/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 76 Find endpoints of a t-distributi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find endpoints of a t-distribution with \(5 \%\) beyond them in each tail if the sample has size \(n=10\)

Short Answer

Expert verified
The endpoints of the t-distribution for a sample size of 10 with 5% beyond each tail are the t-values corresponding to the 5% and 95% points with 9 degrees of freedom.

Step by step solution

01

Identify Degrees of Freedom

Degrees of Freedom (df) for a t-distribution is given by \(n-1\), where \(n\) is the sample size. For this exercise, the sample size \(n\) is 10, therefore df = \(10 - 1 = 9\)
02

Determine the t-values

From the t-distribution table or a statistical function capable of returning t-values, lookup or calculate the t-values that correspond to the upper 5% and the lower 5% of the t-distribution for 9 degrees of freedom. These t-values represent the endpoints of the t-distribution with 5% of the area beyond them in each tail.
03

Provide the Result

After using the t-table or a function, the resulting t-value that bounds the lower and upper 5% of the distribution are the final answer. These form the endpoints asked for in the exercise.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees of Freedom
The term 'degrees of freedom' (df) in statistics is crucial when dealing with distributions like the t-distribution. It refers to the number of independent values or quantities which can freely vary in the analysis without breaking any constraints. In the context of a sample, if you have a sample size, denoted as \(n\), the degrees of freedom are usually calculated as \(n - 1\).

When working with t-distributions, the degrees of freedom help determine the exact shape of the curve. It's important because the t-distribution varies according to the sample size. For small samples, the t-distribution is more spread out with fatter tails, indicating higher uncertainty. As the df increases, the t-distribution looks more like the standard normal distribution. In our exercise, with a sample size of 10, we have \(10 - 1 = 9\) degrees of freedom, which indicates the specific t-distribution to use for our calculations.
T-Values
T-values are the critical values in a t-distribution, and they're used to estimate where a sample mean would fall within a whole population. Whenever you are dealing with hypothesis testing in statistics, t-values come into play. To locate these values, typically you'd refer to a t-distribution table or use a statistical software, which will show you the t-value associated with a given probability and degrees of freedom.

In our exercise's case, we are looking for the t-values that correspond to the tails (the upper and lower 5%) of the t-distribution with 9 degrees of freedom. These t-values define the threshold for what we consider extreme values in our distribution, essentially the endpoints beyond which we only expect 5% of the data to fall in either tail.
Statistical Significance
Statistical significance is a term used to indicate that the results of a statistical test are not likely to have occurred by random chance. This is determined through a p-value, which essentially indicates the probability of obtaining test results at least as extreme as the ones observed during the test, assuming that the null hypothesis is true. A commonly used threshold for determining statistical significance is a p-value of 0.05 or 5%.

If a result is statistically significant, it means the data provide strong evidence against the null hypothesis. In relation to our t-distribution problem, locating the t-values that correspond to the 5% in the tails helps us determine the range of values for which we would consider results statistically significant or not.
Probability Distribution
A probability distribution is a mathematical function that provides the probabilities of occurrence of different possible outcomes in an experiment. It's a core concept in statistics because it describes the spread of values a random variable can take on and how likely they are to occur. There are many types of probability distributions, with the t-distribution being one of them. Specifically designed for small sample sizes, the t-distribution accounts for the extra uncertainty inherent when estimating population parameters.

The t-distribution is particularly useful when the population standard deviation is unknown and the sample size is small. As with our exercise, the t-distribution can determine the probability associated with the t-values at the tails or 'endpoints' indicating how extreme the data can be before it becomes statistically significant.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Standard Error from a Formula and a Bootstrap Distribution In Exercises 6.19 to \(6.22,\) use StatKey or other technology to generate a bootstrap distribution of sample proportions and find the standard error for that distribution. Compare the result to the standard error given by the Central Limit Theorem, using the sample proportion as an estimate of the population proportion \(p\). Proportion of home team wins in soccer, with \(n=120\) and \(\hat{p}=0.583\)

A sample with \(n=12, \bar{x}=7.6,\) and \(s=1.6\)

Impact of the Population Proportion on SE Compute the standard error for sample proportions from a population with proportions \(p=0.8, p=0.5\), \(p=0.3,\) and \(p=0.1\) using a sample size of \(n=100\). Comment on what you see. For which proportion is the standard error the greatest? For which is it the smallest?

Number of Bedrooms in Houses in New York and New Jersey The dataset HomesForSale has data on houses available for sale in three Mid-Atlantic states (NY, NJ, and PA). For this exercise we are specifically interested in homes for sale in New York and New Jersey. We have information on 30 homes from each state and observe the proportion of homes with more than three bedrooms. We find that \(26.7 \%\) of homes in NY \(\left(\hat{p}_{N Y}\right)\) and \(63.3 \%\) of homes in NJ \(\left(\hat{p}_{N J}\right)\) have more then three bedrooms. (a) Is the normal distribution appropriate to model this difference? (b) Test for a difference in proportion of homes with more than three bedrooms between the two states and interpret the result.

A young statistics professor decided to give a quiz in class every week. He was not sure if the quiz should occur at the beginning of class when the students are fresh or at the end of class when they've gotten warmed up with some statistical thinking. Since he was teaching two sections of the same course that performed equally well on past quizzes, he decided to do an experiment. He randomly chose the first class to take the quiz during the second half of the class period (Late) and the other class took the same quiz at the beginning of their hour (Early). He put all of the grades into a data table and ran an analysis to give the results shown below. Use the information from the computer output to give the details of a test to see whether the mean grade depends on the timing of the quiz. (You should not do any computations. State the hypotheses based on the output, read the p-value off the output, and state the conclusion in context.) $$ \begin{aligned} &\text { Two-Sample T-Test and Cl }\\\ &\begin{array}{lrrrr} \text { Sample } & \mathrm{N} & \text { Mean } & \text { StDev } & \text { SE Mean } \\ \text { Late } & 32 & 22.56 & 5.13 & 0.91 \\ \text { Early } & 30 & 19.73 & 6.61 & 1.2 \end{array} \end{aligned} $$ Difference \(=\mathrm{mu}\) (Late) \(-\mathrm{mu}\) (Early) Estimate for difference: 2.83 \(95 \%\) Cl for difference: (-0.20,5.86) T-Test of difference \(=0\) (vs not \(=\) ): T-Value \(=1.87\) P-Value \(=0.066 \quad \mathrm{DF}=54\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.