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A margin of error within \(\pm 3 \%\) with \(90 \%\) confidence. We estimate that the population proportion is about 0.3 .

Short Answer

Expert verified
The required sample size to acquire a margin of error within \(\pm 3 \%\) with \(90 \%\) confidence, when the population proportion is estimated to be about 0.3, is 752

Step by step solution

01

Determining the value of Z for the given confidence level

For a confidence level of \(90\%\) (or 0.9), a Z value of 1.645 is typically used. This value is found in Z-tables that list known values related to confidence levels.
02

Compute the estimated standard error

The estimated standard error is calculated using the formula \(\sqrt{P(1 - P)}\), where \(P\) is the estimated population proportion. So, using the given \(P\) as 0.3, the estimated standard error is \(\sqrt{0.3(1 - 0.3)} = \sqrt{0.3*0.7} = \sqrt{0.21} = 0.45826 (5 decimals).\)
03

Calculate the required Sample Size

The sample size is found by squaring the result of Z times the standard error divided by the margin of error. The sample size is given by \((Z * \sqrt{P(1 - P)} / E)^2\), where \(E\) is the margin of error, substituting the values, we have \((1.645 * 0.45826 / 0.03)^2 = 751.31\).
04

Adjust the Calculated Sample Size

Since a sample size can’t be in a decimal form, it is rounded up to the next nearest whole number. Thus, the sample size will be 752.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Level
Understanding the confidence level is essential in the context of statistics and research. It represents the probability that a statistical parameter, like a mean or proportion, falls within a certain range of values. The confidence level is typically expressed as a percentage, such as 90%.
This percentage implies that if you were to repeat a study 100 times, you can expect that the true parameter – whether it be a mean or proportion – would fall within the estimated range 90 of those times. The confidence level influences the width of the confidence interval.
  • A higher confidence level means a wider confidence interval. This means more certainty that the interval contains the true parameter but also more cautious estimates.
  • Conversely, a lower confidence level results in a narrower confidence interval, giving less certainty about containing the true parameter but more precise estimates.
For common confidence levels, statisticians use certain Z-values, which are derived from the normal distribution. In our exercise, a 90% confidence level corresponds to a Z-value of 1.645, indicating this is how much we "stretch" our margin of error on either side of our estimate.
Population Proportion
Population proportion is a fundamental concept in statistics that refers to the fraction or percentage of a population that has a particular trait or characteristic. For example, if you want to know what portion of voters favor a new policy, the population proportion is what you would calculate.
This is usually denoted by the letter "P" in equations. In the exercise, the population proportion is given as 0.3, meaning 30% of the population is estimated to possess the trait we're interested in. This value directly affects our calculations for things like standard error and ultimately the margin of error. To broaden our understanding:
  • Population proportion helps in predicting expected frequencies when analyzing categorical data.
  • It can be crucial in crafting and interpreting surveys, polls, and other data-driven tools for decision-making.
The estimation is based on sampling, meaning statistical methods are applied to calculate the best guess of this proportion from smaller, manageable data sets. This estimated population proportion is vital for determining sample size and accuracy in statistical studies.
Sample Size Calculation
Calculating an appropriate sample size is a critical step in designing a survey or study, as it significantly affects the precision and reliability of your results. The goal here is to have as accurate an estimate as possible of the population parameter you're studying.
A larger sample size generally leads to more reliable estimates but requires more resources.The formula used in the exercise \[ n = \left( \frac{Z \cdot \sqrt{P(1 - P)}}{E} \right)^2 \] where
  • \(n\) is the sample size,
  • \(Z\) is the Z-score corresponding to your desired confidence level,
  • \(P\) is the estimated population proportion, and
  • \(E\) is the margin of error.
In our exercise, using a margin of error of \(\pm 3\%\), a Z-value of 1.645, and an estimated population proportion of 0.3, the calculation determined that 752 is the necessary sample size – rounded up from 751.31, to ensure the assigned confidence level is satisfied.
Remember, rounding up is crucial in sample size calculations to maintain the minimum required level of confidence.

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Most popular questions from this chapter

On page 1 1 in Section \(1.1,\) we describe studies to investigate whether there is evidence of pheromones (subconscious chemical signals) in female tears that affect sexual arousal in men. In one of the studies, \(^{71} 50\) men had a pad attached to the upper lip that contained either female tears or a salt solution dripped down the same female's face. Each subject participated twice, on consecutive days, once with tears and once with saline, randomized for order, and doubleblind. Testosterone levels were measured before sniffing and after sniffing on both days. While normal testosterone levels vary significantly between different men, average levels for the group were the same before sniffing on both days and after sniffing the salt solution (about \(155 \mathrm{pg} / \mathrm{mL}\) ) but were reduced after sniffing the tears (about \(133 \mathrm{pg} / \mathrm{mL}\) ). The mean difference in testosterone levels after sniffing the tears was 21.7 with standard deviation \(46.5 .\) (a) Why did the investigators choose a matchedpairs design for this experiment? (b) Test to see if testosterone levels are significantly reduced after sniffing tears? (c) Can we conclude that sniffing female tears reduces testosterone levels (which is a significant indicator of sexual arousal in men)?

If random samples of the given sizes are drawn from populations with the given proportions: (a) Find the mean and standard error of the distribution of differences in sample proportions, \(\hat{p}_{A}-\hat{p}_{B}\) (b) If the sample sizes are large enough for the Central Limit Theorem to apply, draw a curve showing the shape of the sampling distribution. Include at least three values on the horizontal axis. Samples of size 500 from population \(A\) with proportion 0.58 and samples of size 200 from population \(B\) with proportion 0.49

A \(90 \%\) confidence interval for \(\mu_{1}-\mu_{2}\) using the paired difference sample results \(\bar{x}_{d}=556.9\), \(s_{d}=143.6, n_{d}=100\)

Standard Error from a Formula and Simulation In Exercises 6.15 to \(6.18,\) find the mean and standard error of the sample proportions two ways: (a) Use StatKey or other technology to simulate at least 1000 sample proportions. Give the mean and standard error and comment on whether the distribution appears to be normal. (b) Use the formulas in the Central Limit Theorem to compute the mean and standard error. Are the results similar to those found in part (a)? Sample proportions of sample size \(n=40\) from a population with \(p=0.5\)

Test \(H_{0}: \mu_{1}=\mu_{2}\) vs \(H_{a}: \mu_{1}>\mu_{2}\) using the paired data in the following table: $$ \begin{array}{lllllllllll} \hline \text { Situation } 1 & 125 & 156 & 132 & 175 & 153 & 148 & 180 & 135 & 168 & 157 \\ \text { Situation } 2 & 120 & 145 & 142 & 150 & 160 & 148 & 160 & 142 & 162 & 150 \\ \hline \end{array} $$

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