/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 Mix It Up for Better Learning In... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Mix It Up for Better Learning In preparing for a test on a set of material, is it better to study one topic at a time or to study topics mixed together? In one study, \(^{13}\) a sample of fourth graders were taught four equations. Half of the children learned by studying repeated examples of one equation at a time, while the other half studied mixed problem sets that included examples of all four types of calculations grouped together. A day later, all the students were given a test on the material. The students in the mixed practice group had an average grade of \(77,\) while the students in the one-at-a-time group had an average grade of \(38 .\) What is the best estimate for the difference in the average grade between fourth-grade students who study mixed problems and those who study each equation independently? Give notation (as a difference with a minus sign) for the quantity we are trying to estimate, notation for the quantity that gives the best estimate, and the value of the best estimate. Be sure to clearly define any parameters in the context of this situation.

Short Answer

Expert verified
The best estimate for the difference in the average grade between fourth-grade students who study mixed problems and those who study each equation independently is 39. The notation for the quantity we are trying to estimate is \(\Delta = \mu_1 - \mu_2\) where \(\mu_1\) is the average grade of the students who study mixed problems and \(\mu_2\) is the average grade of the students who study one equation at a time. The quantity that gives the best estimate is 39.

Step by step solution

01

Identify the quantities

First, identify the quantities given in the problem. The average grade for the mixed practice group is 77 and for the one-at-a-time group is 38.
02

Define the Parameters

Define \(\mu_1\) as the average grade of the students who study mixed problems and \(\mu_2\) as the average grade of the students who study one equation at a time.
03

Formulate the quantity we are trying to estimate

We are trying to estimate the difference in the average grades between the two groups of students, which can be denoted as \(\Delta = \mu_1 - \mu_2\).
04

Calculate the Difference

Subtract the average grade of the one-at-a-time group from the average grade of the mixed practice group to find the difference. \(\Delta = 77 - 38 = 39\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mixed Practice Learning
Mixed practice learning, also known as interleaved practice, is a study technique in which topics or types of problems are intermingled instead of being studied in isolation.

In the context of the exercise, two groups of fourth graders were taught equations using different methods. Those who studied through the mixed practice method (where different problems were grouped together) showed significantly better performance with an average grade of 77, compared to 38 from the group that studied one type of problem at a time.

Educational research suggests that mixed practice may improve learning by helping students to better integrate and discriminate between concepts. It can also enhance long-term retention and the ability to apply knowledge to new situations. Therefore, when preparing for tests, mixing different types of problems may be more beneficial than concentrating on one topic at a time.
Mathematics Education
Mathematics education entails teaching and learning mathematical principles, from elementary arithmetic to advanced calculus. It not only focuses on transmitting mathematical knowledge but also on fostering problem-solving skills and logical reasoning.

In the given exercise, mathematics education plays a key role as it shows the application of different teaching methods (mixed practice and single-topic study) in learning math equations. The notable difference in results between the two groups attests to the importance of instructional approaches in mathematics education. To optimize student learning outcomes, educators and curriculum developers must consider how various educational techniques align with the goals of mathematics education, including understanding abstract concepts, mastering computational skills, and developing critical thinking abilities.
Statistical Estimation
Statistical estimation involves using sample data to estimate population parameters. In the example from the exercise, we are estimating the difference in performance between two groups of students.

The quantity we aim to estimate is \(\Delta = \mu_1 - \mu_2\), where \(\mu_1\) and \(\mu_2\) represent the average grades of students who study mixed problems and those who study one equation at a time, respectively. The best estimate of this difference, based on our sample data, is 39 points.

This concept is essential in educational research and can be applied to a plethora of situations where making inferences about a larger group based on sample data is necessary. It underscores the importance of accurate data collection and interpretation in making informed decisions.
Educational Research
Educational research investigates teaching methods, learning processes, and the factors that affect education. It aims to improve educational practices and outcomes through methodical analysis and evidence-based strategies.

In the sample exercise, educational research helped to pinpoint the more effective learning strategy for students when dealing with math problems. By comparing the average grades of both groups, researchers could assess the impact of each teaching method.

Such research is crucial for guiding policy decisions, curriculum design, and teaching methods. It combines statistical analysis, like the estimation of differences in performance, with qualitative insights to provide a comprehensive understanding of the educational landscape.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Topical Painkiller Ointment The use of topical painkiller ointment or gel rather than pills for pain relief was approved just within the last few years in the US for prescription use only. \(^{12}\) Insurance records show that the average copayment for a month's supply of topical painkiller ointment for regular users is \(\$ 30 .\) A sample of \(n=75\) regular users found a sample mean copayment of \(\$ 27.90\). (a) Identify each of 30 and 27.90 as a parameter or a statistic and give the appropriate notation for each. (b) If we take 1000 samples of size \(n=75\) from the population of all copayments for a month's supply of topical painkiller ointment for regularusers and plot the sample means on a dotplot, describe the shape you would expect to see in the plot and where it would be centered. (c) How many dots will be on the dotplot you described in part (b)? What will each dot represent?

Are Female Rats More Compassionate Than Male Rats? Exercise 3.79 describes a study in which rats showed compassion by freeing a trapped rat. In the study, all six of the six female rats showed compassion by freeing the trapped rat while 17 of the 24 male rats did so. Use the results of this study to give a point estimate for the difference in proportion of rats showing compassion, between female rats and male rats. Then use StatKey or other technology to estimate the standard error \(^{39}\) and use it to compute an interval estimate for the difference in proportions. Use the interval to determine whether it is plausible that male and female rats are equally compassionate (i.e., that the difference in proportions is zero). The data are available in the dataset CompassionateRats.

What Proportion Believe in One True Love? In Data 2.1 on page \(46,\) we describe a study in which a random sample of 2625 US adults were asked whether they agree or disagree that there is "only one true love for each person." The study tells us that 735 of those polled said they agree with the statement. The standard error for this sample proportion is \(0.009 .\) Define the parameter being estimated, give the best point estimate, the margin of error, and find and interpret a \(95 \%\) confidence interval.

Give information about the proportion of a sample that agree with a certain statement. Use StatKey or other technology to find a confidence interval at the given confidence level for the proportion of the population to agree, using percentiles from a bootstrap distribution. StatKey tip: Use "CI for Single Proportion" and then "Edit Data" to enter the sample information. Find a \(99 \%\) confidence interval if, in a random sample of 1000 people, 382 agree, 578 disagree, and 40 can't decide.

A \(95 \%\) confidence interval is given, followed by possible values of the population parameter. Indicate which of the values are plausible values for the parameter and which are not. \(\mathbf{3 . 4 4}\) A \(95 \%\) confidence interval for a proportion is 0.72 to \(0.79 .\) Is the value given a plausible value of \(p ?\) (a) \(p=0.85\) (b) \(p=0.75\) (c) \(p=0.07\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.