/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Scientists are working to train ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Scientists are working to train dogs to smell cancer, including early stage cancer that might not be detected with other means. In previous studies, dogs have been able to distinguish the smell of bladder cancer, lung cancer, and breast cancer. Now, it appears that a dog in Japan has been trained to smell bowel cancer. \({ }^{12}\) Researchers collected breath and stool samples from patients with bowel cancer as well as from healthy people. The dog was given five samples in each test, one from a patient with cancer and four from healthy volunteers. The dog correctly selected the cancer sample in 33 out of 36 breath tests and in 37 out of 38 stool tests. (a) The cases in this study are the individual tests. What are the variables? (b) Make a two-way table displaying the results of the study. Include the totals. (c) What proportion of the breath samples did the dog get correct? What proportion of the stool samples did the dog get correct? (d) Of all the tests the \(\operatorname{dog}\) got correct, what proportion were stool tests?

Short Answer

Expert verified
The variables are the type of test (breath or stool), the health status of the patients (healthy or with cancer) and the outcome of the dog's test (correct or incorrect). The tables present the test results for breath and stool. The proportion of breath samples the dog got correct is \(33/36 = 0.92\) (approximately 92%), the proportion of stool samples the dog got correct is \(37/38 = 0.97\) (approximately 97%), and the proportion of all the tests the dogs got correct that were stool tests is \(37/(33+37) = 0.53\) (approximately 53%).

Step by step solution

01

Identifying the variables

In this study, the variables refer to the entities that can take different values. Here, the variables would be the type of test (breath or stool), the health status of the patients (healthy or with cancer), and the outcome of the dog's test (correct or incorrect).
02

Creating a two-way table

A two-way table would show the relationship between the variable of the dog's test (correct or incorrect) and the health status of the patients (healthy or with cancer) for both the types of tests (breath and stool). So, the rows of the table can be the outcome of the test (correct or incorrect), and the columns can be the patient type (healthy or with cancer):| | Cancer patient | Healthy volunteer | Total ||------------|---------------|-------------------|-------|| Correct | 33 | 3 | 36 || Incorrect | 3 | 1 | 4 || Total | 36 | 4 | 40 |Stool Test:| | Cancer patient | Healthy volunteer | Total ||------------|---------------|-------------------|-------|| Correct | 37 | 1 | 38 || Incorrect | 1 | 0 | 1 || Total | 38 | 1 | 39 |
03

Calculating proportions

For breath test, the proportion of samples the dog got correct will be the number of correct outcomes divided by the total number of samples, i.e., \(33/36\). Similarly, for stool test, it will be \(37/38\). To find out the proportion of all the tests the dogs got correct that were stool tests, divide the number of correct stool tests by the total number of correct tests: \(37/(33+37)\).
04

Interpreting results

Calculate the values obtained in Step 3 and interpret the results. The proportion of breath and stool samples the dog got correct give the success rate of the dog’s sniffing ability for each type of test. The proportion of all the tests the dogs got correct that were stool tests indicates what proportion of the dog's correct identifications were for stool tests.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Variables in Research Studies
Understanding the variables in a research study is crucial to grasping the framework of the research's investigation. In the context of biomedical research, variables are attributes or characteristics that can vary among subjects or across time. These can be quantitative, like age or blood pressure, or qualitative, like the presence or absence of a disease.

For example, in the study about dogs detecting cancer, the primary variables include the type of sample (breath or stool), the health status (whether the subject has cancer or not), and the outcome of the dog's test (correct identification or not). Each of these variables is integral to the research design and further analysis. Recognizing these variables helps researchers to systematically collect data, define the scope of the study, and analyze the results using statistical methods.
Two-Way Table
A two-way table is a powerful tool used for organizing data and summarizing the relationships between two categorical variables. The table helps in visualizing how different variables interact with each other, making it simpler to identify patterns and relationships.

In our case study, the two-way table displayed the dog's ability to correctly identify cancer samples against breath and stool tests. The rows labeled 'Correct' and 'Incorrect' represent the outcomes, while the columns are divided into 'Cancer patient' and 'Healthy volunteer', reflecting the health status of the subjects. By laying out the results in this manner, the two-way table made it easier to compare the dog's performance across different test types and to comprehend the success rate associated with each variable.
Proportion Calculation
Proportion calculation is a statistical method that expresses the part of a whole as a fraction or a percentage. It is often used to understand the prevalence or success rate in studies.

In the dog cancer detection study, calculating the proportion involves dividing the number of correct identifications by the total number of samples. Through this process, we can obtain the success rate of the dog’s ability to identify cancer. For example, if the dog correctly identified 33 out of 36 breath samples, the proportion of success for breath samples is calculated as \(\frac{33}{36}\). Similarly, the proportion for stool samples is obtained by \(\frac{37}{38}\). These calculations give us insight into the reliability and efficiency of cancer detection by the trained dog.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Examine issues of location and spread for boxplots. In each case, draw sideby- side boxplots of the datasets on the same scale. There are many possible answers. One dataset has median 50, interquartile range \(20,\) and range \(40 .\) A second dataset has median 50 , interquartile range 50 , and range 100 . A third dataset has median 50 , interquartile range 50 , and range 60 .

In Exercises 2.11 and 2.12, cases are classified according to one variable, with categories \(\mathrm{A}\) and \(\mathrm{B},\) and also classified according to a second variable with categories \(1,2,\) and 3 . The cases are shown, with the first digit indicating the value of the first variable and the second digit indicating the value of the second variable. (So "A1" represents a case in category \(\mathrm{A}\) for the first variable and category 1 for the second variable.) Construct a two-way table of the data. Twenty cases: \(\begin{array}{llllllllll}\mathrm{A} 1 & \mathrm{~A} 1 & \mathrm{~A} 1 & \mathrm{~A} 2 & \mathrm{~A} 3 & \mathrm{~A} 3 & \mathrm{~A} 3 & \mathrm{~A} 3 & \mathrm{~A} 3 & \mathrm{~A} 3 \\ \mathrm{~A} 3 & \mathrm{~A} 3 & \mathrm{~B} 1 & \mathrm{~B} 1 & \mathrm{~B} 1 & \mathrm{~B} 1 & \mathrm{~B} 2 & \mathrm{~B} 2 & \mathrm{~B} 2 & \mathrm{~B} 3\end{array}\)

Two variables are defined, a regression equation is given, and one data point is given. (a) Find the predicted value for the data point and compute the residual. (b) Interpret the slope in context. (c) Interpret the intercept in context, and if the intercept makes no sense in this context, explain why. Study \(=\) number of hours spent studying for an exam, Grade \(=\) grade on the exam \(\widehat{\text { Grade }}=41.0+3.8(\) Study \() ;\) data point is a student who studied 10 hours and received an 81 on the exam.

Apparently, sexual frustration increases the desire for alcohol, at least in fruit flies. Scientists \(^{33}\) randomly put 24 fruit flies into one of two situations. The 12 fruit flies in the "mating" group were allowed to mate freely with many available females eager to mate. The 12 in the "rejected" group were put with females that had already mated and thus rejected any courtship advances. After four days of either freely mating or constant rejection, the fruit flies spent three days with unlimited access to both normal fruit fly food and the same food soaked in alcohol. The percent of time each fly chose the alcoholic food was measured. The fruit flies that had freely mated chose the two types of food about equally often, choosing the alcohol variety on average \(47 \%\) of the time. The rejected males, however, showed a strong preference for the food soaked in alcohol, selecting it on average \(73 \%\) of the time. (The study was designed to study a chemical in the brain called neuropeptide that might play a role in addiction.) (a) Is this an experiment or an observational study? (b) What are the cases in this study? What are the variables? Which is the explanatory variable and which is the response variable? (c) We are interested in the difference in means, where the means measure the average percent preference for alcohol \((0.47\) and 0.73 in this case). Find the difference in means and give the correct notation for your answer, using the correct notation for a mean, subscripts to identify groups, and a minus sign. (d) Can we conclude that rejection increases a male fruit fly's desire for alcohol? Explain.

Near-Death Experiences People who have a brush with death occasionally report experiencing a near-death experience, which includes the sensation of seeing a bright light or feeling separated from one's body or sensing time speeding up or slowing down. Researchers \(^{14}\) interviewed 1595 people admitted to a hospital cardiac care unit during a recent 30 -month period. Patients were classified as cardiac arrest patients (in which the heart briefly stops after beating unusually quickly) or patients suffering other serious heart problems (such as heart attacks). The study found that 27 individuals reported having had a near-death experience, including 11 of the 116 cardiac arrest patients. Make a two-way table of these data. Compute the appropriate percentages to compare the rate of near-death experiences between the two groups. Describe the results.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.