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A study was carried out to investigate the relationship between the hardness of molded plastic \((y,\) in Brinell units) and the amount of time elapsed since termination of the molding process \((x,\) in hours \() .\) Summary quantities include \(n=15,\) SSResid \(=1235.470,\) and SSTo \(=25,321.368\). Calculate and interpret the coefficient of determination.

Short Answer

Expert verified
The coefficient of determination (\( R^2 \)) is 0.951.

Step by step solution

01

Identify Provided Variables

In this problem, we have been given \( n = 15 \), SSResid \( = 1235.470 \) and SSTo \( = 25321.368 \). These numbers will be used in the calculation of the coefficient of determination.
02

Implement the Coefficient of Determination Formula

Substitute the provided SSResid and SSTo values into the formula \( R^2 = 1 - (SSResid / SSTo) \). So, \( R^2 = 1 - (1235.470/25321.368) \)
03

Calculate \( R^2 \)

After substituting the variables into the formula, perform the division and subtraction to get the actual value of \( R^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

SSResid
The SSResid, or sum of squares due to error, plays an integral role in regression analysis. It is a measure used to quantify the variation in the observed data that is not explained by the regression model. In simple terms, it represents all the discrepancies or variances between the actual data points and the estimated values provided by the model.

To calculate SSResid, one would take each observed value and subtract the corresponding predicted value provided by the regression line, square these differences, and finally, sum them all. It’s crucial to understand that a lower SSResid indicates a model that closely aligns with the real data, which suggests a more accurate representation of the underlying relationship.
SSTo
SSTo stands for Total Sum of Squares, which is another statistical term utilized in regression analysis. It reflects the total variation in the observed data with respect to the mean. SSTo includes both the variation that the model explains (SSReg) and the variation that the model does not explain (SSResid).

You can think of SSTo as a measure of how scattered the data points are around their mean value. A higher SSTo indicates more dispersion and variability in the dataset. When combined with SSResid, SSTo helps in determining how well a regression model fits the data, leading us towards calculations like the coefficient of determination.
Regression Analysis
Regression analysis is a powerful statistical tool that establishes the relationship between a dependent variable and one or more independent variables. This method enables us to understand how the typical value of the dependent variable changes when any one of the independent variables is varied, while the other independent variables are held fixed.

Most commonly, regression analysis is used to predict the outcome of an event, understand which factors influence the event, and to evaluate different theories or models. In the context of the exercise, regression analysis would help in predicting the Brinell hardness given a certain amount of time elapsed since termination of the molding process.
Brinell Hardness Units
Brinell hardness units are used in the field of materials testing to quantify the hardness of materials, including plastics, metals, and other substances. This measurement is obtained by using the Brinell hardness test, in which a hard, spherical indenter is pressed into the surface of the material to be tested under a specific load for a definite time period.

The result is expressed as the Brinell hardness number (HB), which is the ratio of the applied force to the surface area of the indentation left on the material. In the exercise given, the Brinell hardness of molded plastic is being analyzed, which is a crucial indicator of its durability and suitability for various applications.

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Most popular questions from this chapter

Explain why the slope \(b\) of the least-squares line always has the same sign (positive or negative) as does the sample correlation coefficient \(r .\)

The sales manager of a large company selected a random sample of \(n=10\) salespeople and determined for each one the values of \(x=\) years of sales experience and \(y=\) annual sales (in thousands of dollars). A scatterplot of the resulting \((x, y)\) pairs showed a linear pattern. a. Suppose that the sample correlation coefficient is \(r=.75\) and that the average annual sales is \(\bar{y}=100 .\) If a particular salesperson is 2 standard deviations above the mean in terms of experience, what would you predict for that person's annual sales? b. If a particular person whose sales experience is 1\. 5 standard deviations below the average experience is predicted to have an annual sales value that is 1 standard deviation below the average annual sales, what is the value of \(r\) ?

The paper "Effects of Age and Gender on Physical Performance" (Age [2007]: 77-85) describes a study of the relationship between age and 1 -hour swimming performance. Data on age and swim distance for over 10,000 men participating in a national long-distance 1 -hour swimming competition are summarized in the accompanying table. In Exercise 5.34 from Section 5.3 , a plot of the residuals from the least-squares line showed a curved pattern that suggested that a quadratic curve would do a better job of summarizing the relationship between \(x=\) representative age and \(y=\) average swim distance. Find the equation of the least-squares quadratic curve and use it to predict average swim distance at 40 years of age. \(\hat{y}=3843.027+10.619 x-0.360 x^{2}\) \(\hat{y}=3691.293\)

An article on the cost of housing in California that appeared in the San Luis Obispo Tribune (March 30 . 2001 ) included the following statement: "In Northern California, people from the San Francisco Bay area pushed into the Central Valley, benefiting from home prices that dropped on average \(\$ 4000\) for every mile traveled east of the Bay area." If this statement is correct, what is the slope of the least-squares regression line, \(\hat{y}=a+b x,\) where \(y=\) house price (in dollars) and \(x=\) distance east of the Bay (in miles)? Explain.

With a bit of algebra, we can show that $$ \text { SSResid }=\left(1-r^{2}\right) \sum(y-\bar{y})^{2} $$ from which it follows that $$ s_{e}=\sqrt{\frac{n-1}{n-2}} \sqrt{1-r^{2}} s_{y} $$ Unless \(n\) is quite small, \((n-1) /(n-2) \approx 1,\) so $$ s_{e} \approx \sqrt{1-r^{2}} s_{y} $$ a. For what value of \(r\) is \(s_{e}\) as large as \(s_{y}\) ? What is the least- squares line in this case? \(r=0, \hat{y}=\bar{y}\) b. For what values of \(r\) will \(s_{e}\) be much smaller than \(s_{y}^{?}\) c. A study by the Berkeley Institute of Human Development (see the book Statistics by Freedman et al., listed in the back of the book) reported the following summary data for a sample of \(n=66\) California boys: \(r \approx .80\) At age 6 , average height \(\approx 46\) inches, standard deviation \(\approx 1.7\) inches. At age 18 , average height \(\approx 70\) inches, standard deviation \(\approx 2.5\) inches. What would \(s_{e}\) be for the least-squares line used to predict 18 -year-old height from G-year-old height? d. Referring to Part (c), suppose that you wanted to predict the past value of G-year-old height from knowledge of 18 -year-old height. Find the equation for the appropriate least-squares line. What is the corresponding value of \(s_{e} ? \hat{y}=7.92+.544 x, s_{c}=1.02\)

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