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Find a \(95 \%\) confidence interval for the mean two ways: using StatKey or other technology and percentiles from a bootstrap distribution and using the t-distribution and the formula for standard error. Compare the results. Mean price of a used Mustang car online, in \$1000s, using data in MustangPrice with \(\bar{x}=15.98\), \(s=11.11,\) and \(n=25\)

Short Answer

Expert verified
The 95% confidence interval using the bootstrapping method will depend on the results from the bootstrapping software, while the 95% confidence interval using the t-distribution and standard error method is approximately (11.43, 20.53). If the bootstrap interval is similar to this, both methods have provided comparable results. Otherwise, this indicates some asymmetry or skewness in the bootstrap distribution.

Step by step solution

01

Bootstrapping Method

Using the bootstrap method means taking repeated samples from the observed dataset and computing the mean for each sample. By doing this, a distribution of means is created which can be used to find percentiles and thereby compute the 95% confidence interval. Bootstrapping uses a software, so the specific steps will depend on the software or technology being used. In general, the steps involve selecting the data, choosing a bootstrap sampling (with replacement), selecting the mean as the statistic, running the bootstrap for thousands of iterations, and finding the 2.5th and 97.5th percentiles of the bootstrap distribution.
02

T-distribution and Standard Error Method

First, the standard error (SE) is calculated using the formula \( SE = s / \sqrt{n} \) where s is the standard deviation and n is the sample size. In this case, \( SE = 11.11 / \sqrt{25} = 2.222 \). The t-distribution can then be used to find the critical t-value (t*) corresponding to a 95% confidence level with 24 degrees of freedom (n-1). Checking the t-table, t* is approximately 2.064. The confidence interval is then given by \( \bar{x} \pm t* * SE = 15.98 \pm 2.064 * 2.222 \). Therefore, the 95% confidence interval for the mean using the t-distribution and standard error is approximately (11.43, 20.53).
03

Compare the Results

Compare the 95% confidence intervals obtained from the bootstrapping and t-distribution methods. Consider whether they are approximately equal, which would suggest that the data follow a normal distribution and both methods yield similar results.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bootstrapping
Bootstrapping is a modern statistical method that uses resampling to approximate the sampling distribution of a statistic. It is a flexible and powerful technique, particularly useful when traditional assumptions about the population distribution are not met. The essence of bootstrapping lies in using the available data to make inferences about the population without relying heavily on parametric assumptions.

Here's how bootstrapping works:
  • Resampling: Random samples are drawn from the original dataset with replacement, meaning the same data points can be chosen multiple times in each iteration.
  • Sample Statistic: After each sampling, the desired statistic (such as the mean) is calculated for the sample.
  • Distribution: This process is repeated many times, often thousands, to create an empirical distribution of the statistic.
  • Percentiles: From this empirical distribution, you can find percentiles. For a 95% confidence interval, you typically look at the 2.5th and 97.5th percentiles.
By leveraging this resampling technique, bootstrapping can provide insights into the variability and distribution of sample statistics. It is particularly advantageous when the sample size is small or the data do not meet normality assumptions.
T-distribution
The t-distribution is a probability distribution used in statistics to estimate population parameters when the sample size is small or the population standard deviation is unknown. It is similar to the normal distribution but has heavier tails, making it more suitable for data samples where there's more variability or uncertainty.

Key features of the t-distribution include:
  • Degrees of Freedom: Its shape depends on the degrees of freedom, typically calculated as the sample size minus one (-1). With more degrees of freedom, the t-distribution resembles the normal distribution.
  • Critical Values: For constructing confidence intervals, critical t-values are used. These values depend on the desired confidence level and degrees of freedom.
When calculating a confidence interval using the t-distribution, you often follow these steps:Use the calculated mean and standard error of the sample.Determine the critical t-value from a t-table, appropriate for your degrees of freedom and confidence level.Construct the interval using the formula: \( \bar{x} \pm t^* \times SE \), where \(t^*\) is the critical t-value.The t-distribution provides reliable estimates for population means, particularly when sample sizes are limited.
Standard Error
The standard error (SE) is a key concept in statistics, providing a measure of how much sample means can be expected to vary. It quantifies the precision of the sample mean as an estimate of the population mean. The smaller the standard error, the more reliable the sample mean is likely to be.

Here's what you need to know about standard error:
  • Calculation: The standard error is calculated as the sample standard deviation divided by the square root of the sample size, \( SE = \frac{s}{\sqrt{n}} \).
  • Relation to Sample Size: As the sample size increases, the standard error generally decreases, indicating more reliable estimates of the population mean.
  • Role in Confidence Intervals: When calculating confidence intervals, the standard error helps determine the margin of error, providing insights into the uncertainty of the sample mean.
Standard error is a critical component when using the t-distribution to create confidence intervals. It provides insight into how representative the sample mean is concerning the true population mean.

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Most popular questions from this chapter

In the mid-1990s a Nabisco marketing campaign claimed that there were at least 1000 chips in every bag of Chips Ahoy! cookies. A group of Air Force cadets collected a sample of 42 bags of Chips Ahoy! cookies, bought from locations all across the country, to verify this claim. \({ }^{41}\) The cookies were dissolved in water and the number of chips (any piece of chocolate) in each bag were hand counted by the cadets. The average number of chips per bag was \(1261.6,\) with standard deviation 117.6 chips. (a) Why were the cookies bought from locations all over the country? (b) Test whether the average number of chips per bag is greater than 1000 . Show all details. (c) Does part (b) confirm Nabisco's claim that every bag has at least 1000 chips? Why or why not?

A \(99 \%\) confidence interval for \(\mu_{1}-\mu_{2}\) using the paired data in the following table: $$ \begin{array}{lccccc} \hline \text { Case } & \mathbf{1} & \mathbf{2} & \mathbf{3} & \mathbf{4} & \mathbf{5} \\ \hline \text { Treatment 1 } & 22 & 28 & 31 & 25 & 28 \\ \text { Treatment 2 } & 18 & 30 & 25 & 21 & 21 \\ \hline \end{array} $$

Standard Error from a Formula and Simulation In Exercises 6.15 to \(6.18,\) find the mean and standard error of the sample proportions two ways: (a) Use StatKey or other technology to simulate at least 1000 sample proportions. Give the mean and standard error and comment on whether the distribution appears to be normal. (b) Use the formulas in the Central Limit Theorem to compute the mean and standard error. Are the results similar to those found in part (a)? Sample proportions of sample size \(n=10\) from a population with \(p=0.2\)

On page 1 1 in Section \(1.1,\) we describe studies to investigate whether there is evidence of pheromones (subconscious chemical signals) in female tears that affect sexual arousal in men. In one of the studies, \(^{71} 50\) men had a pad attached to the upper lip that contained either female tears or a salt solution dripped down the same female's face. Each subject participated twice, on consecutive days, once with tears and once with saline, randomized for order, and doubleblind. Testosterone levels were measured before sniffing and after sniffing on both days. While normal testosterone levels vary significantly between different men, average levels for the group were the same before sniffing on both days and after sniffing the salt solution (about \(155 \mathrm{pg} / \mathrm{mL}\) ) but were reduced after sniffing the tears (about \(133 \mathrm{pg} / \mathrm{mL}\) ). The mean difference in testosterone levels after sniffing the tears was 21.7 with standard deviation \(46.5 .\) (a) Why did the investigators choose a matchedpairs design for this experiment? (b) Test to see if testosterone levels are significantly reduced after sniffing tears? (c) Can we conclude that sniffing female tears reduces testosterone levels (which is a significant indicator of sexual arousal in men)?

Impact of Sample Size on Accuracy Compute the standard error for sample proportions from a population with proportion \(p=0.4\) for sample sizes of \(n=30, n=200,\) and \(n=1000 .\) What effect does increasing the sample size have on the standard error? Using this information about the effect on the standard error, discuss the effect of increasing the sample size on the accuracy of using a sample proportion to estimate a population proportion.

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