/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 The paper "If It's Hard to Read,... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The paper "If It's Hard to Read, It's Hard to Do" (Psychological Science [2008]\(: 986-988)\) described an interesting study of how people perceive the effort required to do certain tasks. Each of 20 students was randomly assigned to one of two groups. One group was given instructions for an exercise routine that were printed in an easy-to-read font (Arial). The other group received the same set of instructions, but printed in a font that is considered difficult to read (Brush). After reading the instructions, subjects estimated the time (in minutes) they thought it would take to complete the exercise routine. Summary statistics are given below. $$ \begin{array}{ccc} & \text { Easy font } & \text { Difficult font } \\ \hline n & 10 & 10 \\ \bar{x} & 8.23 & 15.10 \\ s & 5.61 & 9.28 \\ \hline \end{array} $$ The authors of the paper used these data to carry out a two-sample \(t\) test, and concluded that at the .10 significance level, there was convincing evidence that the mean estimated time to complete the exercise routine was less when the instructions were printed in an easy-to-read font than when printed in a difficult-to-read font. Discuss the appropriateness of using a two-sample \(t\) test in this situation.

Short Answer

Expert verified
The application of the two-sample t test in this exercise routine case could be inappropriate due to potential violation of its assumptions of normality and equality of variances, as there's not sufficient data to confirm these conditions are met.

Step by step solution

01

Understanding a two-sample t test

A two-sample t test is a hypothesis test that compares the means of two populations. The test is used to determine whether there is significant evidence that the means are different. The primary assumptions for this test are: Independence of observations within and between groups, approximately normally distributed responses within each group, and equal variances of the two populations. The first assumption seems to be met since individuals were randomly assigned to the two groups.
02

Checking assumptions

For the second assumption, normal distribution of response within each group, we don't have enough information. The standard deviations are provided but we can't make an inference about normality without a plot of the data or statistical measures of skewness and kurtosis. The third assumption regarding equal variances is also hard to determine with certainty given only summary statistics. Though from the provided data, the standard deviation of the difficult font group is higher than that of the easy font group.
03

Conclusion

Therefore, despite a t test being possibly the correct statistical approach for comparing means of two independent samples, in this case, it might not be entirely appropriate due to potential violation of the assumptions of equal variances and normality. Without additional information, it's difficult to judge if it is permissible to use a two-sample t test in this situation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
The concept of normal distribution is a central pillar in statistics, especially in hypothesis testing. A normal distribution is a symmetric, bell-shaped curve that characterizes the spread of a set of data. It is vital because much of statistical theory is based on this model.

In the context of a two-sample t test, the assumption is that the data from each group being compared are normally distributed. This means that within each group, if you were to plot the data, it should resemble a bell-shaped curve. However, it's important to note that without concrete data—like a histogram or numerical tests like the Shapiro-Wilk test—verifying normality based simply on summary statistics can be tricky.
- Normal distribution allows us to make probabilistic statements about data - Many tests, including the t test, assume normality for reliability
The study mentioned in the exercise assumes normal distribution for both easy and difficult font groups' responses. Without specific evidence of normality from the data, caution should be exercised when interpreting results.
Independent Samples
Independent samples mean that the performance or outcome of one group does not affect or relate to the other group. In experiments, ensuring independence is crucial to maintaining the validity of the conclusions.

The study in question used random assignment to assign students to either the easy font group or the difficult font group. This randomization process is intended to ensure that the groups are independent of each other.
- Independence supports the validity of comparative statistical tests - Random assignment is a common technique to achieve independence
For the two-sample t test, the assumption of independent samples is key. If randomization was properly followed, then this assumption is likely met. However, external factors or biases not controlled for could potentially violate independence.
Equal Variance Assumption
The equal variance assumption states that the variance in outcomes should be the same or similar across the groups being compared. Variance is a measure of how data points differ from the mean.

In a two-sample t test, if the variances are not equal (known as heteroscedasticity), the test results may not be valid. The exercise provides standard deviations of 5.61 for the easy font group and 9.28 for the difficult font group. This suggests potentially different variances.
- Equal variances ensure reliability in the comparison of means - Standard deviations offer a clue but not proof of equal variances
To check for this, a test such as Levene's test for equality of variances could be used. In the absence of such tests, one must be cautious in interpreting t test results if variances seem disparate from summary data alone.
Hypothesis Testing
Hypothesis testing is a procedural method used in statistics to test a claim or theory about a population parameter. It involves comparing an experimental group to a control group to determine statistical significance.

In the context of the exercise, a two-sample t test was used to test the hypothesis whether the average estimated time to complete a task was different for groups receiving easy-to-read and difficult-to-read instructions. The hypotheses set were:
  • Null Hypothesis ( H_0 ): Mean times are equal.
  • Alternative Hypothesis ( H_a ): Mean time for the easy font is less than for the difficult font.
- The t test evaluates if observed data deviate from the null hypothesis to a degree that is statistically significant - A significance level of 0.10 implies a 10% risk of concluding a difference exists when it doesn't
If the p-value obtained from the test is less than the significance level, the null hypothesis can be rejected in favor of the alternative. But given the importance of the other assumptions, such as normal distribution and equal variance, the conclusions drawn from such a test must be carefully considered.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A researcher at the Medical College of Virginia conducted a study of 60 randomly selected male soccer players and concluded that frequently "heading" the ball in soccer lowers players' IQs (USA Today, August 14 1995). The soccer players were divided into two groups, based on whether they averaged 10 or more headers per game. Mean IQs were reported in the article, but the sample sizes and standard deviations were not given. Suppose that these values were as given in the accompanying table. $$ \begin{array}{l|ccc} & & \text { Sample } & \text { Sample } \\ & n & \text { Mean } & \text { sd } \\ \hline \text { Fewer Than 1O Headers } & 35 & 112 & 10 \\ 10 \text { or More Headers } & 25 & 103 & 8 \\ \hline \end{array} $$ Do these data support the researcher's conclusion? Test the relevant hypotheses using \(\alpha=.05 .\) Can you conclude that heading the ball causes lower \(\mathrm{IQ}\) ?

Two different underground pipe coatings for preventing corrosion are to be compared. The effect of a coating (as measured by maximum depth of corrosion penetration on a piece of pipe) may vary with depth, orientation, soil type, pipe composition, etc. Describe how an experiment that filters out the effects of these extraneous factors could be carried out.

Two proposed computer mouse designs were compared by recording wrist extension in degrees for 24 people who each used both mouse types ("Comparative Study of Two Computer Mouse Designs," Cornell Human Factors Laboratory Technical Report RP7992). The difference in wrist extension was computed by subtracting extension for mouse type \(\mathrm{B}\) from the wrist extension for mouse type A for each student. The mean difference was reported to be 8.82 degrees. Assume that it is reasonable to regard this sample of 24 people as representative of the population of computer users. a. Suppose that the standard deviation of the differences was 10 degrees. Is there convincing evidence that the mean wrist extension for mouse type \(A\) is greater than for mouse type B? Use a .05 significance level. b. Suppose that the standard deviation of the differences was 26 degrees. Is there convincing evidence that the mean wrist extension for mouse type \(A\) is greater than for mouse type B? Use a .05 significance level. c. Briefly explain why a different conclusion was reached in the hypothesis tests of Parts (a) and (b).

"Mountain Biking May Reduce Fertility in Men, Study Says" was the headline of an article appearing in the San Luis Obispo Tribune (December 3,2002 ). This conclusion was based on an Austrian study that compared sperm counts of avid mountain bikers (those who ride at least 12 hours per week) and nonbikers. Ninety percent of the avid mountain bikers studied had low sperm counts, as compared to \(26 \%\) of the nonbikers. Suppose that these percentages were based on independent samples of 100 avid mountain bikers and 100 non-bikers and that it is reasonable to view these samples as representative of Austrian avid mountain bikers and nonbikers. a. Do these data provide convincing evidence that the proportion of Austrian avid mountain bikers with low sperm count is higher than the proportion of Austrian nonbikers? b. Based on the outcome of the test in Part (a), is it reasonable to conclude that mountain biking 12 hours per week or more causes low sperm count? Explain.

The paper "Ready or Not? Criteria for Marriage Readiness among Emerging Adults" (Journal of \(\underline{\text { Ado- }}\) lescent Research [2009]: 349-375) surveyed emerging adults (defined as age 18 to 25 ) from five different colleges in the United States. Several questions on the survey were used to construct a scale designed to measure endorsement of cohabitation. The paper states that "on average, emerging adult men \((\mathrm{M}=3.75, \mathrm{SD}=1.21)\) reported higher levels of cohabitation endorsement than emerging adult women \((\mathrm{M}=3.39, \mathrm{SD}=1.17) . "\) The sample sizes were 481 for women and 307 for men. a. Carry out a hypothesis test to determine if the reported difference in sample means provides convincing evidence that the mean cohabitation endorsement for emerging adult women is significantly less than the mean for emerging adult men for students at these five colleges. b. What additional information would you want in order to determine whether it is reasonable to generalize the conclusion of the hypothesis test from Part (a) to all college students?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.