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Is a Normal Distribution Appropriate? In Exercises 6.13 and \(6.14,\) indicate whether the Central Limit Theorem applies so that the sample proportions follow a normal distribution. In each case below, does the Central Limit Theorem apply? (a) \(n=500\) and \(p=0.1\) (b) \(n=25\) and \(p=0.5\) (c) \(n=30\) and \(p=0.2\) (d) \(n=100\) and \(p=0.92\)

Short Answer

Expert verified
For all of the four situations (a, b, c, d), the Central Limit Theorem applies, and the sample proportions follow a normal distribution.

Step by step solution

01

Analyze Situation (a)

Here, the sample size \(n = 500 \) and the sample proportion \(p = 0.1\). We'll first check if \(n*p > 5\), which would be \(500 * 0.1 = 50\). Then, we will check if \(n*(1-p) > 5\), which would be \(500 * (1 - 0.1) = 450\). Since both \(n*p\) and \(n*(1-p)\) are greater than 5, the Central Limit Theorem applies in this case and the sample proportions follow a normal distribution.
02

Analyze Situation (b)

In this case, the sample size \(n = 25\) and the sample proportion \(p = 0.5\). We'll first check \(n*p > 5\), which would be \(25 * 0.5 = 12.5\). Then, we'll check \(n*(1-p) > 5\), which would be \(25 * (1 - 0.5) = 12.5\). Given that both \(n*p\) and \(n*(1-p)\) are greater than 5, the Central Limit Theorem applies here, and thus the sample proportions follow a normal distribution.
03

Analyze Situation (c)

In situation (c), the sample size \(n = 30\) and the sample proportion \(p = 0.2\). Checking \(n*p > 5\) provides \(30 * 0.2 = 6\). Then, \(n*(1-p) > 5\) would give \(30 * (1 - 0.2) = 24\). Once again, both \(n*p\) and \(n*(1-p)\) are greater than 5. Therefore, the Central Limit Theorem applies and the sample proportions follow a normal distribution.
04

Analyze Situation (d)

Here, the sample size \(n = 100\) and the sample proportion \(p = 0.92\). We'll first check if \(n*p > 5\), which gives \(100 * 0.92 = 92\). Then, we'll check \(n*(1-p) > 5\), which results in \(100 * (1 - 0.92) = 8\). Given that both conditions are met, as both \(n*p\) and \(n*(1-p)\) are larger than 5, the Central Limit Theorem applies, meaning the sample proportions follow a normal distribution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
The normal distribution is a bell-shaped curve that is symmetrical about the mean, showing how data is dispersed in a set. It's a fundamental concept in statistics, used to describe any variable that tends to cluster around the mean. In the context of the Central Limit Theorem (CLT), it tells us that when we take an adequately large sample from a population, the sample mean will be normally distributed, regardless of the population's distribution, provided the sample size is large enough and the data are independently sampled.

For instance, consider flipping a coin. While the outcomes of individual flips are not normally distributed (as they are binomial), the distribution of the proportion of heads over a large number of flips does tend to be normal. This is due to the CLT which states that these sample proportions will approximate a normal distribution as the number of trials increases. Hence, for the exercise situations (a) through (d), the question was to determine whether the calculated sample proportions would follow a normal distribution according to the CLT criteria.
Sample Proportion
Sample proportion, symbolized as \(p\), is a statistic that estimates the proportion of a certain outcome within a sample. It's the fraction of sample units that exhibits a particular attribute or feature. For the problems given in the exercise, sample proportion represents the assumed likelihood of a particular event occurring.

It's important to remember that calculating the sample proportion is quite straightforward. It's simply the number of 'successes' in the sample divided by the total sample size. However, for the Central Limit Theorem to apply to the sample proportion — and allow for the normal distribution assumption — the products \(np\) and \(n(1-p)\) both need to be greater than 5, which ensures a sufficiently large sample size and a spread of data which helps in approximating the binomial distribution to the normal distribution. The provided step-by-step solution for our exercise expertly verifies these conditions for each scenario.
Sample Size
Sample size, denoted as \(n\), is the total number of observations or elements selected from a population to be included in the study. A larger sample size provides a more accurate estimate of the population parameter and is less susceptible to sampling error. In statistical analysis and experiments, choosing an appropriate sample size is crucial as it affects the ability to draw meaningful conclusions about the whole population.

The sample size is a key component in the effectiveness of the Central Limit Theorem. With a larger \(n\), the more likely the distribution of the sample mean will resemble a normal distribution. This is vividly seen in the exercise provided, where only when the sample size and the sample proportion product met the condition of being greater than 5, could it be affirmed that the CLT applies, thereby allowing the sample proportions to align with a normal distribution. This principle holds true across all sorts of data and is a cornerstone of inferential statistics.

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Most popular questions from this chapter

Involve scores from the high school graduating class of 2010 on the SAT (Scholastic Aptitude Test). The average score on the Writing part of the SAT exam for males is 486 with a standard deviation of \(112,\) while the average score for females is 498 with a standard deviation of 111 (a) If random samples are taken with 100 males and 100 females, find the mean and standard deviation of the distribution of differences in sample means, \(\bar{x}_{m}-\bar{x}_{f},\) where \(\bar{x}_{m}\) represents the sample mean for the males and \(\bar{x}_{f}\) represents the sample mean for the females. (b) Repeat part (a) if the random samples contain 500 males and 500 females. (c) What effect do the different sample sizes have on center and spread of the distribution?

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In the dataset ICUAdmissions, the variable Service indicates whether the ICU (Intensive Care Unit) patient had surgery (1) or other medical treatment (0) and the variable Sex gives the gender of the patient (0 for males and 1 for females.) Use technology to test at a \(5 \%\) level whether there is a difference between males and females in the proportion of ICU patients who have surgery.

Percent of Free Throws Made Usually, in sports, we expect top athletes to get better over time. We expect future athletes to run faster, jump higher, throw farther. One thing has remained remarkably constant, however. The percent of free throws made by basketball players has stayed almost exactly the same for 50 years. \(^{5}\) For college basketball players, the percent is about \(69 \%,\) while for players in the NBA (National Basketball Association) it is about \(75 \%\). (The percent in each group is also very similar between male and female basketball players.) In each case below, find the mean and standard deviation of the distribution of sample proportions of free throws made if we take random samples of the given size. (a) Samples of 100 free throw shots in college basketball (b) Samples of 1000 free throw shots in college basketball (c) Samples of 100 free throw shots in the \(\mathrm{NBA}\) (d) Samples of 1000 free throw shots in the \(\mathrm{NBA}\)

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