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The article "Students Increasingly Turn to Credit Cards" (San Luis Obispo Tribune, July 21,2006\()\) reported that \(37 \%\) of college freshmen and \(48 \%\) of college seniors carry a credit card balance from month to month. Suppose that the reported percentages were based on random samples of 1000 college freshmen and 1000 college seniors. a. Construct a \(90 \%\) confidence interval for the proportion of college freshmen who carry a credit card balance from month to month. b. Construct a \(90 \%\) confidence interval for the proportion of college seniors who carry a credit card balance from month to month. c. Explain why the two \(90 \%\) confidence intervals from Parts (a) and (b) are not the same width.

Short Answer

Expert verified
The 90% confidence interval for the proportion of college freshmen carrying a credit card balance is approx. (0.357, 0.383) whereas for college seniors it's approx. (0.468, 0.492). The difference in widths is due to the different proportions of freshmen and seniors carrying a credit card balance.

Step by step solution

01

Calculate for Freshmen

First, we calculate the 90% confidence interval for the proportion of college freshmen carrying a credit card balance. \n We know, the confidence interval formula is: \( p \pm Z^*\sqrt{p(1-p)/n} \) \n Where: \n p is the sample proportion = 0.37\n n is the sample size = 1000\n Z* is Z score for 90% confidence level (one-tailed) = 1.645 \n Substituting the values in the formula, we get the confidence interval.
02

Calculate for Seniors

Next, we calculate the 90% confidence interval for the proportion of college seniors carrying a credit card balance. We use the same formula as in step 1. This time, p = 0.48 and n, the sample size remains the same, n = 1000. The Z score for 90% confidence level (one-tailed) remains 1.645 as well. Substituting the values in the formula gives us the confidence interval for seniors.
03

Compare The Confidence Intervals

Upon comparing the confidence intervals for freshmen and seniors, we notice that the widths of the intervals are not the same. This can be attributed to the different proportions (p) of freshmen and seniors carrying a credit card balance. When the proportion p and (1-p) are not the same as in our case, they yield different values when plugged in the formula \(\sqrt{p(1-p)/n}\), resulting in different widths of the confidence intervals.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
In statistics, the sample proportion is a way to estimate the part of a population that has a certain characteristic. It is the ratio of the number of times an event occurs in a sample to the total number of observations in the sample. In the context of our exercise, the sample proportion refers to the percentage of college students (freshmen and seniors) who carry a credit card balance. For freshmen, this is given as 37%, or 0.37 when expressed as a decimal. For seniors, it is 48%, or 0.48 in decimal form.

This measure is crucial because it serves as an estimate of the true proportion in the entire population, which is typically unknown. By using a sample proportion, we can derive other important statistical measures, such as confidence intervals, which help us understand the range in which we expect the true population proportion to lie.
College Students
College students, in this context, are divided into two categories: freshmen and seniors. These are two distinct groups within the college population who were surveyed regarding their credit card usage. Understanding the behavior of different groups allows researchers to identify patterns and differences in financial behavior over the course of a college career.

Freshmen are usually new to college life, possibly experiencing financial independence for the first time. Seniors, on the other hand, are more experienced and might handle credit differently due to their additional years of experience. These distinctions are important when performing statistical analyses, as they can influence the proportions and the confidence intervals derived from them.
Statistical Analysis
Statistical analysis is a method used to collect, review, and interpret data. It is fundamental in making sense of the collected information and forming conclusions. In the original exercise, statistical analysis is used to construct confidence intervals - a core concept in understanding how data from a sample can inform us about a population.

By analyzing the responses from 1000 freshmen and 1000 seniors, the statistical process helps construct confidence intervals that provide a range for the estimated proportions of these students carrying a credit card balance. This analysis involves understanding and applying formulas, ensuring that the resultant intervals are meaningful and accurately reflect the population from which the samples were drawn.
Z Score
The Z score is a statistical measure that describes a value's relation to the mean of a group of values. It is expressed in terms of standard deviations from the mean. In the context of confidence intervals, a Z score helps determine how many standard deviations above or below the mean the data point is.

For a 90% confidence interval, the Z score is approximately 1.645. This score tells us the range in which the population parameter is expected to lie, with a certain level of confidence. When constructing confidence intervals, the Z score is used to calculate the margin of error, which is then applied to the sample proportion to determine the interval's boundaries. Understanding how to use a Z score is essential in statistical analysis, especially in hypothesis testing and constructing confidence intervals.

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Most popular questions from this chapter

In a study of academic procrastination, the authors of the paper "Correlates and Consequences of Behavioral Procrastination" (Procrastination, Current Issues and New Directions [20001) reported that for a sample of 411 undergraduate students at a midsize public university preparing for a final exam in an introductory psychology course, the mean time spent studying for the exam was 7.74 hours and the standard deviation of study times was 3.40 hours. For purposes of this exercise, assume thar it is reasonable to regard this sample as represcntative of students taking introductory psychology at this university. a. Construct a \(95 \%\) confidence interval to estimate \(\mu\), the mean time spent studying for the final exam for students taking introductory psychology at this university. b. The paper also gave the following sample statistics for the percentage of study time that occurred in the 24 hours prior to the exam: \(n=411 \quad \bar{x}=43.18 \quad s=21.46\) Construct and interpret a \(90 \%\) confidence interval for the mean percentage of study time that occurs in the 24 hours prior to the exam.

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