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In Exercises 6.1 to \(6.6,\) if random samples of the given size are drawn from a population with the given proportion: (a) Find the mean and standard error of the distribution of sample proportions. (b) If the sample size is large enough for the Central Limit Theorem to apply, draw a curve showing the shape of the sampling distribution. Include at least three values on the horizontal axis. Samples of size 50 from a population with proportion 0.25

Short Answer

Expert verified
The mean of the distribution of sample proportions is 0.25. The standard error of the distribution of sample proportions is approximately 0.069. As per the Central Limit Theorem, the distribution curve will be a normal curve, centered on 0.25 with dispersion determined by the standard error of 0.069.

Step by step solution

01

Calculate the mean

The formula for the mean (usually denoted by \(\mu_p\)) of the sampling distribution of a proportion is equal to the proportion of the population, which is given as 0.25. Hence, \(\mu_p = 0.25\).
02

Calculate the standard error

The standard error (usually denoted by \(SE_p\)) of the sampling distribution of a proportion is calculated by the formula \(\sqrt{(p(1 - p) / n)}\) where 'p' is the population proportion and 'n' is the sample size. Substituting p = 0.25 and n = 50 into the formula gives \(SE_p = \sqrt{(0.25 * (1 - 0.25)) / 50} = 0.069\).
03

Apply Central Limit Theorem and draw the curve

According to the Central Limit Theorem, we can assume the distribution is approximately normal if the sample size is large enough. The condition for this is np > 5 and n(1-p) > 5. Here, np = 12.5 and n(1-p) = 37.5, which are both greater than 5. Therefore, the Central Limit Theorem applies here and the distribution can be assumed as normal. Thus, we can plot a curve which would be bell-shaped with its high point at the mean, which is 0.25 in this case, and dispersion determined by the standard error, 0.069. The horizontal line would include three points, at least one marker less than 0.25 and one greater than 0.25 to show the spread of the normal distribution.
04

Drawing the Curve

The curve can be drawn either using a computer software or manually. Start by setting a range for the horizontal axis that includes the mean (0.25) as its center. Then, the other two values can be decided by adding and subtracting the standard error (0.069) from the mean. The curve should peak at the mean and spread out symmetrically around it.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean of Sample Proportions
The mean of sample proportions is a fundamental concept in statistics, especially when discussing sampling distributions. It represents the average value of proportions obtained from random samples drawn from a population.
In the context of the Central Limit Theorem, the mean of the sampling distribution of sample proportions is equal to the population proportion itself.
When you hear "mean of sample proportions," think about the expected value of taking many samples from a given population and finding their average proportion.
  • In our example, the population proportion is 0.25.
  • Therefore, the mean of sample proportions, denoted as \(\mu_p\), is also 0.25.
This shows that the mean of sample proportions does not change, remaining consistent with the population proportion. Thus, it's predictable and serves as a foundation for further statistical analysis.
Standard Error
Standard error is a critical measure in sampling distributions. It quantifies the variation or "spread" of sample proportions relative to the population proportion.
The formula used to calculate the standard error (SE) in proportion sampling is:\[SE_p = \sqrt{\frac{p(1-p)}{n}}\]where:
  • \(p\) is the population proportion,
  • \(n\) is the sample size.
In our given example, with a population proportion \(p = 0.25\) and a sample size \(n = 50\), calculations yield:\[SE_p = \sqrt{\frac{0.25 \times (1 - 0.25)}{50}} = 0.069\]This indicates the standard error is approximately 0.069.
It tells us how much the sample proportions are expected to vary around the mean proportion of 0.25.
A smaller standard error signifies that the sample proportions are closely clustered around the mean, whereas a larger standard error indicates more spread out sample proportions.
Sampling Distribution
Sampling distribution is a distribution of all possible sample proportions from a population. When analyzing sample data, it becomes vital to understand its shape and spread.
For large enough sample sizes, the Central Limit Theorem helps by indicating that the sampling distribution of sample proportions can be approximated as a normal distribution, even if the original population does not follow a normal distribution.
In our example, the sampling distribution of a sample of 50 from a population with a proportion of 0.25 will resemble a normal curve.
  • We check the conditions: \( np > 5 \) and \( n(1-p) > 5 \).
  • Here, \( np = 12.5 \) and \( n(1-p) = 37.5 \), both exceeding 5.
  • Thus, the Central Limit Theorem is applicable.
The normal curve would center at the mean, 0.25, with a standard deviation (width) determined by the standard error, 0.069.
Visually, depict this with a curve peaking at the mean and symmetrically descending on either side. Points selected on the horizontal axis (e.g., 0.181, 0.25, 0.319) correlate to \(0.25 \pm 0.069\), helping illustrate the spread and variation in sampling.

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