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Flipping Coins We flip a coin 150 times and get 90 heads, so the sample proportion of heads is \(\hat{p}=90 / 150=0.6 .\) To test whether this provides evidence that the coin is biased, we create a randomization distribution. Where will the distribution be centered? Why?

Short Answer

Expert verified
The randomization distribution will be centered at 0.5, as this is the expected proportion of heads under the null hypothesis that the coin is fair and not biased.

Step by step solution

01

Understand the concept of randomization distribution

Randomization distribution is produced by simulating, or replicating, the experiment over and over again assuming the null hypothesis is true, and then recording the statistic of interest (in this case, the proportion of head) from each of the replicated experiments to produce a distribution.
02

State the null hypothesis for the proportion

In this case, the null hypothesis would be that the coin is unbiased, meaning that there is an equal probability, i.e. 0.5, of getting heads or tails in any given flip.
03

Determine where the randomization distribution will be centered

A randomization distribution is expected to be centered at the null hypothesis value. In this case, assuming the coin is unbiased (null hypothesis), the expected proportion of heads is 0.5. Therefore, the randomization distribution will be centered at 0.5.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
When working with experiments like coin flips, the sample proportion is a critical concept to grasp. A sample proportion is a measure that represents the ratio of times an event occurs relative to the total number of trials. For example, in the context of flipping a coin 150 times, we are measuring how many of those flips result in heads.
In the example, we obtained heads 90 times out of 150 flips. This means our sample proportion, denoted as \( \hat{p} \), is calculated as follows:\[ \hat{p} = \frac{90}{150} = 0.6 \]This value is a way of summarizing our data and can be really helpful when analyzing whether our coin behaves as expected, or if perhaps it is biased. A sample proportion is a practical tool for summarizing data from a series of trials and is foundational in conducting hypothesis tests.
Null Hypothesis
The concept of a null hypothesis is foundational in statistical testing. It sets a benchmark expectation under which the randomization distribution is centered. The null hypothesis is essentially a statement of 'no effect' or 'no difference.' It provides a point of comparison against which we measure the outcome of our experiment.
In the context of flipping a coin, the null hypothesis would be that the coin is fair. That means there is an equal probability of landing on heads or tails, mathematically expressed as a probability of 0.5 for heads.
When we establish this null hypothesis, we are assuming there is no bias in the coin. Thus, any deviation from this hypothesis in our observed sample proportion might suggest that the coin could be biased, but we need statistical tests to confirm it.
Statistical Evidence
Statistical evidence is crucial when we want to determine whether the results of our experiments are significant or merely due to chance. It allows us to make objective conclusions based on the data collected.
To gather statistical evidence in our coin flip example, we generate a randomization distribution. This is done by simulating the experiment multiple times under the assumption that the null hypothesis is true. In this example, we assume the coin is fair, so the expected proportion of heads in our randomization distribution should be 0.5.
If the sample proportion from our actual experiment (0.6) is significantly different from this expected value, and falls outside the common range of simulated proportions, we may obtain enough statistical evidence to reject the null hypothesis. This would indicate that the observed data (90 heads out of 150 flips) is unlikely to have occurred by random chance alone and suggests bias in the coin.

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Most popular questions from this chapter

Arsenic in Chicken Data 4.5 on page 228 introduces a situation in which a restaurant chain is measuring the levels of arsenic in chicken from its suppliers. The question is whether there is evidence that the mean level of arsenic is greater than 80 ppb, so we are testing \(H_{0}: \mu=80\) vs \(H_{a}: \mu>80\), where \(\mu\) represents the average level of arsenic in all chicken from a certain supplier. It takes money and time to test for arsenic so samples are often small. Suppose \(n=6\) chickens from one supplier are tested, and the levels of arsenic (in ppb) are: \(68, \quad 75\) 81, \(\quad 93\) 134 (a) What is the sample mean for the data? (b) Translate the original sample data by the appropriate amount to create a new dataset in which the null hypothesis is true. How do the sample size and standard deviation of this new dataset compare to the sample size and standard deviation of the original dataset? (c) Write the six new data values from part (b) on six cards. Sample from these cards with replacement to generate one randomization sample. (Select a card at random, record the value, put it back, select another at random, until you have a sample of size \(6,\) to match the original sample size.) List the values in the sample and give the sample mean. (d) Generate 9 more simulated samples, for a total of 10 samples for a randomization distribution. Give the sample mean in each case and create a small dotplot. Use an arrow to locate the original sample mean on your dotplot.

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State the null and alternative hvpotheses for the statistical test described. Testing to see if there is evidence that a proportion is greater than 0.3

In Exercises 4.14 and \(4.15,\) determine whether the sets of hypotheses given are valid hypotheses. State whether each set of hypotheses is valid for a statistical test. If not valid, explain why not. (a) \(H_{0}: \mu=15 \quad\) vs \(\quad H_{a}: \mu \neq 15\) (b) \(H_{0}: p \neq 0.5 \quad\) vs \(\quad H_{a}: p=0.5\) (c) \(H_{0}: p_{1}p_{2}\) (d) \(H_{0}: \bar{x}_{1}=\bar{x}_{2} \quad\) vs \(\quad H_{a}: \bar{x}_{1} \neq \bar{x}_{2}\)

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