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In Exercises 5.44 to 5.49 , find the indicated confidence interval. Assume the standard error comes from a bootstrap distribution that is approximately normally distributed. A \(95 \%\) confidence interval for a mean \(\mu\) if the sample has \(n=50\) with \(\bar{x}=72\) and \(s=12,\) and the standard error is \(S E=1.70\)

Short Answer

Expert verified
The 95% confidence interval for the mean \(\mu\) is \([68.668, 75.332]\).

Step by step solution

01

Identify the Given Values

For the given problem, the sample size \(n=50\), the sample mean \(\bar{x} = 72\), the standard deviation \(s=12\), and the standard error \(SE = 1.70\). The desired confidence level is 95%. Given that this is a normal distribution, the z-value for a 95% confidence level is 1.96 (This is found in a standard normal distribution table).
02

Apply the Confidence Interval Formula

The formula for a confidence interval is given as \(\bar{x} \pm z \times SE\). Here, \(\bar{x} = 72\), \(z = 1.96\), and \(SE = 1.70\). This gives us \(72 \pm 1.96 \times 1.70\).
03

Calculate the Confidence Interval

Substitute \(z\) and \(SE\) into the formula, and perform the multiplication and addition/subtraction to find the confidence interval. \(72 \pm 1.96 \times 1.70\) gives \(72 \pm 3.332\), or a 95% confidence interval of \([68.668, 75.332]\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bootstrap Distribution
Bootstrap distribution is a powerful statistical method used to estimate the sampling distribution of a statistic by resampling with replacement from the original data set. It's like having another chance to gather data, but instead of going back to the field, you use the data you have. This technique is particularly useful when the original sample may not represent a perfectly normally distributed population.

To create a bootstrap distribution, you repeatedly sample from your data to create 'bootstrap samples'. Then, calculate the statistic of interest, such as a mean or median, for each of these samples. These statistics provide a distribution – the bootstrap distribution – that approximates the sampling distribution of that statistic.
  • This approach is non-parametric, meaning it doesn't assume a specific distribution for the data.
  • It helps assess the variability or spread of statistics and is robust even with small sample sizes.
  • Using the bootstrap method, you can derive confidence intervals without relying solely on traditional approaches, which might have stricter assumptions.
Understanding bootstrap distributions allows you to gain insights into the reliability and stability of your statistical estimates.
Standard Error
The standard error (SE) is an incredibly important concept when it comes to inferential statistics. It essentially measures how far the sample mean of the data is likely to be from the true population mean. Imagine you're attempting to predict the real value from a smaller group – the standard error tells you how much "wiggle room" you have in that prediction.

Standard error is calculated by dividing the standard deviation (s) of the sample by the square root of the sample size (n), as shown by the formula:\[SE = \frac{s}{\sqrt{n}}\]This equation highlights how the standard error decreases as the sample size increases, which suggests more data means more precision in estimates. Here are some key points to consider about standard error:
  • It provides the basis for constructing confidence intervals around sample estimates.
  • As the sample size grows, the SE gets smaller, indicating increased reliability of the mean.
  • The SE can be used to understand the precision of sample statistics, serving as a measure of sampling variability.
This concept is pivotal for interpreting statistical analysis results, especially when deciding how closely your sample reflects the broader population.
Normal Distribution
The normal distribution, often referred to as the bell curve or Gaussian distribution, is a fundamental concept in statistics due to its natural occurrence in many datasets. It's symmetric, meaning it has equal weight on the left and right of the mean, which is why it's visually identifiable with its characteristic bell shape. The beauty of normal distribution lies in its ability to capture the idea that most occurrences take place around the average.

A key property of a normal distribution is that it is completely described by its mean and standard deviation, denoting how data is spread around the mean.
  • Approximately 68% of data lies within one standard deviation of the mean.
  • About 95% falls within two standard deviations of the mean.
  • Almost 99.7% is within three standard deviations, showcasing the rare outliers.
These percentages are essential when considering confidence intervals in normally distributed data. For example, a 95% confidence interval is constructed by considering values within two standard deviations from the mean, providing insights into where the true mean of the population likely falls.

Understanding the normal distribution allows statisticians to apply the Central Limit Theorem, which states that the sampling distribution of the sample mean will be normal or nearly normal, if sample size is large enough. This principle is foundational for many statistical methods used in hypothesis testing and confidence interval calculations.

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Most popular questions from this chapter

Exercises 5.50 to 5.55 include a set of hypotheses, some information from one or more samples, and a standard error from a randomization distribution. Find the value of the standardized \(z\) -test statistic in each situation. Test \(H_{0}: \mu=80\) vs \(H_{a}: \mu>80\) when the sample has \(n=20, \bar{x}=82.4\), and \(s=3.5,\) with \(S E=0.8\).

Random Samples of College Degree Proportions In Exercise \(5.29,\) we see that the distribution of sample proportions of US adults with a college degree for random samples of size \(n=500\) is \(N(0.275,0.02) .\) How often will such samples have a proportion, \(\hat{p},\) that is more than \(0.30 ?\)

Commuting Times in St. Louis A bootstrap distribution of mean commute times (in minutes) based on a sample of \(500 \mathrm{St}\). Louis workers stored in CommuteStLouis is shown in Figure 5.13 . The pattern in this dotplot is reasonably bell-shaped so we use a normal curve to model this distribution of bootstrap means. The mean for this distribution is 21.97 minutes and the standard deviation is 0.65 minutes. Based on this normal distribution, what proportion of bootstrap means should be in each of the following regions? (a) More than 23 minutes (b) Less than 20 minutes (c) Between 21.5 and 22.5 minutes

(a) The area to the left of the endpoint on a \(N(100,15)\) curve is about \(0.75 .\) (b) The area to the right of the endpoint on a \(N(8,1)\) curve is about 0.03 .

Empirical Rule for Normal Distributions Pick any positive values for the mean and the standard deviation of a normal distribution. Use your selection of a normal distribution to answer the questions below. The results of parts (a) to (c) form what is often called the Empirical Rule for the standard deviation in a normal distribution. (a) Verify that about \(95 \%\) of the values fall within two standard deviations of the mean. (b) What proportion of values fall within one standard deviation of the mean? (c) What proportion of values fall within three standard deviations of the mean? (d) Will the answers to (b) and (c) be the same for any normal distribution? Explain why or why not.

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