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The article "Performance Test Conducted for a Gas Air-Conditioning System" (American Society of Heating, Refrigerating. and Alr Conditioning Engineering [1969]: 54\()\) reported the following data on maximum outdoor temperature \((x)\) and hours of chiller operation per day \((y)\) for a 3 -ton residential gas air- conditioning system: \(\begin{array}{rrrrrrr}x & 72 & 78 & 80 & 86 & 88 & 92 \\ y & 4.8 & 7.2 & 9.5 & 14.5 & 15.7 & 17.9\end{array}\) Suppose that the system is actually a prototype model, and the manufacturer does not wish to produce this model unless the data strongly indicate that when maximum outdoor temperature is \(82^{\circ} \mathrm{F}\), the true average number of hours of chiller operation is less than 12 . The appropriate hypotheses are then \(H_{0}: \alpha+\beta(82)=12 \quad\) versus \(\quad H_{d}: \alpha+\beta(82)<12\) Use the statistic \(t=\frac{a+b(82)-12}{s_{a+b(82)}}\) which has a \(t\) distribution based on \((n-2)\) df when \(H_{0}\) is true, to test the hypotheses at significance level .01 .

Short Answer

Expert verified
The decision to reject or fail to reject the null hypothesis depends on the comparison between the calculated \( t \) value and the critical value from \( t \) distribution table.

Step by step solution

01

Calculate the parameters of the regression equation

The first step is to calculate the parameters \( \alpha \) and \( \beta \) of the regression equation \( y = \alpha + \beta x \). This can be achieved using the given pairs of \( x \) and \( y \) values. To find \( \alpha \) and \( \beta \), the following formulas can be used: \( \beta = \frac{n(\sum{x_i * y_i}) - \sum{x_i}*\sum{y_i}}{n(\sum{x_i^2}) - (\sum{x_i})^2} \) and \( \alpha = \frac{\sum{y_i} - \beta*\sum{x_i}}{n} \), where \( n \) is the number of pairs, \( x_i \) and \( y_i \) are the given \( x \) and \( y \) data points respectively.
02

Compute the test statistic \( t \)

Using the values of \( \alpha \) and \( \beta \) obtained in the previous step, evaluate the statistic \( t = \frac{a+b(82)-12}{s_{a+b(82)}} \). Here, \( s_{a+b(82)} \) is the standard error of estimate, which can be calculated using the formula: \( s_{a+b(82)}^2 = s^2*(\frac{1}{n} + \frac{(82-\bar{x})^2}{\sum{(x_i - \bar{x})^2}}) \) where \( s^2 = \frac{1}{n-2}\sum{(y-\alpha-\beta*x)^2} \), \( \bar{x} = \frac{1}{n}\sum{x_i} \) and \( x_i \) is each value of \( x \).
03

Determine the critical value for \( t \) distribution

For a significance level of .01 and \( n-2 \) degrees of freedom, find the critical value from the \( t \) distribution table.
04

Make a decision

Compare the calculated \( t \) value with the critical value. If the calculated \( t \) value is less than the critical value, then we reject the null hypothesis and conclude that the true average number of hours of chiller operation is less than 12 when the maximum outdoor temperature is \(82^{\circ} \mathrm{F}\). Otherwise we fail to reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Regression Analysis
Regression analysis is a statistical tool used to understand the relationship between variables. In the context of the given exercise, regression analysis helps us to explore how maximum outdoor temperature ('x') influences the hours of chiller operation per day ('y') for an air-conditioning system.

Using a set of paired observations, we can estimate the parameters of the regression line, which is the equation that represents this relationship. By applying the formulas:
  • For the slope: \(\beta = \frac{n(\sum{x_i \cdot y_i}) - \sum{x_i} \cdot \sum{y_i}}{n(\sum{x_i^2}) - (\sum{x_i})^2}\)
  • For the intercept: \(\alpha = \frac{\sum{y_i} - \beta \cdot \sum{x_i}}{n}\)
We calculate the best fit line that minimizes the differences (errors) between the observed 'y' values and the corresponding 'y' values estimated by our regression line. Once we have \(\alpha\) and \(\beta\), we can predict the hours of chiller operation for any given temperature, which is helpful for testing hypotheses about the air-conditioning system's performance.

Understanding regression analysis is crucial for interpreting the relationship between variables and making informed decisions based on data.
T-Distribution
The t-distribution, often used in hypothesis testing, is a probability distribution resembling a normal distribution but with thicker tails. It is particularly useful when dealing with small sample sizes, like in our exercise where we have only six data pairs.

To conduct a hypothesis test, we compare a test statistic to a value drawn from the t-distribution. This test statistic, represented as 't', encapsulates whether the observed data deviate significantly from what the null hypothesis predicts. In the exercise, we calculated 't' using the formula:
\[t = \frac{a + b(82) - 12}{s_{a + b(82)}}\]
Where 'a' and 'b' are the estimated regression parameters and \(s_{a+b(82)}\) is the standard error of the estimate at an outdoor temperature of \(82\degree F\). This standard error adjusts for the variability in the regression, thereby standardizing our test statistic.

Understanding the t-distribution allows us to interpret the significance of our t-statistic, and thus, the credibility of our results within the context of the given sample data.
Statistical Significance
Statistical significance is used to determine whether the result of an experiment is not likely due to chance. In terms of hypothesis testing, it helps us decide if we should reject the null hypothesis. In our scenario, we are questioning if the true average number of hours the chiller operates is actually less than 12 given a temperature of \(82^\circ F\).

The level of significance, denoted by \(\alpha\), is commonly set at 0.05, 0.01, or 0.001, based on how strict the tester wants to be. We've used a significance level of 0.01, suggesting we are looking for evidence that is strong enough to have less than a 1% chance of being wrong if we reject the null hypothesis.

By finding the critical value from the t-distribution table and comparing it to our calculated t-statistic, we conclude if the data provides sufficient evidence to show that the average chiller operation hours are significantly less than 12 at the given temperature. This level of proof is crucial for credible and reliable conclusions in scientific and business decision-making processes.

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Most popular questions from this chapter

Exercise 13.21 gave data on \(x=\) nerve firing frequency and \(y=\) pleasantness rating when nerves were stimulated by a light brushing stoke on the forearm. The \(x\) values and the corresponding residuals from a simple linear regression are as follows: a. Construct a standardized residual plot. Does the plot exhibit any unusual features? b. A normal probability plot of the standardized residuals follows. Based on this plot, do you think it is reasonable to assume that the error distribution is approximately normal? Explain.

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