/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Use the fact that we have indepe... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the fact that we have independent events \(\mathrm{A}\) and \(\mathrm{B}\) with \(P(A)=0.7\) and \(P(B)=0.6\). Find \(P(B\) if \(A)\).

Short Answer

Expert verified
The probability of event B occurring, given that event A has occurred, for independent event A and B, is 0.42 or 42%.

Step by step solution

01

Identify Given Probabilities and Events

In this case, the known probabilities are \(P(A) = 0.7\) and \(P(B) = 0.6\). Event A and B are given to be independent.
02

Compute for Independent Events

When A and B are both independent, it is known that \( P(A ∩ B) = P(A)P(B) \). We compute by substituting the known values in this formula: \( P(A ∩ B) = (0.7)(0.6) = 0.42 \).
03

State the Result

Using the property of independent events, even though we only know the individual probabilities of each event, we can say that the probability of both events occurring simultaneously is 0.42, or 42%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is a mathematical framework designed to handle uncertainty and quantify the likelihood of various outcomes. It deals with events that may or may not happen and uses a numerical value, called probability, to represent how likely an event is to occur. This value ranges between 0 and 1, where 0 indicates impossibility and 1 signifies certainty.

At the core of probability theory are various axioms and principles that govern how probabilities can be calculated and manipulated. For example, the probability of all possible outcomes in a given scenario must add up to 1. In the context of solving problems, understanding the basics of probability theory is crucial. It provides a systematic way of thinking that can lead to accurate predictions in random processes - like predicting the outcome of flipping a coin or drawing a card from a deck.
Conditional Probability
Conditional probability is a measure of the probability of an event occurring given that another event has already occurred. The notation for conditional probability is represented as P(A|B), which reads as 'the probability of A given B'.

Understanding conditional probability is essential for distinguishing between independent and dependent events. For instance, if pulling a red card from a deck of cards changes the likelihood of pulling a black card right after, we're dealing with dependent events. However, in the absence of such influence, like in the case of flipping coins, events are considered independent, and the conditional probability is simply the probability of the event itself. The textbook exercise seeks to apply these principles by calculating the probability of an event occurring, assuming another related event has already occurred.
Event Independence
Event independence is a fundamental concept in probability theory where two events are said to be independent if the occurrence of one does not affect the probability of the occurrence of the other. This concept has practical implications as it simplifies calculations and helps us predict outcomes in various real-world scenarios.

In practical terms, suppose two dice are thrown; the outcome of one die does not influence the outcome of the other. Mathematically, if events A and B are independent, then the probability of both A and B occurring is the product of their individual probabilities, expressed as P(A ∩ B) = P(A)P(B). In the original exercise, events A and B are independent, leading to a straightforward calculation of the joint probability P(A ∩ B), which is important for various applications such as risk assessment and decision-making processes in fields as diverse as finance, meteorology, and even healthcare.

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Most popular questions from this chapter

About \(26 \%\) of movies coming out of Hollywood are comedies, Warner Bros has been the lead studio for about \(13 \%\) of recent movies, and about \(3 \%\) of recent movies are comedies from Warner Bros. \(^{2}\) Let \(\mathrm{C}\) denote the event a movie is a comedy and \(W\) denote the event a movie is produced by Warner Bros. (a) Write probability expressions for each of the three facts given in the first sentence of the exercise. (b) What is the probability that a movie is either a comedy or produced by Warner Bros? (c) What is the probability that a Warner Bros movie is a comedy? (d) What is the probability that a comedy has Warner Bros as its producer? (e) What is the probability that a movie coming out of Hollywood is not a comedy? (f) In terms of movies, what would it mean to say that \(\mathrm{C}\) and \(\mathrm{W}\) are disjoint events? Are they disjoint events? (g) In terms of movies, what would it mean to say that \(\mathrm{C}\) and \(\mathrm{W}\) are independent events? Are they independent events?

Heights of Men in the US Heights of adult males in the US are approximately normally distributed with mean 70 inches \((5 \mathrm{ft} 10 \mathrm{in})\) and standard deviation 3 inches. (a) What proportion of US men are between \(5 \mathrm{ft}\) 8 in and \(6 \mathrm{ft}\) tall \((68\) and 72 inches, respectively)? (b) If a man is at the 10 th percentile in height, how tall is he?

Ask you to convert an area from one normal distribution to an equivalent area for a different normal distribution. Draw sketches of both normal distributions, find and label the endpoints, and shade the regions on both curves. The area above 13.4 for a \(N(10,2)\) distribution converted to a standard normal distribution

In Exercises \(\mathrm{P} .74\) to \(\mathrm{P} .77\), fill in the \(?\) to make \(p(x)\) a probability function. If not possible, say so. $$ \begin{array}{lccccc} \hline x & 1 & 2 & 3 & 4 & 5 \\ \hline p(x) & 0.3 & ? & 0.3 & 0.3 & 0.3 \\ \hline \end{array} $$

Use the information that, for events \(\mathrm{A}\) and \(\mathrm{B}\), we have \(P(A)=0.8, P(B)=0.4\), and \(P(A\) and \(B)=0.25.\) Find \(P(B\) if \(A)\).

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