/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 129 In Exercise \(6.128,\) we see th... [FREE SOLUTION] | 91Ó°ÊÓ

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In Exercise \(6.128,\) we see that plastic microparticles are contaminating the world's shorelines and that much of the pollution appears to come from fibers from washing polyester clothes. The same study referenced in Exercise 6.128 also took samples from ocean beaches. Five samples were taken from each of 18 different shorelines worldwide, for a total of 90 samples of size \(250 \mathrm{~mL}\). The mean number of plastic microparticles found per \(250 \mathrm{~mL}\) of sediment was 18.3 with a standard deviation of 8.2 . (a) Find and interpret a \(99 \%\) confidence interval for the mean number of polyester microfibers per \(250 \mathrm{~mL}\) of beach sediment. (b) What is the margin of error? (c) If we want a margin of error of only ±1 with \(99 \%\) confidence, what sample size is needed?

Short Answer

Expert verified
The 99% confidence interval for the mean number of polyester microfibers per 250 mL of beach sediment is approximately 16.064 to 20.536. The margin of error is approximately ±2.236. A sample size of approximately 448 is required to achieve a desired margin of error of only ±1 with 99% confidence.

Step by step solution

01

- Calculate confidence interval

Using the formula for the confidence interval, which is \( \bar{x} \pm z*\frac{\sigma}{\sqrt{n}}\), where \(\bar{x}\) is the sample mean, \(\sigma\) is the standard deviation, \(n\) is the sample size, and \(z\) the z-score associated with the desired level of confidence. Here, \(\bar{x} = 18.3, \sigma = 8.2, and n = 90\). The z-score for a 99% confidence interval is approximately 2.576. Substituting these values into the formula gives: \(18.3 \pm 2.576*\frac{8.2}{\sqrt{90}}\) which calculates to a confidence interval of approximately \(18.3 \pm 2.236\). This means we are 99% confident that the true mean number of polyester microfibers per 250 mL of beach sediment is between 16.064 and 20.536.
02

- Calculate margin of error

The margin of error is the amount of uncertainty around the sample estimate. The margin of error for this confidence interval is half the width of the confidence interval, so in this case it would be \(2.236\), since our confidence interval has a width of \(2.236 * 2 = 4.472\). This means there is a fluctuation of around 2.236 in either direction.
03

- Determine needed sample size

If we want the margin of error to be only ±1, we can use the formula for the margin of error and solve for n to find the necessary sample size. The formula is \(E=z*\frac{\sigma}{\sqrt{n}}\), so solving for n gives \(n=(z*\frac{\sigma}{E})^2\). Substituting the values \(z = 2.576, \sigma = 8.2, and E = 1\) gives: \(n=(2.576*\frac{8.2}{1})^2\) which calculates to approximately n=448. Thus, a sample size of 448 is needed to achieve a margin of error of only ±1 with 99% confidence.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Margin of Error
The margin of error is a crucial concept in statistics. It's defined as the maximum expected difference between the true population parameter and a sample estimate. In simple terms, it gives us a buffer zone around our sample mean, within which we can expect the true mean to lie with a certain level of confidence.
For a 99% confidence interval in our exercise, we want to know how much our sample estimate (18.3 microfibers per 250 mL) might differ from the actual population mean. As calculated in the exercise, the margin of error is 2.236. This value indicates that the true average number of plastic microparticles could be 2.236 more or less than the sample mean of 18.3.
In essence, the margin of error allows us to account for the variability inherent in any sampling process, reassuring us that even if our sample isn't perfectly representative, our estimation still falls within this range.
Sample Size Calculation
Determining the right sample size is fundamental to achieving a desired margin of error with a given level of confidence. The larger your sample size, the narrower your margin of error becomes, allowing for a more precise estimate.
In our problem, we want a margin of error of ±1 with 99% confidence. To compute the necessary sample size, we use the formula:
  • \(n = \left( \frac{z \cdot \sigma}{E} \right)^2 \)
Here, \(E\) is the desired margin of error, \(z\) is the z-score for the confidence level (2.576 for 99%), and \(\sigma\) is the standard deviation (8.2). By plugging these into the formula, we find that a sample size of approximately 448 is needed.
This calculation highlights the balance between desired accuracy and the practicality of collecting a larger sample. A bigger sample size demands more resources but reduces uncertainty in estimates.
Importance of Statistical Analysis
Statistical analysis is pivotal in making informed decisions based on data. It helps researchers and decision-makers discern patterns, test hypotheses, and derive meaningful conclusions from sample data. In the context of our exercise, statistical analysis allows us to determine confidence intervals and calculate margins of error, giving us crucial insights into environmental contamination levels.
By analyzing the sample data of plastic microparticles in sediment, researchers can infer the extent and variability of pollution on a broader scale, even with limited data from 18 different shorelines. This type of analysis is essential not only for environmental studies but across various fields where data-driven decisions are made.
Understanding and applying statistical techniques such as confidence intervals, hypothesis testing, and regression analysis can transform raw data into actionable insights, aiding in effective environmental management, policy formulation, and scientific advancements.

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Most popular questions from this chapter

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