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A \(90 \%\) confidence interval for \(\mu\) using the sample results \(\bar{x}=137.0, s=53.9,\) and \(n=50\)

Short Answer

Expert verified
The 90% confidence interval for \( \mu \) given the sample results is approximately \( (122.32, 151.68) \).

Step by step solution

01

Identify Given Parameters

First, identify all given parameters. These include: sample mean \( \bar{x}=137.0 \), standard deviation \( s=53.9 \), and the sample size \( n=50 \).
02

Find the Z-Score

Now, find the z-score corresponding to the desired 90% confidence level. You use a Z-table or a calculator for this, the z-score for 90% confidence is found to be approximately 1.645.
03

Use Confidence Interval Formula

Now apply the z-score and the given parameters into the formula \( \bar{x} \pm z \cdot \frac{s}{\sqrt{n}} \) to find the confidence interval.
04

Calculate the Confidence Interval

Calculate the confidence interval using the values identified in the previous steps: \( \bar{x} \pm z \cdot \frac{s}{\sqrt{n}} = 137.0 \pm 1.645 \cdot \frac{53.9}{\sqrt{50}} \). Solving this gives the confidence interval as approximately \( (122.32, 151.68) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
Understanding the sample mean is crucial when dealing with statistical analysis. The sample mean represents the average value in a sample and is denoted as \( \bar{x} \). It's calculated by adding up all the observed values and dividing by the number of observations. For example, if we measured the heights of 50 people and found the average height to be 137.0 cm, that number is the sample mean of our dataset.

In the context of confidence intervals, the sample mean serves as the central point from which we measure the range of values that, with a specific level of confidence, we believe contains the true population mean \( \mu \). The accuracy of our confidence interval greatly depends on the reliability of our sample mean, which is why the method of collecting the sample and the size of the sample are pivotal.
Standard Deviation
The standard deviation is a measure of the amount of variation or dispersion in a set of values. A low standard deviation indicates that the values tend to be close to the mean (also the average) of the set, while a high standard deviation indicates that the values are spread out over a wider range. In our example, a standard deviation \( s \) of 53.9 means that the individual measures of height vary, on average, by 53.9 cm from the sample mean (137.0 cm).

When calculating confidence intervals, the standard deviation is used to determine the range of the interval. The standard deviation reflects the precision of the sample mean - the smaller the standard deviation, the more precise the sample mean and the narrower the confidence interval.
Sample Size
The sample size, often denoted as \( n \), plays a pivotal role in statistical inference. It represents the number of independent observations in the sample. The larger the sample size, the more representative it's likely to be of the population. This is because a larger sample tends to average out the randomness and capture the true characteristics of the population.

In our scenario with a sample size of 50, we are using a moderately sized sample to estimate the average height. The sample size affects the confidence interval through the margin of error - the component of the formula \( z \cdot \frac{s}{\sqrt{n}} \) that captures the precision of the estimate. Generally, larger sample sizes yield narrower confidence intervals, implying greater precision of the sample mean to estimate the population mean.
Z-Score
The z-score is a statistical measurement that describes a value's relationship to the mean of a group of values, measured in terms of standard deviations. It's often used in the context of standard normal distributions. For confidence intervals, the z-score corresponds to the desired level of confidence and indicates how many standard deviations an element is from the mean.

For a 90% confidence interval, as seen in the example, the z-score is approximately 1.645. This means the range of the confidence interval extends 1.645 standard deviations above and below the sample mean. Thus, the formula to calculate the confidence interval integrates the sample mean, standard deviation, and the z-score to capture where the true mean \( \mu \) likely resides with 90% certainty.

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Most popular questions from this chapter

In Exercises 6.1 to \(6.6,\) if random samples of the given size are drawn from a population with the given proportion: (a) Find the mean and standard error of the distribution of sample proportions. (b) If the sample size is large enough for the Central Limit Theorem to apply, draw a curve showing the shape of the sampling distribution. Include at least three values on the horizontal axis. Samples of size 1000 from a population with proportion 0.70

Difference in mean commuting time (in minutes) between commuters in Atlanta and commuters in St. Louis, using \(n_{1}=500, \bar{x}_{1}=29.11,\) and \(s_{1}=20.72\) for Atlanta and \(n_{2}=500, \bar{x}_{2}=21.97,\) and \(s_{2}=14.23\) for St. Louis.

NBA Free Throws In Exercise 6.10, we learn that the percent of free throws made in the \(\mathrm{NBA}\) (National Basketball Association) has been about \(75 \%\) for the last 50 years. If we take random samples of free throws in the NBA and compute the proportion of free throws made, what percent of samples of size \(n=200\) will have a sample proportion greater than \(80 \%\) ? Use the fact that the sample proportions are normally distributed and compute the mean and standard deviation of the distribution.

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Use StatKey or other technology to generate a bootstrap distribution of sample means and find the standard error for that distribution. Compare the result to the standard error given by the Central Limit Theorem, using the sample standard deviation as an estimate of the population standard deviation. Mean commute time in Atlanta, in minutes, using the data in CommuteAtlanta with \(n=500\), \(\bar{x}=29.11,\) and \(s=20.72\)

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