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Watch Out for Lions after a Full Moon Scientists studying lion attacks on humans in Tanzania \(^{34}\) found that 95 lion attacks happened between \(6 \mathrm{pm}\) and \(10 \mathrm{pm}\) within either five days before a full moon or five days after a full moon. Of these, 71 happened during the five days after the full moon while the other 24 happened during the five days before the full moon. Does this sample of lion attacks provide evidence that attacks are more likely after a full moon? In other words, is there evidence that attacks are not equally split between the two five-day periods? Use StatKey or other technology to find the p-value, and be sure to show all details of the test. (Note that this is a test for a single proportion since the data come from one sample.)

Short Answer

Expert verified
The exact p-value depends on the calculated test statistic. However, after computing the p-value, if it is less than 0.05, we conclude that there is significant evidence that lion attacks are more likely after a full moon. If the p-value is greater than 0.05, we conclude that there is not enough evidence to suggest that lion attacks occur more frequently after a full moon.

Step by step solution

01

Compute Observed Proportions

Firstly, total observed lion attacks are 95. Out of these, 71 are after a full moon. An observed proportion after a full moon is calculated by dividing the number of attacks after a full moon by the total number of attacks, which results in \(\frac{71}{95}=0.747\)
02

State the Null and Alternative Hypotheses

The null hypothesis, \(H_0\), is that lion attacks are equally likely before and after a full moon, meaning the proportion is 0.5. The alternative hypothesis, \(H_1\), is that attacks are more likely after a full moon, meaning the proportion is more than 0.5.
03

Perform the Hypothesis Test

To perform the test, we use the following formula to calculate the test statistic: \(Z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}\), where \(\hat{p}\) is the observed proportion (0.747), \(p_0\) is the assumed proportion under null hypothesis (0.5), and n is the total number of observations (95). Plug in these values to calculate the test statistic.
04

Calculate the P-Value

Use the test statistic value obtained from Step 3 to calculate the p-value. Note that because this is a one-tailed test with the alternative hypothesis stating the observed proportion is more than 0.5, so we need to find the probability that the Z is greater than the observed test statistic. You can use statistical software, such as StatKey or other technology to find the p-value.
05

Conclusion

Interpret the p-value: If the p-value is less than 0.05 (a common threshold), reject the null hypothesis and conclude there is significant evidence to suggest that more lion attacks occur after a full moon than otherwise as per our sample data. If the p-value is greater than 0.05, do not reject the null hypothesis - there is not enough evidence in our sample to suggest that lion attacks occur more frequently after a full moon.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing, the null hypothesis is a statement or assumption that indicates there is no effect or no difference between groups or conditions. It serves as a starting point for statistical testing and is often denoted as \(H_0\). In our example of lion attacks, the null hypothesis assumes that the attacks are equally likely before and after a full moon. This means we expect the proportion of attacks during both periods to be equal, or more specifically, a 50% probability for each period.

To represent this mathematically, our null hypothesis is: \(H_0: p = 0.5\). Here, \(p\) represents the proportion of lion attacks occurring after a full moon. By testing the null hypothesis, we seek to determine if observed data significantly deviate from this assumption. If our statistical analysis results in rejecting the null hypothesis, we conclude that there is sufficient evidence for a potential difference or effect.
Alternative Hypothesis
The alternative hypothesis offers a different perspective from the null hypothesis, suggesting that there is indeed a difference or effect. It is generally denoted by \(H_1\) or \(H_a\). In the context of our exercise, the alternative hypothesis posits that more lion attacks occur after a full moon than before. This implies the proportion of attacks during the period following a full moon is greater than 50%.

Mathematically, our alternative hypothesis is: \(H_1: p > 0.5\). This hypothesis supports the idea that lion behavior, and consequently the frequency of attacks on humans, changes in relation to the lunar cycle. When we conduct our test, we compare the observed data against this alternative view, using evidence provided by the data to accept or reject the null hypothesis. An acceptance of \(H_1\) means there is significant evidence supporting more attacks post-full moon.
P-Value
In hypothesis testing, the p-value is a crucial concept that provides the probability of observing data as extreme as, or more extreme than, the observed data under the assumption that the null hypothesis is true. It serves as a measure of the strength of the evidence against the null hypothesis. Essentially, the smaller the p-value, the stronger the evidence against \(H_0\).

In our exercise involving lion attacks, after calculating the test statistic, the p-value helps us decide whether our observed proportion of 0.747 (attacks after a full moon) offers robust evidence to refute the null hypothesis of equal probability (0.5). A typical significance level used is 0.05. If the p-value is less than 0.05, we reject the null hypothesis, inferring that there is substantial evidence to suggest that more lion attacks occur after a full moon. Conversely, a p-value greater than 0.05 implies insufficient evidence to reject \(H_0\), indicating no strong proof of an increased attack rate post-full moon based on our sample.

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Most popular questions from this chapter

In Exercises 4.5 to 4.8 , state the null and alternative hvpotheses for the statistical test described. Testing to see if there is evidence that the mean of group \(\mathrm{A}\) is not the same as the mean of group \(\mathrm{B}\).

Testing for a Home Field Advantage in Soccer In Exercise 3.108 on page \(215,\) we see that the home team was victorious in 70 games out of a sample of 120 games in the FA premier league, a football (soccer) league in Great Britain. We wish to investigate the proportion \(p\) of all games won by the home team in this league. (a) Use StatKey or other technology to find and interpret a \(90 \%\) confidence interval for the proportion of games won by the home team. (b) State the null and alternative hypotheses for a test to see if there is evidence that the proportion is different from 0.5 . (c) Use the confidence interval from part (a) to make a conclusion in the test from part (b). State the confidence level used. (d) Use StatKey or other technology to create a randomization distribution and find the p-value for the test in part (b). (e) Clearly interpret the result of the test using the p-value and using a \(10 \%\) significance level. Does your answer match your answer from part (c)? (f) What information does the confidence interval give that the p-value doesn't? What information does the p-value give that the confidence interval doesn't? (g) What's the main difference between the bootstrap distribution of part (a) and the randomization distribution of part (d)?

Definition of a P-value Using the definition of a p-value, explain why the area in the tail of a randomization distribution is used to compute a p-value.

Beer and Mosquitoes Does consuming beer attract mosquitoes? A study done in Burkino Faso, Africa, about the spread of malaria investigated the connection between beer consumption and mosquito attraction. \(^{9}\) In the experiment, 25 volunteers consumed a liter of beer while 18 volunteers consumed a liter of water. The volunteers \({ }^{8}\) Bouchard, M., Bellinger, D., Wright, \(\mathrm{R}\), and Weisskopf, M. "Attention-Deficit/Hyperactivity Disorder and Urinary Metabolites of Organophosphate Pesticides," Pediatrics, \(2010 ; 125:\) e1270-e1277. \({ }^{9}\) Lefvre, T., et al., "Beer Consumption Increases Human Attractiveness to Malaria Mosquitoes," PLoS ONE, 2010; 5(3): e9546.were assigned to the two groups randomly. The attractiveness to mosquitoes of each volunteer was tested twice: before the beer or water and after. Mosquitoes were released and caught in traps as they approached the volunteers. For the beer group, the total number of mosquitoes caught in the traps before consumption was 434 and the total was 590 after consumption. For the water group, the total was 337 before and 345 after. (a) Define the relevant parameter(s) and state the null and alternative hypotheses for a test to see if, after consumption, the average number of mosquitoes is higher for the volunteers who drank beer. (b) Compute the average number of mosquitoes per volunteer before consumption for each group and compare the results. Are the two sample means different? Do you expect that this difference is just the result of random chance? (c) Compute the average number of mosquitoes per volunteer after consumption for each group and compare the results. Are the two sample means different? Do you expect that this difference is just the result of random chance? (d) If the difference in part (c) is unlikely to happen by random chance, what can we conclude about beer consumption and mosquitoes? (e) If the difference in part (c) is statistically significant, do we have evidence that beer consumption increases mosquito attraction? Why or why not?

In Exercises 4.71 to \(4.74,\) using the p-value given, are the results significant at a \(10 \%\) level? At a \(5 \%\) level? At a 1\% level? $$ \text { p-value }=0.0320 $$

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