution. StatKey tip: Use "CI for Single Proportion" and then "Edit Data" to enter the sample information. Find a \(99 \%\) confidence interval if, in a random sample of 1000 people, 382 agree, 578 disagree, and 40 can't decide.

Exercises 3.71 to 3.73 consider the question (using fish) of whether uncommitted members of a group make it more democratic. It has been argued that individuals with weak preferences are particularly vulnerable to a vocal opinionated minority. However, recent studies, including computer simulations, observational studies with humans, and experiments with fish, all suggest that adding uncommitted members to a group might make for more democratic decisions by taking control away from an opinionated minority. \({ }^{36}\) In the experiment with fish, golden shiners (small freshwater fish who have a very strong tendency to stick together in schools) were trained to swim toward either yellow or blue marks to receive a treat. Those swimming toward the yellow mark were trained more to develop stronger preferences and became the fish version of individuals with strong opinions. When a minority of five opinionated fish (wanting to aim for the yellow mark) were mixed with a majority of six less opinionated fish (wanting to aim for the blue mark), the group swam toward the minority yellow mark almost all the time. When some untrained fish with no prior preferences were added, however, the majority opinion prevailed most of the time. \({ }^{37}\) Exercises 3.71 to 3.73 elaborate on this study. How Often Does the Fish Majority Win? In a school of fish with a minority of strongly opinionated fish wanting to aim for the yellow mark and a majority of less passionate fish wanting to aim for the blue mark, as described under Fish Democracies above, a \(95 \%\) confidence interval for the proportion of times the majority wins (they go to the blue mark) is 0.09 to \(0.26 .\) Interpret this confidence interval. Is it plausible that fish in this situation are equally likely to go for either of the two options?

A Sampling Distribution for Performers in the Rock and Roll Hall of Fame Exercise 3.38 tells us that 206 of the 303 inductees to the Rock and Roll Hall of Fame have been performers. The data are given in RockandRoll. Using all inductees as your population: (a) Use StatKey or other technology to take many random samples of size \(n=10\) and compute the sample proportion that are performers. What is the standard error of the sample proportions? What is the value of the sample proportion farthest from the population proportion of \(p=0.68 ?\) How far away is it? (b) Repeat part (a) using samples of size \(n=20\). (c) Repeat part (a) using samples of size \(n=50\). (d) Use your answers to parts (a), (b), and (c) to comment on the effect of increasing the sample size on the accuracy of using a sample proportion to estimate the population proportion.

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