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In Exercises 4.112 to \(4.116,\) the null and alternative hypotheses for a test are given as well as some information about the actual sample(s) and the statistic that is computed for each randomization sample. Indicate where the randomization distribution will be centered. In addition, indicate whether the test is a left-tail test, a right-tail test, or a twotailed test. Hypotheses: \(H_{0}: p_{1}=p_{2}\) vs \(H_{a}: p_{1}>p_{2}\) Sample: \(\hat{p}_{1}=0.3, n_{1}=20\) and \(\hat{p}_{2}=0.167, n_{2}=12\) Randomization statistic \(=\hat{p}_{1}-\hat{p}_{2}\)

Short Answer

Expert verified
The randomization distribution will be centered at 0. The test is a right-tail test.

Step by step solution

01

Identify the Hypotheses and Expected Center

We have been given \(H_{0}: p_{1}=p_{2}\) and \(H_{a}: p_{1}>p_{2}\). This means we expect both proportions to be equal under the null hypothesis. The randomization distribution will be centered around 0. That's because if \(p_{1} = p_{2}\), then \(p_{1} - p_{2} = 0\).
02

Identify the Type of Test

The alternative hypothesis \(H_{a}: p_{1}>p_{2}\) stipulates that the first proportion is greater than the second. This makes it a right-tail test. You focus on the extreme right side of the distribution curve, where the observed values are significantly greater than what is expected under the null hypothesis.
03

Verify with Sample Data

The sample proportions given are \(\hat{p}_{1}=0.3\) and \(\hat{p}_{2}=0.167\) and the randomization statistic is \(\hat{p}_{1}-\hat{p}_{2}\), which equals 0.133. This positive value validates the previous findings, indicating that the test is indeed a right-tail test and p1 is possibly greater than p2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null and Alternative Hypotheses
Understanding the null and alternative hypotheses is crucial in statistics, particularly in hypothesis testing. These hypotheses are the backbone of any statistical test and guide the direction of your analysis.

The null hypothesis, denoted as \( H_0 \), represents a statement of no effect or no difference. It is a hypothesis of equality, and in our exercise, it states that \( p_1 = p_2 \), meaning the two population proportions are the same. The null hypothesis serves as a starting point for statistical significance testing.

In contrast, the alternative hypothesis, denoted as \( H_a \), is what you are trying to show evidence for in your study. It is a statement that indicates the presence of an effect or a difference. For the given exercise, the alternative hypothesis is \( p_1 > p_2 \), suggesting that the first proportion is larger than the second. The type of alternative hypothesis affects which kind of test we will use: left-tail, right-tail, or two-tailed test.

When conducting a hypothesis test, the goal is to determine if there is enough evidence in your sample data to reject the null hypothesis in favor of the alternative hypothesis. If the results are not significant, you fail to reject the null hypothesis, which is not the same as proving it true.
Randomization Distribution
The randomization distribution plays a vital role in understanding the expected outcomes under the null hypothesis. It is the theoretical distribution of outcomes that would result from applying the test statistic to all possible combinations of the observed data, assuming the null hypothesis is true.

In our exercise, since we are considering two proportions under the null hypothesis, where \( p_1 \)= \( p_2 \), the randomization distribution will be centered around 0. This zero center means that if the null hypothesis holds true, then no difference should exist between the two population proportions, and the mean of their distribution should equal 0.

When we use a test statistic, like \(\hat{p}_1 - \hat{p}_2\), we compare the observed statistic to this centered distribution to ascertain how extreme or typical our observed statistic is. The more extreme the observed statistic (far from 0 in either tail), the less likely it is to have occurred by random chance, and thus the stronger the evidence against the null hypothesis.
Right-Tail Test
Depending on the nature of the alternative hypothesis, a hypothesis test can be a right-tail, left-tail, or two-tailed test. In a right-tail test, we are interested in finding evidence that the test statistic is significantly larger than what we would expect if the null hypothesis was true.

In the context of our exercise, where the alternative hypothesis is \( H_a: p_1 > p_2 \), the test becomes a right-tail test. This is because we are looking for cases where \( \hat{p}_1 \) (the sample estimate for \( p_1 \)is greater than \( \hat{p}_2 \) (sample estimate for \( p_2 \). Our attention is therefore focused on the right-hand side of the randomization distribution, to observe if there is a significant area representing values as extreme or more extreme than our observed statistic.

A crucial output from this test is the p-value, which quantifies how extreme our observed results are. A small p-value (typically less than 0.05) suggests that our observed value is unlikely under the null hypothesis and hence provides evidence favoring the alternative hypothesis.

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Most popular questions from this chapter

Interpreting a P-value In each case, indicate whether the statement is a proper interpretation of what a p-value measures. (a) The probability the null hypothesis \(H_{0}\) is true. (b) The probability that the alternative hypothesis \(H_{a}\) is true. (c) The probability of seeing data as extreme as the sample, when the null hypothesis \(H_{0}\) is true. (d) The probability of making a Type I error if the null hypothesis \(H_{0}\) is true. (e) The probability of making a Type II error if the alternative hypothesis \(H_{a}\) is true.

Beer and Mosquitoes Does consuming beer attract mosquitoes? A study done in Burkino Faso, Africa, about the spread of malaria investigated the connection between beer consumption and mosquito attraction. \(^{9}\) In the experiment, 25 volunteers consumed a liter of beer while 18 volunteers consumed a liter of water. The volunteers \({ }^{8}\) Bouchard, M., Bellinger, D., Wright, \(\mathrm{R}\), and Weisskopf, M. "Attention-Deficit/Hyperactivity Disorder and Urinary Metabolites of Organophosphate Pesticides," Pediatrics, \(2010 ; 125:\) e1270-e1277. \({ }^{9}\) Lefvre, T., et al., "Beer Consumption Increases Human Attractiveness to Malaria Mosquitoes," PLoS ONE, 2010; 5(3): e9546.were assigned to the two groups randomly. The attractiveness to mosquitoes of each volunteer was tested twice: before the beer or water and after. Mosquitoes were released and caught in traps as they approached the volunteers. For the beer group, the total number of mosquitoes caught in the traps before consumption was 434 and the total was 590 after consumption. For the water group, the total was 337 before and 345 after. (a) Define the relevant parameter(s) and state the null and alternative hypotheses for a test to see if, after consumption, the average number of mosquitoes is higher for the volunteers who drank beer. (b) Compute the average number of mosquitoes per volunteer before consumption for each group and compare the results. Are the two sample means different? Do you expect that this difference is just the result of random chance? (c) Compute the average number of mosquitoes per volunteer after consumption for each group and compare the results. Are the two sample means different? Do you expect that this difference is just the result of random chance? (d) If the difference in part (c) is unlikely to happen by random chance, what can we conclude about beer consumption and mosquitoes? (e) If the difference in part (c) is statistically significant, do we have evidence that beer consumption increases mosquito attraction? Why or why not?

Influencing Voters: Is a Phone Call More Effective? Suppose, as in Exercise \(4.37,\) that we wish to compare methods of influencing voters to support a particular candidate, but in this case we are specifically interested in testing whether a phone call is more effective than a flyer. Suppose also that our random sample consists of only 200 voters, with 100 chosen at random to get the flyer and the rest getting a phone call. (a) State the null and alternative hypotheses in this situation. (b) Display in a two-way table possible sample results that would offer clear evidence that the phone call is more effective. (c) Display in a two-way table possible sample results that offer no evidence at all that the phone call is more effective. (d) Display in a two-way table possible sample results for which the outcome is not clear: There is some evidence in the sample that the phone call is more effective but it is possibly only due to random chance and likely not strong enough to generalize to the population.

In Exercises 4.112 to \(4.116,\) the null and alternative hypotheses for a test are given as well as some information about the actual sample(s) and the statistic that is computed for each randomization sample. Indicate where the randomization distribution will be centered. In addition, indicate whether the test is a left-tail test, a right-tail test, or a twotailed test. Hypotheses: \(H_{0}: p=0.5\) vs \(H_{a}: p<0.5\) Sample: \(\hat{p}=0.4, n=30\) Randomization statistic \(=\hat{p}\)

Determining Statistical Significance How small would a p-value have to be in order for you to consider results statistically significant? Explain. (There is no correct answer! This is just asking for your personal opinion. We'll study this in more detail in the next section.)

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