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91Ó°ÊÓ

If random samples of the given sizes are drawn from populations with the given proportions: (a) Find the mean and standard error of the distribution of differences in sample proportions, \(\hat{p}_{A}-\hat{p}_{B}\) (b) If the sample sizes are large enough for the Central Limit Theorem to apply, draw a curve showing the shape of the sampling distribution. Include at least three values on the horizontal axis. Samples of size 300 from population \(A\) with proportion 0.15 and samples of size 300 from population \(B\) with proportion 0.20

Short Answer

Expert verified
Mean of distribution of differences in sample proportions: -0.05. Standard error: approx. 0.028. The sizes of the samples are large enough for the Central Limit Theorem to apply, and the sampling distribution curve will be a normal curve centered at -0.05. The points on the horizontal axis will be at about -0.05, -0.022, and -0.078.

Step by step solution

01

Calculate Sample Proportions

First, calculate the proportions from the two populations, \(A\) and \(B\), which are set given as \(p_{A}=0.15\) and \(p_{B}=0.20\).
02

Compute Difference in Sample Proportions

The difference in sample proportions, denoted by \(\hat{p}_{A} - \hat{p}_{B}\), can be obtained simply by subtracting the proportion of Population \(B\) from that of Population \(A\). Hence, the difference is \(0.15 - 0.20 = -0.05\).
03

Calculate the Standard Error

The formula for the standard error of the difference in proportions is \(\sqrt{ \[ \frac{{p_{A} * (1 - p_{A})}}{{n_{A}}} \] + \[ \frac{{p_{B} * (1 - p_{B})}}{{n_{B}}} \] }\). Here, \(n_{A}\) and \(n_{B}\) represent the sizes of populations \(A\) and \(B\) respectively, which are both 300 in this exercise. Substituting the values in, we get the standard error to be approximately 0.028.
04

Application of Central Limit Theorem

Since the sizes of both the samples are large (300), the Central Limit Theorem can be applied. This theorem stipulates that the distribution of the sample means approximates a normal distribution as the sample size becomes large.
05

Draw the Sampling Distribution Curve

The sampling distribution curve will be a normal curve centered around the mean difference in proportions which is -0.05. The standard deviation in this case will be the standard error that we earlier computed. The horizontal axis will mark the mean, and points representing one standard error above and below the mean, approximately at -0.022 and -0.078.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Sampling Distribution
Sampling distribution is a key statistical concept that represents the probability distribution of a given statistic based on a random sample. In simple terms, it tells us how a specific measurement might vary across different samples. For instance, if we repeatedly drew samples from the same population and calculated the mean each time, the distribution of these means would form the sampling distribution of the mean.
This concept is vital for understanding how statistics derived from samples can reflect the true parameters of a population. In our exercise, we're particularly interested in the sampling distribution of the difference between sample proportions from two populations.
  • This distribution helps us determine how different the sample proportions could be due to random sampling variability.
  • The shape of this distribution is often normal, especially when sample sizes are large, thanks to the Central Limit Theorem.
This concept allows statisticians to make inferences about the population differences based on the observed sample differences.
Decoding Standard Error
Standard error is an important measure in statistics that reflects the amount of variability or dispersion you might expect in a statistic from sample to sample. It essentially tells us how much the sample statistic can be expected to fluctuate from the actual population parameter.
When dealing with the difference between two sample proportions, the standard error helps quantify the uncertainty in that difference.
  • The formula for the standard error of the difference in sample proportions is: \[\sqrt{ \frac{{p_{A} \times (1 - p_{A})}}{n_{A}} + \frac{{p_{B} \times (1 - p_{B})}}{n_{B}} }\]
  • This formula incorporates both proportions \(p_{A}\), \(p_{B}\) and their respective sample sizes \(n_{A}\), \(n_{B}\).
The computed standard error can then be used to determine how far off our observed sample difference might be from the true difference in population proportions. In our exercise, the standard error was calculated to be 0.028. This means there's some variability expected in the sample difference, but it's relatively small compared to other potential statistics.
Exploring Sample Proportions
Sample proportions are the fractions or percentages that represent part of a whole sample. In statistics, understanding sample proportions is crucial for estimating and making inferences about population proportions.
For example, if 15% of a sample of 300 comes from Population A, then the sample proportion \(\hat{p}_{A}\) would be 0.15. Similarly, if 20% of a sample of the same size comes from Population B, then \(\hat{p}_{B}\) would be 0.20.
  • These sample proportions can vary from the actual population proportions due to sampling variability.
  • By using the Central Limit Theorem, we can assume that with large sample sizes, the distribution of these sample proportions will approximate a normal distribution.
In our exercise, we are comparing differences in these sample proportions to make inferences about the two populations. This comparison involves both calculating the difference and understanding how that difference might vary due to random chance.

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Most popular questions from this chapter

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