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The categories of a categorical variable are given along with the observed counts from a sample. The expected counts from a null hypothesis are given in parentheses. Compute the \(\chi^{2}\) -test statistic, and use the \(\chi^{2}\) -distribution to find the p-value of the test. $$ \begin{array}{lccc} \hline \text { Category } & \text { A } & \text { B } & \text { C } \\ \text { Observed } & 35(40) & 32(40) & 53(40) \\ \text { (Expected) } & & & \\ \hline \end{array} $$

Short Answer

Expert verified
The $\chi^{2}$ -test statistic for the data is 6.45 and the p-value is less than 0.05.

Step by step solution

01

Calculate $\chi^{2}$ -test statistic

The Chi-Square test statistic is calculated by summing up the squares of the differences between observed (O) and expected (E) frequencies divided by the expected frequencies for each category (A, B, and C in this case). So for each category, the formula is \((O-E)^2/E\). We use the observed and expected counts for each category given in the question. These calculations are: For category A: \((35-40)^2 / 40 = 0.625\)For category B: \((32-40)^2 / 40 = 1.6\)For category C: \((53-40)^2 / 40 = 4.225\)Summing these values gives the test statistic:\(0.625 + 1.6 + 4.225 = 6.45\)
02

Find degrees of freedom

The degrees of freedom for a Chi-Square test for independence are calculated as the number of categories minus 1. In this case, we have 3 categories (A, B, C), so degrees of freedom becomes \(3-1 = 2\).
03

Find p-value

The p-value is the probability of obtaining test results at least as extreme as the results actually observed, under the assumption that the null hypothesis is correct. It can be looked up in a Chi-Square distribution table (with degrees of freedom found in Step 2 and the Chi-Square statistic value found in Step 1). This is a complex step and usually requires specialized statistical software. The exact value cannot be given without referencing the $\chi^{2}$ table or software, but is less than 0.05 if the test statistic is greater than 5.991 for degrees of freedom 2. As our Stats calculated as 6.45 is greater than 5.991, we can say that the p-value is less than 0.05 which indicates a significant result.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Categorical variable analysis
Categorical variables are qualities or characteristics that can be categorized into groups or categories which don't have an inherent order or ranking. Examples include colors, types of cuisine, or categories like 'pass' or 'fail'.

Analyzing categorical variables often involves looking at the frequency or count of occurrences within each category and comparing these against expected frequencies - which is precisely what we do in a Chi-Square test. The Chi-Square test evaluates if there is a significant difference between what was observed in real-world data and what would be expected under a certain hypothesis. For instance, if you're testing whether a die is fair, the expected frequency for each side would be equal. If the die keeps landing on one number more often than others, a Chi-Square test can help assess if this pattern is due to random chance or if it's statistically unlikely, suggesting the die might be biased.

When applied effectively, categorical variable analysis using tests like the Chi-Square can uncover insights into trends, biases, or anomalies within the data, providing valuable information that can impact decision making in fields such as marketing, healthcare, and social sciences.
Null hypothesis
The null hypothesis is a fundamental concept in statistical testing, representing the default statement or position that there is no effect or no difference. In the context of a Chi-Square test, the null hypothesis usually asserts that there is no association between the categorical variables being tested.

For instance, if a researcher believes that a new teaching method does not affect student performance, the null hypothesis would state that the pass rates among students are the same regardless of whether the new or old teaching method is used. The Chi-Square test then assesses the strength of evidence against the null hypothesis based on the data collected.

Understanding and properly stating the null hypothesis is critical since the outcome of the test—whether you reject or fail to reject it—forms the basis of your statistical inference. A common error for students to watch out for is misunderstanding or incorrectly formulating the null hypothesis, which can lead to incorrect conclusions. Always ensure that your null hypothesis aligns precisely with the question or problem at hand.
p-value calculation
The p-value is an integral part of hypothesis testing and is used to measure the strength of evidence against the null hypothesis. In simple terms, it tells you how likely it is to obtain your observed results, or more extreme, if the null hypothesis were true.

In a Chi-Square test, this means the p-value calculates the probability of seeing the differences between the observed and expected frequencies by chance alone. A smaller p-value indicates that the observed data is very unlikely under the assumption that the null hypothesis is correct. For example, a p-value less than 0.05, which is a common threshold, suggests that there is less than a 5% probability that the observed discrepancies are due to chance, leading many researchers to reject the null hypothesis.

Significant p-values can indicate the need for further investigation or suggest that some variable not accounted for is influencing the results. It's important to remember that while the p-value can guide us in understanding our results, it is not a measure of the size or importance of the observed effect and should be interpreted within the context of the entire study and its limitations.

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Most popular questions from this chapter

Can People Delay Death? A new study indicates that elderly people are able to postpone death for a short time to reach an important occasion. The researchers \(^{9}\) studied deaths from natural causes among 1200 elderly people of Chinese descent in California during six months before and after the Harbor Moon Festival. Thirty-three deaths occurred in the week before the Chinese festival, compared with an estimated 50.82 deaths expected in that period. In the week following the festival, 70 deaths occurred, compared with an estimated 52\. "The numbers are so significant that it would be unlikely to occur by chance," said one of the researchers. (a) Given the information in the problem, is the \(\chi^{2}\) statistic likely to be relatively large or relatively small? (b) Is the p-value likely to be relatively large or relatively small? (c) In the week before the festival, which is higher: the observed count or the expected count? What does this tell us about the ability of elderly people to delay death? (d) What is the contribution to the \(\chi^{2}\) -statistic for the week before the festival?

Give a two-way table and specify a particular cell for that table. In each case find the expected count for that cell and the contribution to the chi- square statistic for that cell. \((\mathrm{B}, \mathrm{E})\) cell $$ \begin{array}{l|rrrr|r} \hline & \text { D } & \text { E } & \text { F } & \text { G } & \text { Total } \\ \hline \text { A } & 39 & 34 & 43 & 34 & 150 \\ \text { B } & 78 & 89 & 70 & 63 & 330 \\ \text { C } & 23 & 37 & 27 & 33 & 120 \\ \hline \text { Total } & 140 & 160 & 140 & 130 & 600 \\ \hline \end{array} $$

The categories of a categorical variable are given along with the observed counts from a sample. The expected counts from a null hypothesis are given in parentheses. Compute the \(\chi^{2}\) -test statistic, and use the \(\chi^{2}\) -distribution to find the p-value of the test. $$ \begin{array}{lccc} \hline \text { Category } & \text { A } & \text { B } & \text { C } \\ \text { Observed } & 61(50) & 35(50) & 54(50) \\ \text { (Expected) } & & & \\ \hline \end{array} $$

Metal Tags on Penguins In Exercise 6.178 on page 403 we perform a test for the difference in the proportion of penguins who survive over a 10 -year period, between penguins tagged with metal tags and those tagged with electronic tags. We are interested in testing whether the type of tag has an effect on penguin survival rate, this time using a chi-square test. In the study, 33 of the 167 metal-tagged penguins survived while 68 of the 189 electronic-tagged penguins survived. (a) Create a two-way table from the information given. (b) State the null and alternative hypotheses. (c) Give a table with the expected counts for each of the four categories. (d) Calculate the chi-square test statistic. (e) Determine the p-value and state the conclusion.

Who Is More Likely to Smoke: Males or Females? Data 2.11 on page 111 introduces the dataset NutritionStudy which contains, among other things, information about smoking history and gender of the participants. Is there a significant association between these two variables? Use a statistical software package and the variables PriorSmoke and Gender to conduct a chi- square analysis and clearly give the results. The variable PriorSmoke is coded as \(1=\) never smoked, \(2=\) prior smoker, and \(3=\) current smoker.

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