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In Exercises 4.146 to \(4.149,\) hypotheses for a statistical test are given, followed by several possible confidence intervals for different samples. In each case, use the confidence interval to state a conclusion of the test for that sample and give the significance level used. Hypotheses: \(H_{0}: \mu_{1}=\mu_{2}\) vs \(H_{a}: \mu_{1} \neq \mu_{2} .\) In addition, in each case for which the results are significant, state which group ( 1 or 2 ) has the larger mean. (a) \(95 \%\) confidence interval for \(\mu_{1}-\mu_{2}:\) $$ 0.12 \text { to } 0.54 $$ (b) \(99 \%\) confidence interval for \(\mu_{1}-\mu_{2}\) : -2.1 to 5.4 (c) \(90 \%\) confidence interval for \(\mu_{1}-\mu_{2}\) : -10.8 to -3.7

Short Answer

Expert verified
For scenario (a), we reject the null hypothesis and group 1 has a larger mean. In scenario (b), we cannot reject the null hypothesis and we can't decisively determine which group has a larger mean. For scenario (c), we reject the null hypothesis, and group 2 has a larger mean.

Step by step solution

01

Understanding the Hypotheses

The null hypothesis is that the mean of population 1 \(\mu_1=\mu_2\), that is, it is equal to that of population 2. And, the alternative hypothesis is that the means are not equal, denoted by \(\mu_1 \neq \mu_2\). A confidence interval provides a range in which we can be certain that the true value lies, given a certain level of confidence.
02

Evaluating Confidence Interval (a)

In scenario (a), the 95% confidence interval for \(\mu_{1}-\mu_{2}\) is from 0.12 to 0.54, which doesn't include 0. This signifies that the difference of means is not 0 and we reject the null hypothesis in favor of the alternative hypothesis. Since the interval is positive, group 1 has a larger mean than group 2.
03

Evaluating Confidence Interval (b)

In scenario (b), the 99% confidence interval for \(\mu_{1}-\mu_{2}\) ranges from -2.1 to 5.4. It includes 0 which suggests that no significant difference between the means. Hence, the null hypothesis is not rejected in this case. As the interval includes both negative and positive values, we cannot make a decisive statement about which group has a larger mean.
04

Evaluating Confidence Interval (c)

In scenario (c), the 90% confidence interval for \(\mu_{1}-\mu_{2}\) ranges from -10.8 to -3.7. It does not include 0, hence, we reject the null hypothesis in favor of the alternative hypothesis. As the value is negative, it signifies that group 2 has a larger mean value than group 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
When we talk about a confidence interval, we are referring to a range of values that, statistically speaking, is likely to contain the true mean of a population. This interval is based on sampled data and a given confidence level—commonly 90%, 95%, or 99%.

For example, if we have a 95% confidence interval for the difference of two means, like \(0.12 \) to \(0.54\), we are saying that we are 95% confident that the actual difference between these two populations' means lies within this interval. If zero falls outside of this interval, we infer that there is a significant difference between the two means, as zero would represent no difference. Conversely, if the interval does contain zero, we might conclude that we have no evidence to support that the means are different at that confidence level.
Null Hypothesis
The null hypothesis (denoted as \(H_0\)) is a default statement that there is no effect or no difference in a statistical test. It is what we assume to be true before collecting any data. In the case of comparing two means, as in the given exercise, the null hypothesis claims that the two population means are equal, represented by \(\mu_1=\mu_2\).

The importance of the null hypothesis lies in providing a baseline or a point of comparison. During hypothesis testing, we try to determine whether there is enough evidence, from our sample, to reject the null hypothesis in favor of an alternative.
Alternative Hypothesis
In contrast to the null hypothesis, the alternative hypothesis (denoted as \(H_a\) or \(H_1\)) represents what we want to prove or suspect is true based on our sample data. For the exercise, the alternative hypothesis is that there is a difference between the two population means, indicated as \(\mu_1 eq \mu_2\).

If the confidence interval does not include the value specified by the null hypothesis (in this case, zero for the difference of means), we then have evidence to support the alternative hypothesis. Statistical tests are designed to determine whether the null hypothesis can be rejected in order to favor the alternative hypothesis.
Statistical Significance
The term statistical significance indicates the likelihood that the difference inferred from a sample is not due to random chance within the context of a hypothesis test. The significance level, typically set at 0.05 (5%), corresponds to the risk we are willing to take of wrongly rejecting the null hypothesis.

A confidence interval that does not contain the value of zero in the context of mean comparison suggests that there is a statistically significant difference. As in the exercise solutions, a 95% confidence interval that excludes zero shows significant difference, meaning we have evidence beyond the 5% significance level to reject the null hypothesis.
Mean Comparison
The process of mean comparison involves looking at the differences between means from different groups or populations. In hypothesis testing, mean comparison helps us to understand if these differences are likely to have occurred by chance, or if they are statistically significant.

By calculating the confidence interval for \(\mu_1-\mu_2\), we assess the magnitude and the direction of the difference. A positive interval suggests that the first group has a larger mean, while a negative interval suggests the opposite. In the provided exercise, case (a) indicates that \(\mu_1\) is larger than \(\mu_2\) since the interval is positive, while in (c) \(\mu_2\) is larger due to the negative interval.

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